Given code: public static void mA(int n) { for ( int i = 0 ; i < n ; i ++) { System.out.println(Math. random()); } }

Question

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Answer 1

Question

Chapter 22.3, Problem 22.3.3CP

a)

Program Plan Intro

Given code:

public static void mA(int n)

{

for ( int i = 0 ; i < n ; i ++) {

System.out.println(Math. random());

}

}

b)

Program Plan Intro

Given code:

public static void mB (int n)

{

for ( int i = 0 ; i < n ; i ++ )

{

for ( int j = 0; j < i ; j ++)

System.out.print(Math. random());

}

}

c)

Program Plan Intro

Given code:

public static void mC(int[ ] m)

{

for (int i = 0; i < m.length; i++)

{

System .out.print(m [i]);

}

for (int i=m.length-1;i>=0;)

{

System.out.print(m[i]);

i--;

}

}

d)

Program Plan Intro

Given code:

public static void mD (int[ ] m)

{

for (int i= 0; i < m.length; i++)

{

for ( int j = 0 ; j < i ; j ++)

System.out. print( m[ i ] * m[ j ]);

}

}

Expert Solution & Answer

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Check out a sample textbook solution

See solution

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A porous membrane having a width of 1cm, contains A at a concentration of 0.5 kmol/m³. One side of the membrane is suddenly exposed to gas and concentration of A at this side is increased to 2 kmol/m³. Calculate the concentration values by finite differences method using computer programing and below data. Calculate the time it takes for the concentration of A to be 2 kmol/m3 everywhere in the membrane. Ox=0.0025m (5 space) Ot=0.01s DAB=2.5*10-4 m²/s

in python sample output is provided

Answer 2

Question

Chapter 22.3, Problem 22.3.3CP

a)

Program Plan Intro

Given code:

public static void mA(int n)

{

for ( int i = 0 ; i < n ; i ++) {

System.out.println(Math. random());

}

}

b)

Program Plan Intro

Given code:

public static void mB (int n)

{

for ( int i = 0 ; i < n ; i ++ )

{

for ( int j = 0; j < i ; j ++)

System.out.print(Math. random());

}

}

c)

Program Plan Intro

Given code:

public static void mC(int[ ] m)

{

for (int i = 0; i < m.length; i++)

{

System .out.print(m [i]);

}

for (int i=m.length-1;i>=0;)

{

System.out.print(m[i]);

i--;

}

}

d)

Program Plan Intro

Given code:

public static void mD (int[ ] m)

{

for (int i= 0; i < m.length; i++)

{

for ( int j = 0 ; j < i ; j ++)

System.out. print( m[ i ] * m[ j ]);

}

}

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 22.3, Problem 22.3.3CP

a)

Program Plan Intro

Given code:

public static void mA(int n)

{

for ( int i = 0 ; i < n ; i ++) {

System.out.println(Math. random());

}

}

b)

Program Plan Intro

Given code:

public static void mB (int n)

{

for ( int i = 0 ; i < n ; i ++ )

{

for ( int j = 0; j < i ; j ++)

System.out.print(Math. random());

}

}

c)

Program Plan Intro

Given code:

public static void mC(int[ ] m)

{

for (int i = 0; i < m.length; i++)

{

System .out.print(m [i]);

}

for (int i=m.length-1;i>=0;)

{

System.out.print(m[i]);

i--;

}

}

d)

Program Plan Intro

Given code:

public static void mD (int[ ] m)

{

for (int i= 0; i < m.length; i++)

{

for ( int j = 0 ; j < i ; j ++)

System.out. print( m[ i ] * m[ j ]);

}

}

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 22.3, Problem 22.3.3CP

a)

Program Plan Intro

Given code:

public static void mA(int n)

{

for ( int i = 0 ; i < n ; i ++) {

System.out.println(Math. random());

}

}

b)

Program Plan Intro

Given code:

public static void mB (int n)

{

for ( int i = 0 ; i < n ; i ++ )

{

for ( int j = 0; j < i ; j ++)

System.out.print(Math. random());

}

}

c)

Program Plan Intro

Given code:

public static void mC(int[ ] m)

{

for (int i = 0; i < m.length; i++)

{

System .out.print(m [i]);

}

for (int i=m.length-1;i>=0;)

{

System.out.print(m[i]);

i--;

}

}

d)

Program Plan Intro

Given code:

public static void mD (int[ ] m)

{

for (int i= 0; i < m.length; i++)

{

for ( int j = 0 ; j < i ; j ++)

System.out. print( m[ i ] * m[ j ]);

}

}

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 22.3, Problem 22.3.3CP

a)

Program Plan Intro

Given code:

public static void mA(int n)

{

for ( int i = 0 ; i < n ; i ++) {

System.out.println(Math. random());

}

}

b)

Program Plan Intro

Given code:

public static void mB (int n)

{

for ( int i = 0 ; i < n ; i ++ )

{

for ( int j = 0; j < i ; j ++)

System.out.print(Math. random());

}

}

c)

Program Plan Intro

Given code:

public static void mC(int[ ] m)

{

for (int i = 0; i < m.length; i++)

{

System .out.print(m [i]);

}

for (int i=m.length-1;i>=0;)

{

System.out.print(m[i]);

i--;

}

}

d)

Program Plan Intro

Given code:

public static void mD (int[ ] m)

{

for (int i= 0; i < m.length; i++)

{

for ( int j = 0 ; j < i ; j ++)

System.out. print( m[ i ] * m[ j ]);

}

}

Answer 6

Chapter 22.3, Problem 22.3.3CP

a)

Program Plan Intro

Given code:

public static void mA(int n)

{

for ( int i = 0 ; i < n ; i ++) {

System.out.println(Math. random());

}

}

Answer 7

Chapter 22.3, Problem 22.3.3CP

a)

Program Plan Intro

Given code:

public static void mA(int n)

{

for ( int i = 0 ; i < n ; i ++) {

System.out.println(Math. random());

}

}

Answer 8

b)

Program Plan Intro

Given code:

public static void mB (int n)

{

for ( int i = 0 ; i < n ; i ++ )

{

for ( int j = 0; j < i ; j ++)

System.out.print(Math. random());

}

}

Answer 9

b)

Program Plan Intro

Given code:

public static void mB (int n)

{

for ( int i = 0 ; i < n ; i ++ )

{

for ( int j = 0; j < i ; j ++)

System.out.print(Math. random());

}

}

Answer 10

c)

Program Plan Intro

Given code:

public static void mC(int[ ] m)

{

for (int i = 0; i < m.length; i++)

{

System .out.print(m [i]);

}

for (int i=m.length-1;i>=0;)

{

System.out.print(m[i]);

i--;

}

}

Answer 11

c)

Program Plan Intro

Given code:

public static void mC(int[ ] m)

{

for (int i = 0; i < m.length; i++)

{

System .out.print(m [i]);

}

for (int i=m.length-1;i>=0;)

{

System.out.print(m[i]);

i--;

}

}

Answer 12

d)

Program Plan Intro

Given code:

public static void mD (int[ ] m)

{

for (int i= 0; i < m.length; i++)

{

for ( int j = 0 ; j < i ; j ++)

System.out. print( m[ i ] * m[ j ]);

}

}

Answer 13

d)

Program Plan Intro

Given code:

public static void mD (int[ ] m)

{

for (int i= 0; i < m.length; i++)

{

for ( int j = 0 ; j < i ; j ++)

System.out. print( m[ i ] * m[ j ]);

}

}

Answer 14

Expert Solution & Answer

Answer 15

Expert Solution & Answer

Answer 16

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Check out a sample textbook solution

See solution

Answer 17

Ch. 22.2 - Prob. 22.2.1CP Ch. 22.2 - What is the order of each of the following...Ch. 22.3 - Count the number of iterations in the following...Ch. 22.3 - How many stars are displayed in the following code...Ch. 22.3 - Prob. 22.3.3CP Ch. 22.3 - Prob. 22.3.4CP Ch. 22.3 - Example 7 in Section 22.3 assumes n = 2k. Revise...Ch. 22.4 - Prob. 22.4.1CP Ch. 22.4 - Prob. 22.4.2CP Ch. 22.4 - Prob. 22.4.3CP

Given code: public static void mA(int n) { for ( int i = 0 ; i &lt; n ; i ++) { System.out.println(Math. random()); } }

Given code: public static void mA(int n) { for ( int i = 0 ; i < n ; i ++) { System.out.println(Math. random()); } }

Given code: public static void mB (int n) { for ( int i = 0 ; i < n ; i ++ ) { for ( int j = 0; j < i ; j ++) System.out.print(Math. random()); } }

Given code: public static void mC(int[ ] m) { for (int i = 0; i < m.length; i++) { System .out.print(m [i]); } for (int i=m.length-1;i>=0;) { System.out.print(m[i]); i--; } }

Given code: public static void mD (int[ ] m) { for (int i= 0; i < m.length; i++) { for ( int j = 0 ; j < i ; j ++) System.out. print( m[ i ] * m[ j ]); } }

Want to see the full answer?

Chapter 22 Solutions

Given code: public static void mA(int n) { for ( int i = 0 ; i < n ; i ++) { System.out.println(Math. random()); } }

Given code:

public static void mA(int n)

{

for ( int i = 0 ; i < n ; i ++) {

System.out.println(Math. random());

}

}

Given code:

public static void mB (int n)

{

for ( int i = 0 ; i < n ; i ++ )

{

for ( int j = 0; j < i ; j ++)

System.out.print(Math. random());

}

}

Given code:

public static void mC(int[ ] m)

{

for (int i = 0; i < m.length; i++)

{

System .out.print(m [i]);

}

for (int i=m.length-1;i>=0;)

{

System.out.print(m[i]);

i--;

}

}

Given code:

public static void mD (int[ ] m)

{

for (int i= 0; i < m.length; i++)

{

for ( int j = 0 ; j < i ; j ++)

System.out. print( m[ i ] * m[ j ]);

}

}