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Concept explainers
A Geiger–Mueller tube is a
(b) Show that the magnitude of the electric field in the space between cathode and anode is
where r is the distance from the axis of the anode to the point where the field is to be calculated.
Figure P24.42
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Chapter 24 Solutions
Physics for Scientists and Engineers with Modern Physics
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- E = E1 E = 0 E= E1 E= E1 The electric field is measured all over a cubical surface, and the pattern of field detected is shown in the figure above. On the right side of the cube, the electric field has magnitude Ej = 426 V/m, and the angle between the electric field and the surface of the cube is 0 = 15 degrees. On the bottom of the cube, the electric field has the same magnitude Ej, and the angle between the electric field and the surface of the cube is also 0 = 15 degrees. On the top of the cube and the left side of the cube, the electric field is zero. On half of the front and back faces, the electric field has magnitude Ej and is parallel to the face; on the other half of the front and back faces, the electric field is zero. One edge of the cube is 41 cm long. Part 1 What is the net electric flux on this cubical surface? Net electric flux = i V•m Save for Later Attempts: 0 of 4 used Submit Answerarrow_forwardHow many electrons are in a 1.00-g electrically neutral steel paper clip? The molar mass of steel is approximately that of iron, or 55.845 g/mol, and a neutral iron atom has 26 electrons.arrow_forwardSuppose a capacitor consists of two coaxial thin cylindrical conductors. The inner cylinder of radius ra has a charge of +Q, while the outer cylinder of radius rp has charge -Q. The electric field E at a radial distance r from the central axis is given by the function: E = ae-r/ao + B/r + bo where alpha (a), beta (B), ao and bo are constants. Find an expression for its capacitance. First, let us derive the potential difference Vab between the two conductors. The potential difference is related to the electric field by: ['´e Vob = Edr= - Edr Calculating the antiderivative or indefinite integral, Vab = (-aaoe¯r7ao + B + bo By definition, the capacitance C is related to the charge and potential difference by: C = Evaluating with the upper and lower limits of integration for Vab, then simplifying: C = Q / ( (erb/ao - eralao) + B In( ) + bo ( ))arrow_forward
- Electrons flow through a 1.5-mm-diameter aluminum wire at 1.0x10-4 m/s. Part A How many electrons move through a cross section of the wire each day? 5 ΑΣΦ xa Xb Ĵ a + √x vx x N= 9.16.1023 x Submit Previous Answers Request Answer X Incorrect; Try Again; 9 attempts remaining |xx| ? X. 10m B electronsarrow_forwardThe following are electron carriers in a hypothetical biological system: Electron Carriers (E° , V) A (0.17 V), B (0.04 V), C (0.31 V), D (-0.65 V), E (-0.25 V). a. Which electron carrier will be the best electron donor? b. Which electron carrier will be the final electron acceptor?arrow_forwardSuppose a capacitor consists of two coaxial thin cylindrical conductors. The inner cylinder of radius ra has a charge of +Q, while the outer cylinder of radius rh has charge -Q. The electric field E at a radial distancer from the central axis is given by the function: E = ae-r/ao + B/r + bo where alpha (a), beta (B), ao and bo are constants. Find an expression for its capacitance. First, let us derive the potential difference Vab between the two conductors. The potential difference is related to the electric field by: Vab = Edr = - Edr Calculating the antiderivative or indefinite integral, Vab = (-aaoe-r/ao + B + bo By definition, the capacitance C is related to the charge and potential difference by: C= Q I Vabarrow_forward
- Q. The ends of the cylinder are made of conducting discs and the space between these discs are filled with an inhomogeneous ohmic medium whose conductivity o = L/(z+1). Where L is the separation distance of the discs. A d-c voltage Vo is applied across the discs as shown on the right. Determine V. a) The total resistance between the discs b) The surface charge densities on the discs c) The volume charge density and the total amount of charge between the discsarrow_forwardSuppose a capacitor consists of two coaxial thin cylindrical conductors. The inner cylinder of radius ra has a charge of +Q, while the outer cylinder of radius rp has charge -Q. The electric field E at a radial distance r from the central axis is given by the function: E = aer/ao + B/r + bo %| where alpha (a), beta (B), ao and bo are constants. Find an expression for its capacitance. First, let us derive the potential difference Vab between the two conductors. The potential difference is related to the electric field by: Va Edr= Edr Calculating the antiderivative or indefinite integral, Vab = (-aaoe-r/ao + B + bo By definition, the capacitance C is related to the charge and potential difference by: C = Evaluating with the upper and lower limits of integration for Vab, then simplifying: C = Q/( (e-"b/ao - era/ao) + B In( ) + bo ( ))arrow_forwardA cylindrical capacitor is made of two concentric conducting cylinders. The inner cylinder has radius R1 = 19 cm and carries a uniform charge per unit length of λ = 30 μC/m. The outer cylinder has radius R2 = 25 cm and carries an equal but opposite charge distribution as the inner cylinder. a. Write an equation for the energy density due to the electric field between the cylinders in terms of λ, r, and e0. u = b. Calculate the energy stored in the capacitor per unit length, in units of J/m. U/l = c. Consider a thin cylindrical shell of thickness dr and radius R1 < r < R2 that is concentric with the cylindrical capacitor. Write an equation for the total energy per unit length contained in the shell in terms of λ, r, dr, and ε0. dU/l = d. Calculate the energy stored per unit length in the capacitor in units of joules per meter. U/l =arrow_forward
- What is the number density of free electron carries in the metallic element nickel if the electrons available for electrical conduction is 1 e- per nickel atom? The atomic mass of nickel is 58.6934 g/mole and the density of nickel is 8.902 g/cm3. a. 3.32 x 1028 e- ' s /m3 b. 1.56 x 1029 e- ' s /m3 c. 5.64 x 1028 e- ' s /m3 d. 9.13 x 1028 e- ' s /m3 e. 7.63 x 1028 e- ' s /m3arrow_forwardA person is found dead at 5 PM in a room whose temperature is 20 °C. The temperature of the body is measured to be 25°C when found, and the heat transfer coefficient is estimated to be 8 W/m2.°C. Modelling the the body as a 30 cm diameter and 1.7 m long cylinder. Use the lamped capacitance method. Take p=996 kg/m³, k=0.617 W/m.°C, Cp=4178 J/kg.K.arrow_forwardTwo protons (p) and two electrons (e) are arranged on a circle of radius r = 4 [cm], with angles 0₁ = 20°, 0₂ = 30°, 03 = 20° and 04 = 60°, as shown in the figure. (qp = +1.6 x 10-1⁹ [C] and qe = -1.6 x 10-¹⁹ [C]). The figure is not to scale. a the circle. 04 Ēnet = ( 02 P Find Enet, the net electric field vector produced at the center of ])i + ( [ ]) Ĵ [N/C] b. Where on the circle should a fifth point charge qo be placed (give its angle relative the +x-axis) and what is its value (calculate qo) in order to have Enet (the net electric field at the center of the circle) equals zero (Type the detailed solution to this question in the below box, Show all your calculation steps by typing in the box). X Fiarrow_forward
- Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage LearningPhysics for Scientists and Engineers with Modern ...PhysicsISBN:9781337553292Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPrinciples of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
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