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Concept explainers
Velocity A ball is thrown straight down from the top of a 210-foot building with an initial velocity of - 18 feet per second.
(a) Find the position and velocity functions for the ball.
(b) Find the average velocity over the interval
(c) Find the instantaneous velocities when
(d) How long will it take the ball to hit the ground?
(e) Find the velocity of the ball when it hits the ground.
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Chapter 2 Solutions
WebAssign Printed Access Card for Larson's Calculus: An Applied Approach, 10th Edition, Single-Term
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- If a ball is thrown in the air with a velocity 48 ft/s, its height in feet t seconds later is given by y = 48t - 16t2. (a) Find the average velocity for the time period beginning when t = 2 and lasting (i) 0.5 second. ft/s (ii) 0.1 second. ft/s (iii) 0.05 second. ft/s (iv) 0.01 second. ft/s (b) Estimate the instantaneous velocity when t = 2. ft/sarrow_forwardThe displacement (in meters) of a particle moving in a straight line is given by S = t² − 4t + 13, where t is measured in seconds. (A) (i) Find the average velocity over the time interval [3,4]. Average Velocity meters per = -> (ii) Find the average velocity over the time interval [3.5,4]. Average Velocity = meters per second. = - (iii) Find the average velocity over the time interval [4,5]. Average Velocity meters per second. → (iv) Find the average velocity over the time interval [4,4.5]. Average Velocity = meters per second. (B) Find the instantaneous velocity when t = 4. Instantaneous velocity = = ← second. meters per second.arrow_forwardA rock is dropped from the edge of a cliff that is 214 metersabove water. (a) Determine the position and velocity functions for therock. (b) Determine the average velocity on the interval [2, 5]. (c) Find the instantaneous velocities when t = 2 and t = 5. (d) Find the time required for the rock to reach the surface ofthe water. (e) Find the velocity of the rock at impact. ***Using only Constant, power, constant multiple, sum & difference, & rate of change rules (sec. 2.2 rules only) please. No chain rule. Please explain work, thank you!arrow_forward
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