Introduction to Java Programming and Data Structures, Comprehensive Version (11th Edition)
11th Edition
ISBN: 9780134670942
Author: Y. Daniel Liang
Publisher: PEARSON
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Chapter 27.4, Problem 27.4.4CP
Program Plan Intro
Open addressing:
- Open Addressing is a method of finding an open location in the hash table at the time of collision.
- There are several variations for open addressing such as linear probing, quadratic probing, and double hashing.
Linear probing:
- Linear probing is one of the variations of open addressing.
- When an entry is inserted into a hash table, a collision occurs. At the time of collision, linear probing will start finding the next available location sequentially.
- Linear probing will look at the consecutive cells which begin at index k.
- Starting from the initial index, linear probing will add an increment of 1 to k to define a search sequence.
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Using quadratic probing, create a hash table HT[0..8, 0..2] for the collection of keys 17, 9, 34, 56, 11, 4, 71, 86, 55, 10, 39, 49, 52, 82, 31, 13, 22, 35, 44, 20, 60, and 28.Use the hashing formula H(X) = X mod 9. What conclusions have you drawn?
Suppose we have a hash table of size 11 and use the hash function h(key) = (key + i2) % 11, where i = 0, 12, 22, ..., 102. After inserting entries with keys 35, 29, 54, 43, 121, 33, 44, and 187. What is the index of key 187?
index = {0, 1, 2, ..., 10}
For the set of keys {17, 9, 34, 56, 11, 4, 71, 86, 55, 10, 39, 49, 52, 82, 31, 13, 22,35, 44, 20, 60, 28} obtain a hash table HT[0..8, 0..2] following quadratic probing.Make use of the hash function H(X) = X mod 9. What are your observations?
Chapter 27 Solutions
Introduction to Java Programming and Data Structures, Comprehensive Version (11th Edition)
Ch. 27.2 - Prob. 27.2.1CPCh. 27.3 - Prob. 27.3.1CPCh. 27.3 - Prob. 27.3.2CPCh. 27.3 - Prob. 27.3.3CPCh. 27.3 - Prob. 27.3.4CPCh. 27.3 - Prob. 27.3.5CPCh. 27.3 - Prob. 27.3.6CPCh. 27.3 - If N is an integer power of the power of 2, is N /...Ch. 27.3 - Prob. 27.3.8CPCh. 27.3 - Prob. 27.3.9CP
Ch. 27.4 - Prob. 27.4.1CPCh. 27.4 - Prob. 27.4.2CPCh. 27.4 - Prob. 27.4.3CPCh. 27.4 - Prob. 27.4.4CPCh. 27.4 - Prob. 27.4.5CPCh. 27.4 - Prob. 27.4.6CPCh. 27.5 - Prob. 27.5.1CPCh. 27.6 - Prob. 27.6.1CPCh. 27.6 - Prob. 27.6.2CPCh. 27.6 - Prob. 27.6.3CPCh. 27.7 - Prob. 27.7.1CPCh. 27.7 - What are the integers resulted from 32 1, 32 2,...Ch. 27.7 - Prob. 27.7.3CPCh. 27.7 - Describe how the put(key, value) method is...Ch. 27.7 - Prob. 27.7.5CPCh. 27.7 - Show the output of the following code:...Ch. 27.7 - If x is a negative int value, will x (N 1) be...Ch. 27.8 - Prob. 27.8.1CPCh. 27.8 - Prob. 27.8.2CPCh. 27.8 - Can lines 100103 in Listing 27.4 be removed?Ch. 27.8 - Prob. 27.8.4CPCh. 27 - Prob. 27.1PECh. 27 - Prob. 27.2PECh. 27 - (Modify MyHashMap with duplicate keys) Modify...Ch. 27 - Prob. 27.6PECh. 27 - Prob. 27.7PECh. 27 - Prob. 27.8PECh. 27 - Prob. 27.10PECh. 27 - Prob. 27.11PECh. 27 - (setToList) Write the following method that...Ch. 27 - (The Date class) Design a class named Date that...Ch. 27 - (The Point class) Design a class named Point that...
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- Using double hasing, insert the following keys: {333, 335, 123, 617, 93, 63, 17, 37} into a hash table of size 17 using k mod m as h1(k), and h2(k) = 8 - k mod 8 as the offset.arrow_forwardLet us consider an empty hash table with 10 positions indexed from 0 to 9. Please illustrate the content of the hash table after inserting the elements 79, 8, 39, 48, 3, and 60 using(1) Quadratic Probing (2) Double hashing with h(k) = k%10 and h’(k)= 7-k%7arrow_forwardDoes a hash table of size m contain the same number of linked lists at all times? No matter how hard I attempt, I cannot identify the purpose of a hash function. Provide an example to illustrate your point.arrow_forward
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