Physics for Scientists and Engineers with Modern Physics
Physics for Scientists and Engineers with Modern Physics
10th Edition
ISBN: 9781337671729
Author: SERWAY
Publisher: Cengage
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Chapter 26, Problem 42AP

(a)

To determine

To show: The resistance between the ends of the wire under strain is given by R=Ri(1+2δ+δ2) .

(b)

To determine

Whether the result is exact or approximate, if assumptions are precisely true.

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The strain in a wire can be monitored and computed by measuring the resistance of the wire. Let Li represent the original length of the wire, Ai its original cross-sectional area, Ri = ρLi /Ai the original resistance between its ends, and δ = ΔL/Li = (L - Li )/Li the strain resulting from the application of tension. Assume the resistivity and the volume of the wire do not change as the wire stretches. (a) Show that the resistance between the ends of the wire under strain is given by R = Ri (1 + 2δ + δ2). (b) If the assumptions are precisely true, is this result exact or approximate? Explain your answer.
A metallic wire is stretched from original length of 1 m to 5 m. If the original cross-sectional area is 4 square millimeters and original resistance is 7 ohms, determine the new resistance (in ohms) of the metallic wire. Assume the volume of the wire is preserved.
A cylindrical conductor has resistance of R0 = 950 Ω. It has length L, radius of the cross section r, and resistivity ρ. a) If the resistivity was restored to its original value and instead the length of the conductor decreased by a factor of 2, what would the value of the new resistance be, in ohms?  b) If the resistivity and length of the conductor were at their original values and the radius of the conductor increased by a factor of 4, what would be the value of the new resistance, in ohms?

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Physics for Scientists and Engineers with Modern Physics

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