Explanation Given data: The room temperature is 20 ° C . Formula used: Write the expression of the average kinetic energy of an atom in an ideal gas. K a v = 3 2 k b T Here, K a v is the average kinetic energy of an atom in an ideal gas, k b is the Boltzmann constant and T is the temperature. Write the expression for the energy of a photon of visible light. E p h = h ν Here, E p h is the energy of the photon, h is Planck’s constant and ν is the frequency of the photon. Write the expression of unit conversion from degree Celsius to Kelvin. T ( K ) = T ( ° C ) + 273 Here, T ( K ) is the temperature in Kelvin and T ( ° C ) is the temperature in degree Celsius. Explanation: The frequency of the visible light photon is 5 × 10 14 Hz . Recall the expression of unit conversion from degree Celsius to Kelvin. T ( K ) = T ( ° C ) + 273 Substitute 20 ° C for T ( ° C ) . T ( K ) = 20 ° C + 273 = 293 K Recall the expression for the average kinetic energy of an atom in an ideal gas. K a v = 3 2 k b T Substitute 1.38 × 10 − 23 J/K for k b and 293 K for T . K a v = 3 2 ( 1

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Chapter 27, Problem 9P

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The average kinetic energy of an atom in an ideal gas at 20°C and compare the result with the energy of a photon of visible light.

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Chapter 27, Problem 8P

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The average kinetic energy of an atom in an ideal gas at 20 ° C and compare the result with the energy of a photon of visible light.

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The average kinetic energy of an atom in an ideal gas at 20°C and compare the result with the energy of a photon of visible light.

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