Concept explainers
(a)
Interpretation:
Whether
Concept introduction:
Sugars show different types of isomerism. They may be enantiomers, epimers, anomers, or diastereomers depending upon chirality and plane of symmetry in molecules. It also depends on stereochemistry of different carbons.
Answer to Problem 24.39AP
The compounds,
Explanation of Solution
The compounds,
They are diastereomers also as they are not mirror images of each other. The structure of both the compounds is shown below.
Figure 1
These two compounds are anomers as well as diastereomers as shown in Figure 1.
(b)
Interpretation:
Whether
Concept introduction:
Sugars show different types of isomerism between molecules. They may be enantiomers, epimers, anomers, or diastereomers depending upon chirality and plane of symmetry in molecules. It also depends on stereochemistry of different carbons.
Answer to Problem 24.39AP
The compounds,
Explanation of Solution
Both the above structures of
Figure 2
The compounds
(c)
Interpretation:
Whether
Concept introduction:
Sugars show different types of isomerism between molecules. They may be enantiomers, epimers, anomers, or diastereomers depending upon chirality and plane of symmetry in molecules. It also depends on stereochemistry of different carbons.
Answer to Problem 24.39AP
The compounds,
Explanation of Solution
Sugars can be divided into two groups based on the symmetry of carbon atoms. If the molecule has asymmetric carbon atom it will have a non superimposable mirror image. The non superimposable mirror images are known as enantiomers. As the given compounds are non super imposable mirror images of each other they are enantiomers. This can be well explained by the illustrations shown below.
Figure 3
These two compounds
(d)
Interpretation:
Whether
Concept introduction:
Sugars show different types of isomerism between molecules. They may be enantiomers, epimers, anomers, or diastereomers depending upon chirality and plane of symmetry in molecules. It also depends on stereochemistry of different carbons.
Answer to Problem 24.39AP
The compounds,
Explanation of Solution
As the isomers are the compounds, having similar chemical formula but different structures. These two compounds have same chemical formula. The chemical structure is of these two compounds is quite different as shown in Figure 4.
Figure 4
In the above shown compounds, one is a pentose sugar furanose while the other is a hexose sugar pyranose.
These two compounds,
(e)
Interpretation:
Whether
Concept introduction:
Sugars show different types of isomerism between molecules. They may be enantiomers, epimers, anomers, or diastereomers depending upon chirality and plane of symmetry in molecules. It also depends on stereochemistry of different carbons.
Answer to Problem 24.39AP
Explanation of Solution
As the isomers are the compounds, having similar chemical formula but different structures. Both the above structures are constitutional isomers as shown below in the Figure.
Figure 5
In the above shown compounds, one is a ring structure having keto group while the other is open ring structure having aldehyde as the functional group. The chemical formula of the given compounds is same but their properties are totally different.
The given compounds
(f)
Interpretation:
Whether the compounds,
Concept introduction:
Sugars show different types of isomerism between molecules. They may be enantiomers, epimers, anomers, or diastereomers depending upon chirality and plane of symmetry in molecules. It also depends on stereochemistry of different carbons. The naming of the same compound can be done in different manners.
Answer to Problem 24.39AP
The compounds,
Explanation of Solution
The structure of
Figure 6
So, the compound is same, they are identical. In first name it is taken as methyl derivative of
The compound shown in Figure 6 can be named as
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Chapter 24 Solutions
Organic Chemistry Study Guide and Solutions
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- Draw and name the seven aldehydes and ketones with the formula C5H10O. Which are chiral?arrow_forwardFour stereoisomers exist for 3-penten-2-ol. (a) Explain how these four stereoisomers arise. (b) Draw the stereoisomer having the E configuration about the carbon-carbon double bond and the R configuration at the chiral center.arrow_forward(a) What is the difference between the hormones progesterone and testosterone? (b) Draw the structure of a a steroid nucleus. (c) Give the products obtained from complete base hydrolysis in the following reaction: O || CH,−O−C−(CH2)14–CH3 O CH–0–C−(CH2)14—CH3 + 3 NaOH O CH,−0–C−(CH2)14–CH3arrow_forward
- Draw all the possible stereoisomerism for following structures. Label the chiral centre with an asterisk (*) if any. (a) CНICOОH)(NH)CH-COOH (b) (CH3)2C=C(COOH)CH(NO2)CH3arrow_forward4. Identify the component monosaccharides of each of the following compounds and describe the type of glycosidic linkage in each. Но он Но OH HO он Но- Но- (a) OH (c) CH,OHO. (b) CH2OHO Lon OH HO H ČHOH H OH ÓH ОНarrow_forward(a) meso-hexane-3,4-diol, CH3CH2CH(OH)CH(OH)CH2CH3, draw any diastereomers.arrow_forward
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