Concept explainers
(a)
Intensity of light at the surface of the bulb.
(a)
Answer to Problem 59P
The intensity is
Explanation of Solution
Write the equation for intensity
Here
Write the equation for surface area.
Here
Substitute (II) in (I)
Conclusion:
Substitute
The intensity is
(b)
Light intensity at
(b)
Answer to Problem 59P
The intensity is
Explanation of Solution
Write the equation for radius
Here
Substitute (IV) in (III)
Conclusion:
Substitute
The intensity is
(c)
Diameter of the bulb’s image.
(c)
Answer to Problem 59P
Image diameter is
Explanation of Solution
Write the mirror equation
Here
Rearrange (VI) in terms of
Diameter of the image is same as that of the height of the image.
Write the equation for image magnification
Here
Write the equation for magnification in terms of image height.
Here
Equate (VIII) and (IX) and write in terms of
Conclusion:
Substitute
Substitute
Image diameter is
(d)
Light intensity at the image.
(d)
Answer to Problem 59P
The intensity is
Explanation of Solution
Write the equation for area of the bulb
Here
Substitute (XI) in (I)
Conclusion:
Substitute
The intensity is
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Chapter 26 Solutions
Principles of Physics
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