Chem 103 : Catalyst - With Access (Custom)
16th Edition
ISBN: 9781323251836
Author: UNIV.OF AK SE
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Textbook Question
Chapter 2.3, Problem 2.21QAP
Round off each of the following calculator answers to three significant
figures:
a. 1.854 kg
b. 88.2038 L
c. 0.004 738 265 cm
d. 8807m
e.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
Record the Celsius temperature according to the thermometer shown below.
78.39 o C
78.4 o C
78.3 o C
78.30 o C
A balloon has a volume of 2.6 liters at 24.0°C. The balloon is heated to 48.0°C. Calculate the new volume of the balloon (in Liters).
A substance is in the form of a 4.5 cm long cylinder with a diameter of 2.1 cm and a mass of 3.7 g. What is the density of the substance. Report your answer with three decimal places.
Chapter 2 Solutions
Chem 103 : Catalyst - With Access (Custom)
Ch. 2.1 - Prob. 2.1QAPCh. 2.1 - Prob. 2.2QAPCh. 2.1 - Prob. 2.3QAPCh. 2.1 - Prob. 2.4QAPCh. 2.1 - Write the abbreviation for each of the following:...Ch. 2.1 - Write the abbreviation for each of the following:...Ch. 2.2 - Prob. 2.7QAPCh. 2.2 - Prob. 2.8QAPCh. 2.2 - Prob. 2.9QAPCh. 2.2 - Prob. 2.10QAP
Ch. 2.2 - 2.13 Indicate if the zeros are significant in each...Ch. 2.2 - 2.14 Indicate if the zeros are significant in each...Ch. 2.2 - 2.9 How many significant figures are in each of...Ch. 2.2 - How many significant figures are in each of the...Ch. 2.2 - 2.11 In which of the following pairs do both...Ch. 2.2 - 2.12 In which of the following pairs do both...Ch. 2.2 - 2.15 Write each of the following in scientific...Ch. 2.2 - 2.16 Write each of the following in scientific...Ch. 2.3 - Prob. 2.19QAPCh. 2.3 - Prob. 2.20QAPCh. 2.3 - Round off each of the following calculator answers...Ch. 2.3 - Prob. 2.22QAPCh. 2.3 - Prob. 2.23QAPCh. 2.3 - Prob. 2.24QAPCh. 2.3 - Prob. 2.25QAPCh. 2.3 - Prob. 2.26QAPCh. 2.3 - Prob. 2.27QAPCh. 2.3 - Prob. 2.28QAPCh. 2.4 - Prob. 2.29QAPCh. 2.4 - Prob. 2.30QAPCh. 2.4 - 2.31 Write the abbreviation for each of the...Ch. 2.4 - Write the abbreviation for each of the following...Ch. 2.4 - Prob. 2.33QAPCh. 2.4 - Prob. 2.34QAPCh. 2.4 - Write the numerical value for each of the...Ch. 2.4 - Prob. 2.36QAPCh. 2.4 - Prob. 2.37QAPCh. 2.4 - Use a prefix to write the name for each of the...Ch. 2.4 - Complete each of the following metric...Ch. 2.4 - Prob. 2.40QAPCh. 2.4 - Prob. 2.41QAPCh. 2.4 - Prob. 2.42QAPCh. 2.5 - Why can two conversion factors be written for an...Ch. 2.5 - Prob. 2.44QAPCh. 2.5 - Prob. 2.45QAPCh. 2.5 - Prob. 2.46QAPCh. 2.5 - Write the equality and two conversion factors, and...Ch. 2.5 - Write the equality and two conversion factors, and...Ch. 2.6 - Prob. 2.49QAPCh. 2.6 - Prob. 2.50QAPCh. 2.6 - Prob. 2.51QAPCh. 2.6 - Prob. 2.52QAPCh. 2.6 - Prob. 2.53QAPCh. 2.6 - Prob. 2.54QAPCh. 2.6 - Prob. 2.55QAPCh. 2.6 - Prob. 2.56QAPCh. 2.7 - Prob. 2.57QAPCh. 2.7 - Prob. 2.58QAPCh. 2.7 - Prob. 2.59QAPCh. 2.7 - Prob. 2.60QAPCh. 2.7 - Prob. 2.61QAPCh. 2.7 - Prob. 2.62QAPCh. 2 - In which of the fo1losing pairs do both numbers...Ch. 2 - In which of the following pairs do both numbers...Ch. 2 - Indicate if each of the following is answered with...Ch. 2 - Prob. 2.66UTCCh. 2 - Prob. 2.67UTCCh. 2 - Prob. 2.68UTCCh. 2 - Prob. 2.69UTCCh. 2 - Prob. 2.70UTCCh. 2 - Prob. 2.71AQAPCh. 2 - Prob. 2.72AQAPCh. 2 - Prob. 2.73AQAPCh. 2 - Prob. 2.74AQAPCh. 2 - Prob. 2.75AQAPCh. 2 - Prob. 2.76AQAPCh. 2 - Prob. 2.77AQAPCh. 2 - Prob. 2.78AQAPCh. 2 - Prob. 2.79AQAPCh. 2 - Prob. 2.80AQAPCh. 2 - Prob. 2.81AQAPCh. 2 - Prob. 2.82AQAPCh. 2 - Prob. 2.83AQAPCh. 2 - Prob. 2.84AQAPCh. 2 - Prob. 2.85AQAPCh. 2 - Prob. 2.86AQAPCh. 2 - Prob. 2.87AQAPCh. 2 - Prob. 2.88AQAPCh. 2 - Prob. 2.89CQCh. 2 - Prob. 2.90CQCh. 2 -
2.117 A car travels at 55 mi/h and gets 11 km/L...Ch. 2 - Prob. 2.92CQCh. 2 - Prob. 2.93CQCh. 2 - A sunscreen preparation contains 2.50% benzyl...Ch. 2 - Prob. 2.95CQCh. 2 - Prob. 2.96CQCh. 2 - Prob. 2.97CQCh. 2 - Prob. 2.98CQCh. 2 - Prob. 2.99CQCh. 2 - Prob. 2.100CQ
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- the answer is between 28ml and 29ml divided the space between those markings and estimate one more digit. Its not 28.5arrow_forwardShow all computations and express final answer in sig fig and scientific notation. Box out final answer. Convert1) 3.25 X10^5 ft/ s^2 to m / hour^2arrow_forwardsubtract 3.58 x 10^-2 from 1.41 x 10^11 and report answer in g.arrow_forward
- To what decimal place should each answer be rounded? How many significant figures does the rounded answer have? 101 cm−99.1 cm=1.9 cm (unrounded) After rounding, the answer should be reported to the and thus has . 0.5 atm+9.8 atm=10.3 atm (unrounded) After rounding, the answer should be reported to the and thus has .arrow_forwardTwo students measured the freezing point of a sample of pure benzene. Student A used an ordinary laboratory thermometer calibrated in 0.1 ℃ units. Student B used a thermometer certified by NIST (National Institute of Standards and Technology) and calibrated in 0.01 °C units. Their results were as follows: Student A: 52 °C, 5.7 °C, 5.5 °C, 5.2 °C Student B: 5.48 °C, 5.52 °C, 5.50 °C, 5.54 °C Calculate the average value for A and B and, knowing the freezing point of benzene is 5.50 °C (and using kelvins for temperature), calculate the percent error for each student. Which student has the smaller error?arrow_forwardEstimate one more place. Reading will be to the nearest 0.1 mL. 52.8 +/-0.1 mL estimated to be between 52.7 and 52.9 mL How many significant digits does this measurement have? 3 sig figs (2 certain and one uncertain or estimated)arrow_forward
- Answer using the metric system conversions. Show work and correct significant figures 01.00cm= m 8.00mm=cm 10.0nm= ?m 3.22Gg=kg 455nm=?m 3.001cg=mgarrow_forwardConvert the temperature as indicated and report with 2 significant figures. Convert 255 degrees F to Karrow_forwardCharlotte is driving at 66.4mi/h and receives a text message. She looks at her phone and takes her eyes off the road for 4.30 seconds. How far has Charlotte reached in feet during this time?arrow_forward
- 17) Perform the following calculations. Show answer in scientific notation. round the coefficient to the correct number of sig figs.select best answer (8.9x109)/ (3x106)=a)2.97x103 b) 2.96x103 C) 3x103 d) 3x1015 e) 2966.67arrow_forwardAttempt 2 Charlotte is driving at 56.9 mi/h56.9 mi/h and receives a text message. She looks down at her phone and takes her eyes off the road for 3.86 s.3.86 s. How far has Charlotte traveled in feet during this time?arrow_forwardUse the data set to answer the question. Correct Value: 59.2 Trial 1 Trial 2 Trial 3 Trial 4 Trial 5 58.7 59.3 60.0 58.9 59.2 Which best describes the data set? O It is accurate but not precise. OIt is precise but not accurate. O It is both accurate and precise. O It is neither accurate nor precise.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Introductory Chemistry: A FoundationChemistryISBN:9781337399425Author:Steven S. Zumdahl, Donald J. DeCostePublisher:Cengage Learning
Chemistry: Matter and ChangeChemistryISBN:9780078746376Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl WistromPublisher:Glencoe/McGraw-Hill School Pub Co
Chemistry & Chemical ReactivityChemistryISBN:9781133949640Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning
Introductory Chemistry: A Foundation
Chemistry
ISBN:9781337399425
Author:Steven S. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Chemistry: Matter and Change
Chemistry
ISBN:9780078746376
Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Publisher:Glencoe/McGraw-Hill School Pub Co
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
Precipitation Reactions: Crash Course Chemistry #9; Author: Crash Course;https://www.youtube.com/watch?v=IIu16dy3ThI;License: Standard YouTube License, CC-BY