Explanation Given info: The car is of voltage 12.6 V . The internal resistance is connected in series to 3.2 Ω . The current-voltage relationship is V = α I + β I 2 . α = 3.8 Ω . β = 1.3 Ω . Explanation : According to the loop rule the potential change over a closed loop will be zero. Write the expression of loop rule for the given circuit. ε − I R − V = 0 Here, ε is the potential difference of the battery R is the resistance I is the current in the circuit V is the voltage Substitute the expression of voltage-current relationship in the above equation. ε − I R − α I + β I 2 = 0 Re-write the above expression in the form of a quadratic equation. β I 2 − ( R + α ) I + ε = 0 Solve the above equation to get an expression for I considering only the positive root. I = − ( R + α ) + ( R + α ) 2 − 4 β ε 2 β Substitute 12

University Physics with Modern Physics Technology Update, Volume 2 (CHS. 21-37)

13th Edition

ISBN: 9780321898098

Author: Hugh D. Young

Publisher: PEARSON

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Question

Chapter 25, Problem 73E

To determine

The current through the 3.2 Ω .

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Chapter 25, Problem 72E

Chapter 25, Problem 74E

Chapter 25 Solutions

University Physics with Modern Physics Technology Update, Volume 2 (CHS. 21-37)

Ch. 25 - Prob. 1DQ Ch. 25 - Prob. 2DQ Ch. 25 - Prob. 3DQ Ch. 25 - Prob. 4DQ Ch. 25 - Prob. 5DQ Ch. 25 - Prob. 6DQ Ch. 25 - Prob. 7DQ Ch. 25 - Prob. 8DQ Ch. 25 - Prob. 9DQ Ch. 25 - Prob. 10DQ

Ch. 25 - Prob. 11DQ Ch. 25 - Prob. 12DQ Ch. 25 - Prob. 13DQ Ch. 25 - Prob. 14DQ Ch. 25 - Prob. 15DQ Ch. 25 - Prob. 16DQ Ch. 25 - Prob. 17DQ Ch. 25 - Prob. 18DQ Ch. 25 - Prob. 19DQ Ch. 25 - Prob. 20DQ Ch. 25 - Prob. 21DQ Ch. 25 - Prob. 22DQ Ch. 25 - Prob. 23DQ Ch. 25 - Prob. 24DQ Ch. 25 - Prob. 1E Ch. 25 - Prob. 2E Ch. 25 - Prob. 3E Ch. 25 - Prob. 4E Ch. 25 - Prob. 5E Ch. 25 - Prob. 6E Ch. 25 - Prob. 7E Ch. 25 - Prob. 8E Ch. 25 - Prob. 9E Ch. 25 - Prob. 10E Ch. 25 - Prob. 11E Ch. 25 - Prob. 12E Ch. 25 - Prob. 13E Ch. 25 - Prob. 14E Ch. 25 - Prob. 15E Ch. 25 - Prob. 16E Ch. 25 - Prob. 17E Ch. 25 - Prob. 18E Ch. 25 - Prob. 19E Ch. 25 - Prob. 20E Ch. 25 - Prob. 21E Ch. 25 - Prob. 22E Ch. 25 - Prob. 23E Ch. 25 - Prob. 24E Ch. 25 - Prob. 25E Ch. 25 - Prob. 26E Ch. 25 - Prob. 27E Ch. 25 - Prob. 28E Ch. 25 - Prob. 29E Ch. 25 - Prob. 30E Ch. 25 - Prob. 31E Ch. 25 - Prob. 32E Ch. 25 - Prob. 33E Ch. 25 - Prob. 34E Ch. 25 - Prob. 35E Ch. 25 - Prob. 36E Ch. 25 - Prob. 37E Ch. 25 - Prob. 38E Ch. 25 - Prob. 39E Ch. 25 - Prob. 40E Ch. 25 - Prob. 41E Ch. 25 - Prob. 42E Ch. 25 - Prob. 43E Ch. 25 - Prob. 44E Ch. 25 - Prob. 45E Ch. 25 - Prob. 46E Ch. 25 - Prob. 47E Ch. 25 - Prob. 48E Ch. 25 - Prob. 49E Ch. 25 - Prob. 50E Ch. 25 - Prob. 51E Ch. 25 - Prob. 52E Ch. 25 - Prob. 53E Ch. 25 - Prob. 54E Ch. 25 - Prob. 55E Ch. 25 - Prob. 56E Ch. 25 - Prob. 57E Ch. 25 - Prob. 58E Ch. 25 - Prob. 59E Ch. 25 - Prob. 60E Ch. 25 - Prob. 61E Ch. 25 - Prob. 62E Ch. 25 - Prob. 63E Ch. 25 - Prob. 64E Ch. 25 - Prob. 65E Ch. 25 - Prob. 66E Ch. 25 - Prob. 67E Ch. 25 - Prob. 68E Ch. 25 - Prob. 69E Ch. 25 - Prob. 70E Ch. 25 - Prob. 71E Ch. 25 - Prob. 72E Ch. 25 - Prob. 73E Ch. 25 - Prob. 74E Ch. 25 - Prob. 75E Ch. 25 - Prob. 76E Ch. 25 - Prob. 77E Ch. 25 - Prob. 78E Ch. 25 - Prob. 79E Ch. 25 - Prob. 80E Ch. 25 - Prob. 81E Ch. 25 - Prob. 82E Ch. 25 - Prob. 83E Ch. 25 - Prob. 84E Ch. 25 - Prob. 85E Ch. 25 - Prob. 86E Ch. 25 - Prob. 87E

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