Concept explainers
A dosed surface with dimensions a = b= 0.400 111 and c = 0.600 in is located as shown in Figure 1*24.63. The left edge of the closed surface is located at position x = a. The electric field throughout the region is non- uniform and is given by
(a)
The net electric flux leaving the closed surface.
Answer to Problem 24.63CP
The net electric flux leaving the closed surface is
Explanation of Solution
Given info: The dimensions of the closed surface are
The position of the closed surface is,
Figure (1)
From the figure (1) the electric field is perpendicular to the normal of area ABEF, area CDHG, area ABCD and the area EFGH. Therefore,
The formula to calculate electric flux is,
Here,
The electric field makes an angle
Substitute
Thus, the flux out of the surface ABEF, CDHG, ABCD and EFGH is zero for the surfaces.
From figure (1), the area of the surface ACGE is,
From figure (1), the area of the surface BFDH is,
The electric flux in the
From figure (1), substitute
From Figure (1), substitute
The net flux leaving closed surface,
Here,
Substitute
Simplify the above equation.
Substitute
Conclusion:
Therefore, the net electric flux leaving the closed surface is
(b)
The net charge enclosed by the surface.
Answer to Problem 24.63CP
The net charge enclosed by the surface is
Explanation of Solution
Given info: The dimensions of the closed surface are
The flux enclosed by a closed surface is given by,
Here,
The permittivity of free space is
Substitute
Rearrange the above equation for
Conclusion:
Therefore, the net charge enclosed by the surface is
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Chapter 24 Solutions
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- Physics for Scientists and Engineers, Technology ...PhysicsISBN:9781305116399Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning