a. Explanation Given information : Given equation 100 e − x / 100 = 0.01 x 2 Formula used : By Intermediate Value theorem a continuous function f ( x ) has a solution c ∈ ( a , b ) , if f ( x ) has opposite signs at x = a , b . Proof : Given equation 100 e − x / 100 = 0.01 x 2 Let f ( x ) = 100 e − x / 100 − 0.01 x 2 ..... ( 1 ) is continuous over ( − ∞ , ∞ ) . Let x = 0 , 100 in equation ( 1 ) , we get f ( 0 ) = 100 > 0 and f ( 100 ) = 100 e − 100 / 100 − 0 b. To determine To find the solution of equation 100 e − x / 100 = 0.01 x 2 using graphing calculator and correct to three decimal places.

15th Edition

ISBN: 9781133109631

Author: Stewart, JAMES, Day, Troy

Publisher: Cengage Learning,

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Question

Chapter 2.5, Problem 47E

To determine

Toprove : that the equation 100e−x/100=0.01x2 has at least one real solution.

To determine

To find the solution of equation 100e−x/100=0.01x2 using graphing calculator and correct to three decimal places.

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Chapter 2.5, Problem 46E

Chapter 2.5, Problem 48E

Chapter 2 Solutions

Biocalculus

Ch. 2.1 - Prob. 1E Ch. 2.1 - Prob. 2E Ch. 2.1 - Prob. 3E Ch. 2.1 - Prob. 4E Ch. 2.1 - Prob. 5E Ch. 2.1 - Prob. 6E Ch. 2.1 - Prob. 7E Ch. 2.1 - Prob. 8E Ch. 2.1 - Prob. 9E Ch. 2.1 - Prob. 10E

Ch. 2.1 - Prob. 11E Ch. 2.1 - Prob. 12E Ch. 2.1 - Prob. 13E Ch. 2.1 - Prob. 14E Ch. 2.1 - Prob. 15E Ch. 2.1 - Prob. 16E Ch. 2.1 - Prob. 17E Ch. 2.1 - Prob. 18E Ch. 2.1 - Prob. 19E Ch. 2.1 - Prob. 20E Ch. 2.1 - Prob. 21E Ch. 2.1 - Prob. 22E Ch. 2.1 - Prob. 23E Ch. 2.1 - Prob. 24E Ch. 2.1 - Prob. 25E Ch. 2.1 - Prob. 26E Ch. 2.1 - Prob. 27E Ch. 2.1 - Prob. 28E Ch. 2.1 - Prob. 29E Ch. 2.1 - Prob. 30E Ch. 2.1 - Prob. 31E Ch. 2.1 - Prob. 32E Ch. 2.1 - Prob. 33E Ch. 2.1 - Prob. 34E Ch. 2.1 - Prob. 35E Ch. 2.1 - Prob. 36E Ch. 2.1 - Prob. 37E Ch. 2.1 - Prob. 38E Ch. 2.1 - Prob. 39E Ch. 2.1 - Prob. 40E Ch. 2.1 - Prob. 41E Ch. 2.1 - Prob. 42E Ch. 2.1 - Prob. 43E Ch. 2.1 - Prob. 44E Ch. 2.1 - Prob. 45E Ch. 2.1 - Prob. 46E Ch. 2.1 - Prob. 47E Ch. 2.1 - Prob. 48E Ch. 2.1 - Prob. 49E Ch. 2.1 - Prob. 50E Ch. 2.1 - Prob. 51E Ch. 2.1 - Prob. 52E Ch. 2.1 - Prob. 53E Ch. 2.1 - Prob. 54E Ch. 2.1 - Prob. 55E Ch. 2.1 - Prob. 56E Ch. 2.1 - Prob. 57E Ch. 2.1 - Prob. 58E Ch. 2.1 - Prob. 59E Ch. 2.1 - Prob. 60E Ch. 2.1 - 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Prob. 9CS

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Toprove : that the equation 100 e − x / 100 = 0.01 x 2 has at least one real solution.

Solution Summary: The author proves that the equation 100e-x/100=0.01x2 has at least one real solution.