In Example 22–6, it may seem that the electric field calculated is due only to the charge on the wire that is enclosed by the cylinder chosen as our gaussian surface. In fact, the entire charge along the whole length of the wire contributes to the field. Explain how the charge outside the cylindrical gaussian surface of Fig. 22–15 contributes to E at the gaussian surface. [ Hint: Compare to what the field would be due to a short wire.]
In Example 22–6, it may seem that the electric field calculated is due only to the charge on the wire that is enclosed by the cylinder chosen as our gaussian surface. In fact, the entire charge along the whole length of the wire contributes to the field. Explain how the charge outside the cylindrical gaussian surface of Fig. 22–15 contributes to E at the gaussian surface. [ Hint: Compare to what the field would be due to a short wire.]
In Example 22–6, it may seem that the electric field calculated is due only to the charge on the wire that is enclosed by the cylinder chosen as our gaussian surface. In fact, the entire charge along the whole length of the wire contributes to the field. Explain how the charge outside the cylindrical gaussian surface of Fig. 22–15 contributes to E at the gaussian surface. [Hint: Compare to what the field would be due to a short wire.]
A semicircle ofradius a is in the first and secondquadrants, with the center of curvatureat the origin. Positive charge+Q is distributed uniformly aroundthe left half of the semicircle, andnegative charge -Q is distributeduniformly around the right half ofthe semicircle (Fig. ). Whatare the magnitude and direction of the net electric field at the originproduced by this distribution of charge?
A large non-conducting slab of area A and thickness d has a charge density rho=Cx^4. The origin is through the center of the slab. That is to say, it bisects the slab into two equal volumes of d/2 thickness and with an area of A, with -d/2 to the left of x=0, and d/2 to the right of x=0. Express all answers in terms of C, x, and any known constants.
Gaussian surface 1 (cylinder) is located such that its volume encompasses the charge contained within the slab. Apply Gauss's Law to cylinder 1 to determine the electric field to the left and to the right of the slab. Make sure you incude the domains over which the field is valid.
A “semi-infinite” non-conducting rod (that is, infinite in one direction only) has uniform linear chargedensity(lambda). Show that the electric field at point P makes an angle of 45⁰ with the rod and that this result isindependent of the distance R.
To do this, separately find the parallel and perpendicular (to the rod) components of the electric fieldat P, and show that these components are equal
Chapter 22 Solutions
Physics For Scientists & Engineers, Vols. 1 & 2, And Masteringphysics With E-book Student Access Kit (4th Edition)
Sears And Zemansky's University Physics With Modern Physics
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.