For Exercises 91−98, use the graph to solve the equation and inequalities. Write the solutions to the inequalities in interval notation. (See Examples 8 − 9 ) 95. a . − 3 ( x + 2 ) + 1 = − x + 5 b . − 3 ( x + 2 ) + 1 ≤ − x + 5 c . − 3 ( x + 2 ) + 1 ≥ − x + 5
For Exercises 91−98, use the graph to solve the equation and inequalities. Write the solutions to the inequalities in interval notation. (See Examples 8 − 9 ) 95. a . − 3 ( x + 2 ) + 1 = − x + 5 b . − 3 ( x + 2 ) + 1 ≤ − x + 5 c . − 3 ( x + 2 ) + 1 ≥ − x + 5
Solution Summary: The author explains how to solve the equation -3(x+2)+1=-x +5 graphically. The point of intersection is (-5,10).
For Exercises 91−98, use the graph to solve the equation and inequalities. Write the solutions to the inequalities in interval notation. (See Examples 8−9) 95.
a
.
−
3
(
x
+
2
)
+
1
=
−
x
+
5
b
.
−
3
(
x
+
2
)
+
1
≤
−
x
+
5
c
.
−
3
(
x
+
2
)
+
1
≥
−
x
+
5
Determine whether the statement makes sense or does not make sense, and explain your reasoning.
In an inequality such as 5x + 4< 8x - 5, I can avoid division by a negative number depending on which side I collect the variable terms and on which side I collect the constant terms.
I'm reviewing for precalc. Can you help me review absolute values and inequalities correctly? I'm working with the absolute value of (5x-3) -2 is less than or equal to 9.
Any help would be appreciated. Thank you.
Elementary Algebra For College Students (9th Edition)
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, algebra and related others by exploring similar questions and additional content below.