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Concept explainers
(a)
ToCalculate: The electric field and the energy density as a function of
(a)
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Answer to Problem 50P
Explanation of Solution
Given information :
Radius of inner radius =
Charge of inner radius =
Radius of outer radius =
Charge of outer radius =
Formula used :
From Gauss’s law:
Where,
Energy density is given by:
Calculation:
Use Gauss’s law to find the electric field for spherical surfaces of radii
For
Because,
For
For
Because
Conclusion:
The energy density is:
The electric field is:
(b)
ToCalculate: The energy associated with the electrostatic field in a spherical shell between the conductors that has a radius
(b)
![Check Mark](/static/check-mark.png)
Answer to Problem 50P
Explanation of Solution
Given information:
Radius of inner radius =
Charge of inner radius =
Radius of outer radius =
Charge of outer radius =
The energy density is:
Formula Used:
The energy in the electrostatic field in a spherical shell of radius
Calculation:
Conclusion:
The energy associated with the electrostatic field is,
(c)
ToFind: The total energy and compare the result with the result obtained using
(c)
![Check Mark](/static/check-mark.png)
Answer to Problem 50P
Explanation of Solution
Given information:
Radius of inner radius =
Charge of inner radius =
Radius of outer radius =
Charge of outer radius =
Formula used:
Energy density:
Where, Q is the charge and V is the voltage.
The energy associated with the electrostatic field is
Calculation:
Integrate
Conclusion:
Theintegration of the given expression is:
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PHYSICS F/SCI.+ENGRS.,STAND.-W/ACCESS
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