Genetics: A Conceptual Approach
Genetics: A Conceptual Approach
6th Edition
ISBN: 9781319050962
Author: Benjamin A. Pierce
Publisher: W. H. Freeman
Question
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Chapter 24.1, Problem 17AQP

(a)

Summary Introduction

To determine:

Expected weights in the F1 progeny if genotype AABB is crossed with aabb.

Introduction:

In the given scenario, it is supposed that plant weight is determined by a pair of alleles at each of two independently assorting loci (A and a, B and b) that are additive in their effects. The alleles represented by uppercase letters contribute 4 grams to plant weight, while the alleles represented by lowercase letters contribute 1 gram to plant weight.

(a)

Expert Solution
Check Mark

Explanation of Solution

The cross between AABB and aabb is as follows:

Parents AABB×aabbGamatesABabF1generationAaBb

F1 (filial 1) generation is AaBb. Its weight can be determined as weight contributed by A + weight contributed by a + weight contributed by B + weight contributed by b (4 + 1 + 4 + 1). So, the plant weight in F1 generation would be 10 grams.

(b)

Summary Introduction

To determine:

Expected weights in the F2 progeny if genotype AABB is crossed with aabb.

Introduction:

In the given scenario, it is supposed that plant weight is determined by a pair of alleles at each of two independently assorting loci (A and a, B and b) that are additive in their effects. The alleles represented by uppercase letters contribute 4 grams to plant weight, while the alleles represented by lowercase letters contribute 1 gram to plant weight.

(b)

Expert Solution
Check Mark

Explanation of Solution

Gametes formed from F1 generation would be AB, Ab, aB, and ab as follows:

F1generationAaBbGamatesABAbaBab

F2 generation is produced when F1 generation is inter-crossed and their expected plant weights would be as follows:

ABAbaBabABAABB(4+4+4+4=16g)AABb(4+4+4+1=13g)AaBB(4+1+4+4=13g)AaBb(4+1+4+1=10g)AbAABb(4+4+4+1=13g)AAbb(4+4+1+1=10g)AaBb(4+1+4+1=10g)Aabb(4+1+1+1=7g)aBAaBB(4+1+4+4=13g)AaBb(4+1+4+1=10g)aaBB(1+1+4+4=10g)aaBb(1+1+4+1=7g)abAaBb(4+1+4+1=10g)Aabb(4+1+1+1=7g)aaBb(1+1+4+1=7g)aabb(1+1+1+1=4g)

Highest plant weight in F2 generation would be of AABB (16 grams) and lowest would be of aabb (4 grams).

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