Concept explainers
In 1911, Ernest Rutherford and his assistants Geiger and Marsden
Trending nowThis is a popular solution!
Chapter 25 Solutions
EBK PHYSICS FOR SCIENTISTS AND ENGINEER
- where 1 eV = 1.602 × 10-19 J. Express the neutron’s kinetic energy in electron volts. b) In nuclear physics, it is convenient to express the energy of particles in electron volts (eV), 2) A neutron with a mass of 1.7 × 10-27 kg passes between two points in a detector 6 m apart in a time interval of 1.8 x 10-4 s. In the tendon at this pon a) Find the kinetic energy of the neutron in joulesarrow_forwardProblem 17: An evacuated tube uses a potential difference of AV= 0.56 kV to accelerate electrons, which then hit a copper plate and produce X-rays. . Part (a) Write an expression for the non-relativistic speed of these electrons v in terms of e, AV, and m, assuming the electrons start from rest. v = AV 7 9 HOME a b d. 4 5 e h 1 j k P END m S V VO BACKSPACE CLEAR DEL Submit Hint Feedback I give up! Hints: 0% deduction per hint. Hints remaining: 2 Feedback: 1% deduction per feedback. Part (b) Calculate the non-relativistic speed of these electrons v in m/s.arrow_forwardA hydrogen atom when in its lowest energy state consists of a proton nucleus of charge +e (remember that +e = 1.6 x 10-19 C) and an electron of charge -e and mass of 9.1 x 10-31 kg. In the Bohr model of the atom, the electron moves around the nucleus in an approximately circular orbit with a radius of 0.52 x 10-10 m. The speed of the electron when in this lowest energy orbit is approximately 2.3 x 106 m/s. Imagine that we want to ionize this atom (that is free up the electron from its nucleus) by launching ANOTHER electron at the atom to break it apart. If we were to launch this electron from very far away from the atom, then how fast must it be launched in order to break apart the atom, so that all three particles (the proton and two electrons) end up at rest, very far apart?arrow_forward
- In this problem, we will try to understand why chemical reactions cannot power the Sun, but nuclear reactions can. The energy scale of chemical reactions is a few eV, where eV is a unit of energy called an electron volt. 1 eV = 1.602 x 10-19 J. A typical chemical reaction involves an energy change of ~0.1 to 10 eV. In contrast, a nuclear reaction typically involves a change in energy of order a few MeV (mega electron volts; a factor of a million larger). Suppose that the Sun has a constant luminosity throughout its life, equal to its current luminosity of L⊙=3.827×1026J/s . Suppose also that the Sun is made entirely of hydrogen (or just protons, since the mass of the electron is about 2000 times smaller and is negligible in comparison). If every pair of two protons in the Sun undergo a one-time chemical reaction that nets ~1 eV of energy, how long would it take (in years) to expend all the available chemical energy?arrow_forwardAn atom of beryllium (m = 8.00 u) splits into two atoms of helium (m = 4.00 u) with the release of 92.2 keV of energy. If the original beryllium atom is at rest, find the kinetic energies and speeds of the two helium atoms.arrow_forwardAn evacuated tube uses a potential difference of ΔV = 0.38 kV to accelerate electrons, which then hit a copper plate and produce X-rays Write an expression for the non-relativistic speed of these electrons v in terms of e, ΔV, and m, assuming the electrons start from rest. Calculate the non-relativistic speed of these electrons v in m/s.arrow_forward
- Consider an electron, of charge magnitude e = 1.602 × 10-1⁹ C and mass m₂ = 9.11 × 10-31 kg, moving in an electric field with an electric field magnitude E = 4 x 10² N/C, similar to what Thana observed in the simulation. Let the length of the plates be L = 50 cm, and the distance between them be d = 20 cm. Find the maximum speed, v, the electron could be moving if it enters the space halfway between and parallel to the two plates to just barely strike one of the plates. m/s If the field is pointing upward, which plate will Thana conclude the electron strikes at this speed? O The upper plate, because the electron charge magnitude is positive. O The upper plate, because we are only considering the magnitude of the electron charge, and magnitudes are always positive. O The lower plate, because the electron is attracted to the negative plate. O The lower plate, because the electron is negatively charged.arrow_forwardPlease Solve Correctly.arrow_forwardElectron capture is a variant on beta-radiation. The lightest nucleus to decay by electron capture is 7Be -- beryllium-7. The daughter nucleus is 7Li -- lithium-7. The electron is transformed into a massless particle (a neutrino): e − + 7 B e + ⟶ 7 L i + ν The initial electron is bound in the atom, so the beryllium mass includes the electron. In fact, since the electron starts bound in the atom, a more-accurate statement of the nuclear reaction is probably: 7 B e ⟶ 7 L i + ν The masses are beryllium: 7.016929 u, and lithium: 7.016003 u, and refer to the neutral atom as a whole. (Use uc and uc2 as your momentum and energy units -- but carry them along in your calculation.) The initial beryllium atom is stationary. Calculate the speed of the final lithium nucleus in km/s. (all the energy released goes into the lighter particle. c = 300,000 km/s)arrow_forward
- Electron capture is a variant on beta-radiation. The lightest nucleus to decay by electron capture is 7Be -- beryllium-7. The daughter nucleus is 7Li -- lithium-7. The electron is transformed into a massless particle (a neutrino): e − + 7 B e + ⟶ 7 L i + ν The initial electron is bound in the atom, so the beryllium mass includes the electron. In fact, since the electron starts bound in the atom, a more-accurate statement of the nuclear reaction is probably: 7 B e ⟶ 7 L i + ν The masses are beryllium: 7.016929 u, and lithium: 7.016003 u, and refer to the neutral atom as a whole. (Use uc and uc2 as your momentum and energy units -- but carry them along in your calculation.) The initial beryllium atom is stationary. Calculate the speed of the final lithium nucleus in km/s. (You will make life much easier for yourself if you recognize that practically all the energy released goes into the lighter particle. c = 300,000 km/s)arrow_forwardIn an x-ray tube, high-speed electrons are slammed into a lead target, giving off x-rays. If the electrons are accelerated from rest through a potential difference of 190 000 volts, what speed do they have when they strike the target? ( q e = 1.6 × 10 −19 C, m e = 9.11 × 10 −31 kg, and c = 3.00 × 10 8 m/s)arrow_forwardHelpful information: (1) An alpha particle is a helium nucleus, (2) e = 1.6 × 10-¹⁹ C, (3) k₂ = 9.0 × 10⁹ Nm² C-2, (4) 1nm = 1 × 10-⁹ m 1-An alpha particle lies on the x-axis, a distance of 1.0 nanometer from a proton (in this set-up, the alpha particle is at the origin while the proton is in the positive direction). Which of the following choices below represents the magnitude of the electric force on the alpha particle? (a) 2.3 × 10-10 N (b) 4.6 × 10-10 N (c) 2.3 x 10-19 N (d) 4.6 x 10-19 N cing the voltage so following insta choices below at a time! 1.00 s?arrow_forward
- College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningUniversity Physics (14th Edition)PhysicsISBN:9780133969290Author:Hugh D. Young, Roger A. FreedmanPublisher:PEARSONIntroduction To Quantum MechanicsPhysicsISBN:9781107189638Author:Griffiths, David J., Schroeter, Darrell F.Publisher:Cambridge University Press
- Physics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningLecture- Tutorials for Introductory AstronomyPhysicsISBN:9780321820464Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina BrissendenPublisher:Addison-WesleyCollege Physics: A Strategic Approach (4th Editio...PhysicsISBN:9780134609034Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart FieldPublisher:PEARSON