Introduction to Algorithms
3rd Edition
ISBN: 9780262033848
Author: Thomas H. Cormen, Ronald L. Rivest, Charles E. Leiserson, Clifford Stein
Publisher: MIT Press
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Chapter 27.1, Problem 8E
Program Plan Intro
The following is the analysis of work, span, and parallelism of replaced parallel for loop in line 3 of P-TRANSPOSE with ordinary for loop.
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Consider an unordered list of data pieces L[0:5] = 23, 14, 98, 45, 67, 53. Let's look for the key K = 53. Obviously, the search proceeds along the list, comparing key K with each element until it finds it as the final member in the list. In the instance of looking for the key K = 110, the search proceeds but falls off the list, declaring it failed.
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Chapter 27 Solutions
Introduction to Algorithms
Ch. 27.1 - Prob. 1ECh. 27.1 - Prob. 2ECh. 27.1 - Prob. 3ECh. 27.1 - Prob. 4ECh. 27.1 - Prob. 5ECh. 27.1 - Prob. 6ECh. 27.1 - Prob. 7ECh. 27.1 - Prob. 8ECh. 27.1 - Prob. 9ECh. 27.2 - Prob. 1E
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- Referring to InsertionSort: (a) Prove using mathematical induction that for all 0 ≤ i ≤n-1 that after the for loop ends each i that the 0,....i elements of the list are sorted. (b) Use your answer to (a) to conclude mathematically that InsertionSort works.arrow_forwardConsider a list of data components L[0:5] = 23, 14, 98, 45, 67, and 53. Let's look for the K = 53 key. Naturally, the search moves down the list, comparing key K with each element until it discovers it as the final element in the list. When looking for the key K = 110, the search moves forward but eventually drops off the list, making it a failed search. Write the algorithmic steps for both sorted and unordered linear searches, along with the times involved.arrow_forward1. Input: An undirected weighted graph G = (V, E, w)2. Output: An MST T = (V, E) of G3. T ← Ø4. Sort edges of G in non-increasing order and place them in a queue Q.5. repeat6. Remove the first edge (u, v) from Q and add it to T if it does not form a cyclewith the edges edge that are already included in T .7. until there are n − 1 edges in T .We can use union-find data structure to find whether the two endpoints of theselected edge are in the same set (the current MST fragment). It can be shown thatthis algorithm is correct and has a time complexity of O(m log n) [1].Give Python Implementation of algoarrow_forward
- Give a MPI program segment to convert a n-by-n matrix distributed on a n-by-n 2D mesh such that allits rows and columns get sorted in ascending order. Show only the iterative loop. Only communicationsallowed are to the four direct neighbors. (Hint: You may employ a variant of odd-even transpositionsort, but the whole matrix does not need to be sorted.)arrow_forwardDevelop a topological sort implementation thatmaintains a vertex-indexed array that keeps track of the indegree of each vertex. Initialize the array and a queue of sources in a single pass through all the edges Then, perform the following operations until the source queue is empty:■ Remove a source from the queue and label it.■ Decrement the entries in the indegree array corresponding to the destinationvertex of each of the removed vertex’s edges.arrow_forwardThe Burrows-Wheeler transform (BWT) is a transformation that is used in data compression algorithms, including bzip2, and in high-throughput sequencing in genomics. Write a SuffixArray client that computes the BWT in linear time, as follows: Given a string of length N (terminated by a special end-of-file character $ that is smaller than any other character), consider the N-by-N matrix in which each row contains a different cyclic rotation of the original text string. Sort the rows lexicographically. The Burrows-Wheeler transform is the rightmost column in the sorted matrix. For example, the BWT of Mississippi is ipssm$pissii. The Burrows-Wheeler inverse transform (BWI) inverts the BWT. For example, the BWI of ipssm$pissii is mississippi$. Also write a client that, given the BWT of a text string, computes the BWI in linear time.arrow_forward
- Develop a topological sort implementation thatmaintains a vertex-indexed array that keeps track of the indegree of each vertex. Initialize the array and a queue of sources in a single pass through all the edges. Then, perform the following operations until the source queue is empty:■ Remove a source from the queue and label it.■ Decrement the entries in the indegree array corresponding to the destination vertex of each of the removed vertex’s edges If decrementing any entry causes it to become 0, insert the corresponding vertex onto the source queue.arrow_forwardThe book demonstrated that a poisoned reverse will prevent the count-to-infinity problem caused when there is a loop involving three directly connected nodes. However, other loops are possible. Will the poisoned reverse solve the general case count-to-infinity problem encountered by Bellman-Ford? -Yes, the poisoned reverse will prevent a node from offering a path that includes preceding nodes in the loop. -It will not, preceeding nodes may still be used in the computation of the distance vector offered by a given node.arrow_forwardSuppose you are given a partially-filled sorted linked list and a partially-filled unsorted linked list of the same size. Assume it is a singly linked list (no back edges).Describe the efficiency of searching for a value within each list and deleting it, including the order of such an operation.arrow_forward
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