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Often a radical change in the form of the solution of a differential equation corresponds to a very small change in either the initial condition or the equation itself. In Problems 39‒42 find an explicit solution of the given initial-value problem. Use a graphing utility to plot the graph of each solution. Compare each solution curve in a neighborhood of (0, 1).
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- In Problems 27 – 36 solve the given initial-value problemarrow_forwardIn Problems 43–46, solve each equation on the interval 0 ≤ θ < 2π43. sin(2θ) + sin (4θ) = 0 44. cos(2θ) + cos(4θ) = 0 45. cos(4θ)) - cos(6θ) = 0 46. sin(4θ) - sin(6θ) = 0arrow_forwardIn Problems 1 through 6, express the solution of the given ini- tial value problem as a sum of two oscillations as in Eq. (8). Throughout, primes denote derivatives with respect to time t. In Problems 1–4, graph the solution function x(t) in such a way that you can identify and label (as in Fig. 3.6.2) its pe- riod. 3. x" + 100x = 225 cos 5t + 300 sin 5t; x(0) = 375, x'(0) = 0arrow_forward
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- In Problems 1 through 6, express the solution of the given ini- tial value problem as a sum of two oscillations as in Eq. (8). Throughout, primes denote derivatives with respect to time t. In Problems 1–4, graph the solution function x(t) in such a way that you can identify and label (as in Fig. 3.6.2) its pe- riod. 2. x" + 4x = 5 sin 31; x(0) = x'(0) = 0arrow_forwardIn Problems 47–58, use a calculator to solve each equation on the interval 0 … u 6 2p. Round answers to two decimal places. 47. sin θ = 0.4 48. cos θ = 0.6 49. tan θ = 5 50. cot θ = 2 51. cos θ = - 0.9 52. sin θ = - 0.2 53. sec θ = - 4 54. csc θ = - 3 55. 5 tan θ + 9 = 0 56. 4 cot θ = - 5 57. 3 sin θ - 2 = 0 58. 4 cos θ + 3 = 0arrow_forwardIII. Solutions of Differential Equations. Verify the followingarrow_forward
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