a. Explanation Given data: Length of the muscle tissue is 8 cm. Width of the muscle tissue is 1 cm. Initial magnetic field is 1.6 T. Final magnetic field is 0 T. Time period is 0.3 s. Formula used: Write the expression for area of circle. A = π r 2 (1) Here, A is the area of the circle and r is the radius. Write the expression for circumference of circle. C = 2 π r (2) Here, C is the circumference of the circle. Write the expression for resistance. R = ρ l A (3) Here, R is the resistance of the material, ρ is the resistivity of the material with value 13 Ω ⋅ m , l is the length of the material, and A is the cross-sectional area of the material. Write the expression for current. I = ε R (4) Here, I is the current. Write the expression for magnetic flux through coil. Φ = B A cos θ (5) Here, Φ is the magnetic flux, A is the area, and θ is the angle between the plane of area to the magnetic field. Write the expression for emf. ε = | Δ Φ Δ t | (6) Here, ε is the induced emf, Δ Φ is the change in magnetic flux, and Δ t is the time period. Write the expression for power and work done. P = W Δ t (7) Here, P is the power, W is the work done, and Δ t is the time period. Write the expression for power and current. P = I 2 R (8) Write the expression for mass. m = ρ V (9) Here, m is the mass, ρ is the density of the material with value 1.1 × 10 3 kg m 3 , and V is the volume of the material. Write the expression for heat energy. Q = m c Δ T (10) Here, Q is the heat energy, c is the specific heat with value 3600 J ⋅ K kg , and Δ T is the change in temperature. Explanation: Combining equation (5) and (6), ε = A Δ B Δ t (11) For cross-sectional area of coil ( A coil ) , Substitute 4 × 10 − 2 m for r in equation (1), A = π × ( 4 × 10 − 2 m ) 2 = 5.03 × 10 − 2 m 2 For cross-sectional area of muscle ( A muscle ) , Substitute 4 × 10 − 2 m for r in equation (1), A = π × ( 5 × 10 − 3 m ) 2 = 7.85 × 10 − 5 m 2 Circumference of the wire ( l ) , Substitute 4 × 10 − 2 m for r in equation (2), l = 2 π × 4 × 10 − 2 m = 2 b. To determine The increase in the tissue temperature.

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ISBN: 9780134700427

Author: Knight

Publisher: PEARSON

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Chapter 25, Problem 61GP

To determine

The energy dissipated in the loop.

To determine

The increase in the tissue temperature.

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Chapter 25, Problem 60GP

Chapter 25, Problem 62GP

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In Figure P19.2, assume in each case the velocity vector shownis replaced with a wire carrying a current in the direction ofthe velocity vector. For each case, find the direction of themagnetic force acting on the wire.

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Chapter 25 Solutions

COLLEGE PHYSICS - LCPO

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The energy dissipated in the loop.

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The energy dissipated in the loop.

The increase in the tissue temperature.

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Chapter 25 Solutions