(a) Interpretation: Balanced chemical reaction for the Sc(l) is produced by the electrolysis of Sc 2 O 3 dissolved inNa 3 ScF 6 (1) should be written. Concept introduction: Oxidation number of Sc in Sc 2 O 3 = +3 Oxidation number of Sc inNa 3 ScF 6 = +3

Question

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Answer 1

Question

Chapter 23, Problem 14E

Interpretation Introduction

(a)

Interpretation:

Balanced chemical reaction for the Sc(l) is produced by the electrolysis of Sc₂O₃dissolved inNa₃ScF₆(1) should be written.

Concept introduction:

Oxidation number of Sc in Sc₂O₃ = +3

Oxidation number of Sc inNa₃ScF₆ = +3

Interpretation Introduction

(b)

Interpretation:

Balanced chemical reaction for Cr(s) reacts with HCl(aq) to produce a blue solution containing Cr²⁺ should be written.

Concept introduction:

Cr(s) is in its lowest oxidation state of zero. In order to go for higher oxidation state of +2; it should be oxidized.

Interpretation Introduction

(c)

Interpretation:

Balanced chemical reaction for Cr²⁺(aq) is readily oxidized by O₂(g) Cr³⁺(aq) should be written.

Concept introduction:

When Cr²⁺ oxidized into Cr³⁺; O₂ gas act as the oxidizing agent.

Interpretation Introduction

(d)

Interpretation:

Reaction for Ag(s) reacts with concentrated HNO₃ and NO₂(g)is evolved; the balanced chemical should be written.

Concept introduction:

Concentrated nitric acid can oxidize Ag(s) to Ag⁺.

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Answer 2

Question

Chapter 23, Problem 14E

Interpretation Introduction

(a)

Interpretation:

Balanced chemical reaction for the Sc(l) is produced by the electrolysis of Sc₂O₃dissolved inNa₃ScF₆(1) should be written.

Concept introduction:

Oxidation number of Sc in Sc₂O₃ = +3

Oxidation number of Sc inNa₃ScF₆ = +3

Interpretation Introduction

(b)

Interpretation:

Balanced chemical reaction for Cr(s) reacts with HCl(aq) to produce a blue solution containing Cr²⁺ should be written.

Concept introduction:

Cr(s) is in its lowest oxidation state of zero. In order to go for higher oxidation state of +2; it should be oxidized.

Interpretation Introduction

(c)

Interpretation:

Balanced chemical reaction for Cr²⁺(aq) is readily oxidized by O₂(g) Cr³⁺(aq) should be written.

Concept introduction:

When Cr²⁺ oxidized into Cr³⁺; O₂ gas act as the oxidizing agent.

Interpretation Introduction

(d)

Interpretation:

Reaction for Ag(s) reacts with concentrated HNO₃ and NO₂(g)is evolved; the balanced chemical should be written.

Concept introduction:

Concentrated nitric acid can oxidize Ag(s) to Ag⁺.

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Answer 3

Question

Chapter 23, Problem 14E

Interpretation Introduction

(a)

Interpretation:

Balanced chemical reaction for the Sc(l) is produced by the electrolysis of Sc₂O₃dissolved inNa₃ScF₆(1) should be written.

Concept introduction:

Oxidation number of Sc in Sc₂O₃ = +3

Oxidation number of Sc inNa₃ScF₆ = +3

Interpretation Introduction

(b)

Interpretation:

Balanced chemical reaction for Cr(s) reacts with HCl(aq) to produce a blue solution containing Cr²⁺ should be written.

Concept introduction:

Cr(s) is in its lowest oxidation state of zero. In order to go for higher oxidation state of +2; it should be oxidized.

Interpretation Introduction

(c)

Interpretation:

Balanced chemical reaction for Cr²⁺(aq) is readily oxidized by O₂(g) Cr³⁺(aq) should be written.

Concept introduction:

When Cr²⁺ oxidized into Cr³⁺; O₂ gas act as the oxidizing agent.

Interpretation Introduction

(d)

Interpretation:

Reaction for Ag(s) reacts with concentrated HNO₃ and NO₂(g)is evolved; the balanced chemical should be written.

Concept introduction:

Concentrated nitric acid can oxidize Ag(s) to Ag⁺.

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Answer 4

Question

Chapter 23, Problem 14E

Interpretation Introduction

(a)

Interpretation:

Balanced chemical reaction for the Sc(l) is produced by the electrolysis of Sc₂O₃dissolved inNa₃ScF₆(1) should be written.

Concept introduction:

Oxidation number of Sc in Sc₂O₃ = +3

Oxidation number of Sc inNa₃ScF₆ = +3

Interpretation Introduction

(b)

Interpretation:

Balanced chemical reaction for Cr(s) reacts with HCl(aq) to produce a blue solution containing Cr²⁺ should be written.

Concept introduction:

Cr(s) is in its lowest oxidation state of zero. In order to go for higher oxidation state of +2; it should be oxidized.

Interpretation Introduction

(c)

Interpretation:

Balanced chemical reaction for Cr²⁺(aq) is readily oxidized by O₂(g) Cr³⁺(aq) should be written.

Concept introduction:

When Cr²⁺ oxidized into Cr³⁺; O₂ gas act as the oxidizing agent.

Interpretation Introduction

(d)

Interpretation:

Reaction for Ag(s) reacts with concentrated HNO₃ and NO₂(g)is evolved; the balanced chemical should be written.

Concept introduction:

Concentrated nitric acid can oxidize Ag(s) to Ag⁺.

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Answer 5

Chapter 23, Problem 14E

Interpretation Introduction

(a)

Interpretation:

Balanced chemical reaction for the Sc(l) is produced by the electrolysis of Sc₂O₃dissolved inNa₃ScF₆(1) should be written.

Concept introduction:

Oxidation number of Sc in Sc₂O₃ = +3

Oxidation number of Sc inNa₃ScF₆ = +3

Interpretation Introduction

(b)

Interpretation:

Balanced chemical reaction for Cr(s) reacts with HCl(aq) to produce a blue solution containing Cr²⁺ should be written.

Concept introduction:

Cr(s) is in its lowest oxidation state of zero. In order to go for higher oxidation state of +2; it should be oxidized.

Interpretation Introduction

(c)

Interpretation:

Balanced chemical reaction for Cr²⁺(aq) is readily oxidized by O₂(g) Cr³⁺(aq) should be written.

Concept introduction:

When Cr²⁺ oxidized into Cr³⁺; O₂ gas act as the oxidizing agent.

Interpretation Introduction

(d)

Interpretation:

Reaction for Ag(s) reacts with concentrated HNO₃ and NO₂(g)is evolved; the balanced chemical should be written.

Concept introduction:

Concentrated nitric acid can oxidize Ag(s) to Ag⁺.

Answer 6

Chapter 23, Problem 14E

Interpretation Introduction

(a)

Interpretation:

Balanced chemical reaction for the Sc(l) is produced by the electrolysis of Sc₂O₃dissolved inNa₃ScF₆(1) should be written.

Concept introduction:

Oxidation number of Sc in Sc₂O₃ = +3

Oxidation number of Sc inNa₃ScF₆ = +3

Answer 7

Chapter 23, Problem 14E

Interpretation Introduction

(a)

Interpretation:

Balanced chemical reaction for the Sc(l) is produced by the electrolysis of Sc₂O₃dissolved inNa₃ScF₆(1) should be written.

Concept introduction:

Oxidation number of Sc in Sc₂O₃ = +3

Oxidation number of Sc inNa₃ScF₆ = +3

Answer 8

Interpretation Introduction

(b)

Interpretation:

Balanced chemical reaction for Cr(s) reacts with HCl(aq) to produce a blue solution containing Cr²⁺ should be written.

Concept introduction:

Cr(s) is in its lowest oxidation state of zero. In order to go for higher oxidation state of +2; it should be oxidized.

Answer 9

Interpretation Introduction

(b)

Interpretation:

Balanced chemical reaction for Cr(s) reacts with HCl(aq) to produce a blue solution containing Cr²⁺ should be written.

Concept introduction:

Cr(s) is in its lowest oxidation state of zero. In order to go for higher oxidation state of +2; it should be oxidized.

Answer 10

Interpretation Introduction

(c)

Interpretation:

Balanced chemical reaction for Cr²⁺(aq) is readily oxidized by O₂(g) Cr³⁺(aq) should be written.

Concept introduction:

When Cr²⁺ oxidized into Cr³⁺; O₂ gas act as the oxidizing agent.

Answer 11

Interpretation Introduction

(c)

Interpretation:

Balanced chemical reaction for Cr²⁺(aq) is readily oxidized by O₂(g) Cr³⁺(aq) should be written.

Concept introduction:

When Cr²⁺ oxidized into Cr³⁺; O₂ gas act as the oxidizing agent.

Answer 12

Interpretation Introduction

(d)

Interpretation:

Reaction for Ag(s) reacts with concentrated HNO₃ and NO₂(g)is evolved; the balanced chemical should be written.

Concept introduction:

Concentrated nitric acid can oxidize Ag(s) to Ag⁺.

Answer 13

Interpretation Introduction

(d)

Interpretation:

Reaction for Ag(s) reacts with concentrated HNO₃ and NO₂(g)is evolved; the balanced chemical should be written.

Concept introduction:

Concentrated nitric acid can oxidize Ag(s) to Ag⁺.

Answer 14

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Answer 15

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Answer 16

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Answer 17

Ch. 23 - By means of orbital diagrams, write electron...Ch. 23 - Arrange the following species according to the...Ch. 23 - Describe how the transition elements compare with...Ch. 23 - With only minor irregularities, the melting points...Ch. 23 - Why do the atomic radii vary so much for two...Ch. 23 - Prob. 6E Ch. 23 - Which of me first transition series elements...Ch. 23 - Why is the number of common oxidation states for...Ch. 23 - As a group, the lanthanides are more reactive...Ch. 23 - The maximum difference in standard reduction...

(a) Interpretation: Balanced chemical reaction for the Sc(l) is produced by the electrolysis of Sc 2 O 3 dissolved inNa 3 ScF 6 (1) should be written. Concept introduction: Oxidation number of Sc in Sc 2 O 3 = +3 Oxidation number of Sc inNa 3 ScF 6 = +3

Solution Summary: The author explains that the balanced chemical reaction for Sc(l) is produced by the electrolysis of Sc 2 O 3 dissolved inNa 3 ScF 6.

(a)

Interpretation:

Balanced chemical reaction for the Sc(l) is produced by the electrolysis of Sc₂O₃dissolved inNa₃ScF₆(1) should be written.

Concept introduction:

Oxidation number of Sc in Sc₂O₃ = +3

Oxidation number of Sc inNa₃ScF₆ = +3

(b)

Interpretation:

Balanced chemical reaction for Cr(s) reacts with HCl(aq) to produce a blue solution containing Cr²⁺ should be written.

Concept introduction:

Cr(s) is in its lowest oxidation state of zero. In order to go for higher oxidation state of +2; it should be oxidized.

(c)

Interpretation:

Balanced chemical reaction for Cr²⁺(aq) is readily oxidized by O₂(g) Cr³⁺(aq) should be written.

Concept introduction:

When Cr²⁺ oxidized into Cr³⁺; O₂ gas act as the oxidizing agent.

(d)

Interpretation:

Reaction for Ag(s) reacts with concentrated HNO₃ and NO₂(g)is evolved; the balanced chemical should be written.

Concept introduction:

Concentrated nitric acid can oxidize Ag(s) to Ag⁺.

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Chapter 23 Solutions

(a) Interpretation: Balanced chemical reaction for the Sc(l) is produced by the electrolysis of Sc 2 O 3 dissolved inNa 3 ScF 6 (1) should be written. Concept introduction: Oxidation number of Sc in Sc 2 O 3 = +3 Oxidation number of Sc inNa 3 ScF 6 = +3

Solution Summary: The author explains that the balanced chemical reaction for Sc(l) is produced by the electrolysis of Sc 2 O 3 dissolved inNa 3 ScF 6.