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Look again at the x-t graph in Fig. 2.9 at the end of Section 2.2. (a) At which of the points P, Q, R, and S is the x-acceleration ax positive? (b) At which points is the x-acceleration negative? (c) At which points does the x-acceleration appear to be zero? (d) At each point state whether the velocity is increasing, decreasing, or not changing.
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University Physics with Modern Physics, Volume 1 (Chs. 1-20) (14th Edition)
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- Then, substituting the time, results to the following hmax = ( )+ (1/2)ay( Substituting ay = -g, results to hmax = ( )- (1/2)g( simplifying the expression, yields hmax = x sin b) The distance traveled by a projectile follows a uniform motion, meaning, velocity is constant from the start point until it reach the ground along the horizontal axis, so, the range R can be expressed as R= Vinitial-xt Substituting the initial velocity on the x-axis results to the following R = ( )t But, the time it takes a projectile to travel this distance is just twice of tmax-height, by substitution, we obtain the following: R = x 2 x ( Re-arranging and then applying the trigonometric identity sin(2x) = 2sin(x)cos(x) we arrive at the expression for the range R as R = sinarrow_forwardThis is one-dimensional. This part uses pure numbers, dispensing with units. If a ball's acceleration is -4, and its initial velocity is 7, derive v(t) -- velocity as a function of time. Now use parameters a and v0, and derive v(t).arrow_forward4.3**5. A car traveling 30 m/s due east turns a smooth corner and heads northeast. The car maintained a constant speed throughout the 10 seconds it took to make the turn. What was the average acceleration for the 10 seconds? (Give the answer in component form for eastward and northward components.)arrow_forward
- A particle's velocity is given by vlt) = -atj, where a = 0.725 m/s? is a constant. (a) Describe the particle's motion. In particular, is it speeding up, slowing down, or maintaining constant speed? speeding up slowing down O maintaining constant speed (b) Find the particle's velocity at t- 0, t= 17.5 s, and t- 6.40 min. (Express your answer in vector form.) vy-0 at t-0 m/s at t- 17.5 S m/s at t-6.40 min -278.4 m/sarrow_forwardAsaparrow_forwardA car accelerates with a constant acceleration of 1.5 m s2 along a long straight road. How long does it take the car to accelerate from 100 kph to 110 kph, and how far does it travel while doing so? [Hint: watch your units and sig figs! Because there is no other information, take the speeds as three significant figures] It takes seconds to accelerate to 110 kph. While accelerating, the car travels m. Separate your answers with a comma. Example: a, barrow_forward
- acceleration ++++ time (a) (b) (c) Fig. 3.10 Graphs describing a body moving with constant positive acceleration: (a) acceleration versus time, (b) velocity versus time, and (c) position versus time speed (m/s) What Have I Learned So Far? Consider the given graph of speed versus time shown here. Then find the values of the following: 1 1. The acceleration from 0 s to 2 s 2. The acceleration from 2 s to 3 s 3. The acceleration from 5 s to 7 s 4. The distance traveled by the body from the 2nd to the 3rd second 5. The distance traveled by the body from the 5th to the 7th second 2 0 -1 veloci -2 momen time 1 2 3 posi bado 30.20 onit 4 time, (s) 5 time 6 Or [16] Menin qui grovdi 7 Moleto obsaheb Mied (20 od s volano tesi vor to szli nie The Physics of Point Particlesarrow_forwardHi, I need help with this physcis problem. I've gone over it multiple times and can't firgure it out. Anyway you can help? A car, initially at rest, accelerates at a constant rate of 2 m/s2 due east (choose east as the positive direction; round your answer to the nearest meter per second; include units)What is its velocity after 1 second? What is its velocity after 2 seconds? What is its velocity after 3 seconds? What is its velocity after 4 seconds? What is its velocity after 5 seconds? What is its velocity after 9 seconds? If instead a car accelerates at a constant rate of 5 m/s2 due eastWhat is its velocity after 1 second? What is its velocity after 2 seconds? What is its velocity after 3 seconds? If instead a car accelerates at a constant rate of 5 m/s2 due westWhat is its velocity after 1 second?arrow_forwardAn ant is crawling along a straight wire, which we shall call the x axis, from A to B to C to D (which overlaps A), as shown in the figure below. (Figure 1) O is the origin. Suppose you take measurements and find that AB is 44 cm, BC is 20 cm ,and AO is 4 cm. Find the displacement of the ant after it has moved over the interval from A to B. Express your answer in centimeters. 15| ΑΣΦ ?arrow_forward
- Consider a dragster that, when the light turns green, accelerates uniformly from rest and completes a 372 meter race in a time of 6.61 seconds. a) During this period, what is the dragster's acceleration expressed as a multiple of the acceleration due to gravity, g? b) If the dragster could continue with this average acceleration, what would its speed be, in miles per hour, after it has traveled a total distance of 1.6km1.6km, which is approximately one mile?arrow_forwardIn this lab, we are going to use a cart, a ramp (an inclined smooth apparatus), and a timing system to study how to determine the instantaneous speed when the cart moves down the ramp at a series of pre-determined position along the ramp. We will also use the definition of the acceleration to determine the average acceleration between chose two position along the ramp. The timer is actually recording the time for the wing on this cart to go through the photogate. When the downside of the wing enters the center of the photogate, the timer starts to time. When the upside of the wing leaves the center of the photogate, the timer stops the timing. Thus, we can calculate the instantaneous speed of the cart passes the position where the photogate is located. We will then move down the photogate and calculate the other instantaneous speed along the ramp at the given location. The instantaneous speed will be V=0.05tV=0.05t. 0,05 meter is the length of the wing of the cart. t is the time you…arrow_forwardA particle travels according to the velocity function v(t) = 4t - 2 m/sec. What is the total distance traveled by the particle over the time interval 0, 6|? Enter your answer as an exact fraction if necessary and do not include units in your answer. Provide your answer below:arrow_forward
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