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In Exercises 11–14, solve the systems of equations by substitution.
12.
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Chapter 2 Solutions
College Algebra in Context, Books a la Carte Edition plus MyLab Math with Pearson eText -- Access Card Package (5th Edition)
- Exercises 149–151 will help you prepare for the material covered in the next section. 149. Multiply: (Vx + 4 + 1)2. 150. Solve: 4x2 16x + 16 = 4(x + 4). 151. Solve: 26 – 11x 16 – 8x + x?.arrow_forwardFor Exercises 81–100, make an appropriate substitution and solve the equation. (See Examples 10–11) 81. (2x + 5)? – 7(2x + 5) - 30 = 0 82. (Зх — 7)? - 6(3х — 7)-16 3D 0 83. (x + 2x)? – 18(r + 2x) = -45 84. (x + 3x)? - 86. (у? — 3)? — 9(y? — 3) — 52 %3D 0 14(x + 3x) = -40 85. (x + 2)2 + (x + 2) – 42 = 0 10 2 10 - 61 m - - 27 = 0 x + + 35 = 0 87. 88. - 121 x + т - m m 89. 2 + 2 + = 12 90. + 3 + 6 + 3 = -8 91. 5c2/5 11c/5 + 2 = 0 92. З3 d'/3 – 4 = 0 93. y'/2 – y/4 6 = 0 94. n'/2 + 6n/4 – 16 = 0 95. 9y 10y + 1 = 0 96. 100х-4 29x-2 + 1 = 0 | 97. 4t – 25 Vi = 0 98. 9m – 16Vm = 0 100. 392 + 16q -1 99. 30k-2 – 23k- + 2 = 0 + 5 = 0arrow_forwardFor Exercises 5–10, a. Simplify the expression. b. Substitute 0 for h in the simplified expression. 2(x + h)? + 3(x + h) · 5. (2x + 3x) 3(x + h - 4(x + h) – (3x - 4x) 6. h 1 1 1 1 (x + h) – 2 7. x - 2 2(x + h) + 5 8. 2x + 5 h (x + h) – x 9. (x + h) 10. - X h harrow_forward
- Solve the equations * 2x – y + 3z = -3, 3.x + 3y – z = 10, -x – y + z = -4 O x = 2, y = 1, z = -4 Ox = 4, y = 2, z = -4 O x = 1, y = 2, z = -4 O x = 1, y = 2, z = -1arrow_forwardState reducible Second-Order Equations?arrow_forwardSolve the system of linear equations. 8) x + y - 2 x - y = 14 A) Ø B) ((8. -6)} C) {(-8, -5)} D) {(7. -5))arrow_forward
- Exercises 143–145 will help you prepare for the material covered in the next section. y2 - yı 143. If (x1, yı) = (-3, 1) and (x2, y2) = (-2, 4), find X2 - X1 144. Find the ordered pairs (- 0) and (0, 4х — Зу - 6 % 0. satisfying 145. Solve for y: 3x + 2y – 4 = 0.arrow_forwardExercises 86–88 will help you prepare for the material covered in the next section. If –9 is substituted for x in the equation 4x – 3 = 5x + 6, is the resulting statement true or false? Simplify: 13 – 3(x + 2). Зх + Simplify: 10(**1).arrow_forwardExercises 59–66: Use the intersection-of-graphs method to solve the equation. Then solve symbolically. 63. -х + 4 %3D 3хarrow_forward
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