A uniformly charged disk of radius 35.0 cm carries charge with a density of 7.90 × 10 -3 C/m 2 . Calculate the electric field on the axis of the disk at (a) 5.00 cm, (b) 10.0 cm, (c) 50.0 cm, and (d) 200 cm from the center of the disk.
A uniformly charged disk of radius 35.0 cm carries charge with a density of 7.90 × 10 -3 C/m 2 . Calculate the electric field on the axis of the disk at (a) 5.00 cm, (b) 10.0 cm, (c) 50.0 cm, and (d) 200 cm from the center of the disk.
A uniformly charged disk of radius 35.0 cm carries charge with a density of 7.90 × 10-3 C/m2. Calculate the electric field on the axis of the disk at (a) 5.00 cm, (b) 10.0 cm, (c) 50.0 cm, and (d) 200 cm from the center of the disk.
(a)
Expert Solution
To determine
The electric field on the axis of the disk at
5.00cm.
Answer to Problem 23.38P
The electric field on the axis of the disk at
5.00cm. is
382.92×106N/C.
Explanation of Solution
Given info: The radius of the disk is
35.0cm, the charge density on the disk is
7.90×10−3C/m2 and the distance at which electric field has to be find is
5.00cm.
Formula to calculate the magnetic field at a distance from the centre of the disk,
E=2πkeσ[1−x(x2+R2)12]
Here,
ke is the constant.
σ is the charge density.
x is the distant of the point from the centre of the disk.
R is the radius of the disk.
Substitute
8.99×109N⋅m2/C2 for
ke,
7.90×10−3C/m2 for
σ,
35.0cm for
R and
5.00cm for
x in above equation.
Therefore, the electric field on the axis of the disk at
5.00cm. is
382.92×106N/C.
(b)
Expert Solution
To determine
The electric field on the axis of the disk at
10.0cm.
Answer to Problem 23.38P
The electric field on the axis of the disk at
10.0cm. is
323.84×106N/C.
Explanation of Solution
Given info: The radius of the disk is
35.0cm, the charge density on the disk is
7.90×10−3C/m2 and the distance at which electric field has to be find is
10.0cm.
Formula to calculate the magnetic field at a distance from the centre of the disk,
E=2πkeσ[1−x(x2+R2)12]
Here,
ke is the constant.
σ is the charge density.
x is the distant of the point from the centre of the disk.
R is the radius of the disk.
Substitute
8.99×109N⋅m2/C2 for
ke,
7.90×10−3C/m2 for
σ,
35.0cm for
R and
10.0cm for
x in above equation.
Therefore, the electric field on the axis of the disk at
10.0cm. is
323.84×106N/C.
(c)
Expert Solution
To determine
The electric field on the axis of the disk at
50.0cm.
Answer to Problem 23.38P
The electric field on the axis of the disk at
50.0cm is
80.7×106N/C.
Explanation of Solution
Given info: The radius of the disk is
35.0cm, the charge density on the disk is
7.90×10−3C/m2 and the distance at which electric field has to be find is
50.0cm.
Formula to calculate the magnetic field at a distance from the centre of the disk,
E=2πkeσ[1−x(x2+R2)12]
Here,
ke is the constant.
σ is the charge density.
x is the distant of the point from the centre of the disk.
R is the radius of the disk.
Substitute
8.99×109N⋅m2/C2 for
ke,
7.90×10−3C/m2 for
σ,
35.0cm for
R and
50.0cm for
x in above equation.
Therefore, the electric field on the axis of the disk at
50.0cm is
80.7×106N/C.
(d)
Expert Solution
To determine
The electric field on the axis of the disk at
200cm.
Answer to Problem 23.38P
The electric field on the axis of the disk at
200cm is
6.68×106N/C.
Explanation of Solution
Given info: The radius of the disk is
35.0cm, the charge density on the disk is
7.90×10−3C/m2 and the distance at which electric field has to be find is
200cm.
Formula to calculate the magnetic field at a distance from the centre of the disk,
E=2πkeσ[1−x(x2+R2)12]
Here,
ke is the constant.
σ is the charge density.
x is the distant of the point from the centre of the disk.
R is the radius of the disk.
Substitute
8.99×109N⋅m2/C2 for
ke,
7.90×10−3C/m2 for
σ,
35.0cm for
R and
200cm for
x in above equation.
Charge is uniformly distributed around a ring of radius R = 2.40 cm, and the resulting electric field magnitude E is measured along the ring’s central axis (perpendicular to the plane of the ring). At what distance from the ring’s center is E maximum?
A non-conducting sphere of radius R = 7.0 cm carries a charge Q = 4.0 mC distributed uniformly throughout its volume. At what distance, measured from the center of the sphere, does the electric field reach a value equal to half its maximum value?
An unknown charge sits on a conducting solid sphere of radius 13 cm. If the electric field 21 cm from the center of the sphere has magnitude 3.5 × 103 N/C and is directed radially inward, what is the net charge on the sphere?
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.