Physics for Scientists and Engineers
6th Edition
ISBN: 9781429281843
Author: Tipler
Publisher: MAC HIGHER
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Chapter 23, Problem 6P
To determine
The sketch of an electric field lines and equipotential surface for the system of charges.
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Throughout a region, equipotential surfaces are given by z = constant . The surfaces are equally spaced with V = 100 V for z = 0.00 m, V = 200 V forz = 0.50 m, V = 300 V for z = 1.00 m. What is the electric field in this region?
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Chapter 23 Solutions
Physics for Scientists and Engineers
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- Two very large metal plates are placed 2.0 cm apart, with a potential difference of 12 V between them. Consider one plate to be at 12 V, and the other at 0 V. (a) Sketch the equipotential surfaces for 0, 4, 8, and 12 V. (b) Next sketch in some electric field lines, and confirm that they are perpendicular to the equipotential lines.arrow_forwardWhat is the maximum charge that can be stored on the 8.00-cm2 plates of an air-filled parallel-plate capacitor beforebreakdown occurs? The dielectric strength of air is 3.00 MV/m.arrow_forwardFind an expression for the electric field between the two conducting disks in Figure P27.61. Make sure your expression is general enough to include the possibility of a dielectric between the disks. Check your answer using the information given in Section 27-8. Figure P27.61arrow_forward
- An equipotential surface must be perpendicular to the electric field at certain points. TRUE or FALSE?arrow_forwardTwo conducting spherical shells have radii a= 2 cm (inner), and b= 5 cm (external). The interior is a perfect dielectric for which ɛR = 10. The value of capacitance between the two plates equals toarrow_forwardA uniform insulating sphere of radius a with charge Q1 = 0.8 nCis concentric with a = 11.0 cm conducting spherical shell ofinner radius b = 20.0 cm, outer radius c = 30.0 cm andcharge Q2 = 2.0 nC as shown in the figure.If the center of the sphere is chosen as the origin of thecoordinate system, find the potential differenceV (x = a/2 , y = 0 , z = 0) − V (x = 0 , y = (b + c)/2 , z = 0)in units of Volts.Take 14πε0= 9.0 × 109 Nm2/C2.arrow_forward
- Let's consider a point with an electric charge q=1.5 microC'. Potential value of V=50VFind the radius of the equipotential surface? A) 270m B) 27m C) 53m D) 120m E) 40marrow_forwardIn Figure (a), a particle of charge +e is initially at coordinate z = 20 nm on the dipole axis through an electric dipole, on the positive side of the dipole. (The origin of z is at the dipole center.) The particle is then moved along a circular path around the dipole center until it is at coordinate z = -20 nm. Figure (b) gives the work Wa done by the force moving the particle versus the angle θ that locates the particle. The scale of the vertical axis is set by Was = 4.0 × 10-30 J. What is the magnitude of the dipole moment? The answer was not 1.112*10^-36.arrow_forwardIn Figure (a), a particle of charge +e is initially at coordinate z = 20 nm on the dipole axis through an electric dipole, on the positive side of the dipole. (The origin of z is at the dipole center.) The particle is then moved along a circular path around the dipole center until it is at coordinate z = -20 nm. Figure (b) gives the work Wa done by the force moving the particle versus the angle θ that locates the particle. The scale of the vertical axis is set by Was = 4.0 × 10-30 J. What is the magnitude of the dipole moment?arrow_forward
- A negatively-charged particle with a magnitude of 13.42 nC is accelerating in a 127.32-N/C uniform electric field. The particle has departed from an equipotential plane of 25 V and is found to have displaced to a plane of 15 V after some time. Calculate the distance covered by the particle.arrow_forwardAn electron is held at point c. In what direction will it move when released? If it starts from rest, how fast will it be moving when it crosses the equipotential line that point b sits at? (You may need to look up a constant or two.) Answer the same questions, but for a proton placed at point b and eventually crossing c’s equipotential line.arrow_forward
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