CAREY: ORGANIC CHEMISTRY
10th Edition
ISBN: 9781260364002
Author: VALUE EDITION
Publisher: MCG CUSTOM
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Chapter 27.5, Problem 9P
Interpretation Introduction
Interpretation:
The fact that whether
Concept introduction:
For a spontaneous reaction, the value of change in Gibb’s free energy or
The relation between
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3) Calculate the physiological AG for the reaction: Phosphocreatine + ADP - creatine + ATP at
25 °C as it occurs in the cytosol of neurons, in which phosphocreatine is present at 4.7 mM,
creatine at 1.0 mM, ADP at 0.20 mM, and ATP at 2.6 mM, knowing that Phosphocreatine + H20
- creatine + Pi AG° = -43 kJ/mol and ATP + H20 ADP + Pi AG = -30.5 kJ/mol
The second step in the catabolism of most amino acids is the removal of the nitrogen atom from glutamate by oxidative
deamination. In this reaction, glutamate is converted to an a-keto acid.
Modify the structure to show the a-keto acid product.
?-
||
с
I
CH₂
I
H₂N-
&
+ remaining products
enzyme
CH₂
I
CH₂
+ NAD+ + H₂O
CH₂
Incorrect
Enter the chemical formulas for the remaining products.
remaining products: NADH + H+ + NH
Identify the enzyme that catalyzes the reaction.
The enzyme that catalyzes the reaction is glutamate
dehydrogenase.
OH
OH
Assume that in a certain cell, the ratio of products/reactants or Keq = 747.1 (Keq is dimensionless) for the reaction Glucose + ATP <> Glucose-6-P + ADP, at a particular instant, the concentrations of each compound were Glucose =2.0M, ATP =7.7M, ADP =10.2M and G-6-P =21.5M. Calculate the difference (dimensionless) between Keq and the ratio of products/ractants at this instance, in this cell, to five significant figures.
Chapter 27 Solutions
CAREY: ORGANIC CHEMISTRY
Ch. 27.1 - Problem 27.1 Write a structural formula for the...Ch. 27.1 - Prob. 2PCh. 27.1 - Prob. 3PCh. 27.2 - Prob. 4PCh. 27.3 - Prob. 5PCh. 27.3 - Prob. 6PCh. 27.5 - Prob. 7PCh. 27.5 - Prob. 8PCh. 27.5 - Prob. 9PCh. 27.6 - Prob. 10P
Ch. 27.7 - Prob. 11PCh. 27.9 - Prob. 12PCh. 27.12 - 27.13 Modify Figure 27.12 so that it corresponds...Ch. 27.13 - Prob. 14PCh. 27 - Prob. 15PCh. 27 - Prob. 16PCh. 27 - Prob. 17PCh. 27 - Nebularine is a toxic nucleoside isolated from a...Ch. 27 - Prob. 19PCh. 27 - The 5-nucleotide of inosine, inosinic acid...Ch. 27 - Prob. 21PCh. 27 - (a) The two most acidic hydrogens of uracil have...Ch. 27 - The phosphorylation of -D-glucopyranose by ATP...Ch. 27 - When 6-chloropurine is heated with aqueous sodium...Ch. 27 - Prob. 25PCh. 27 - Prob. 26PCh. 27 - Prob. 27PCh. 27 - Prob. 28PCh. 27 - Oligonucleotide Synthesis In Section 27.6 we noted...Ch. 27 - Oligonucleotide Synthesis In Section 27.6 we noted...Ch. 27 - Oligonucleotide Synthesis In Section 27.6 we noted...Ch. 27 - Oligonucleotide Synthesis In Section 27.6 we noted...Ch. 27 - Oligonucleotide Synthesis In Section 27.6 we noted...Ch. 27 - Oligonucleotide Synthesis In Section 27.6 we noted...
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- Consider the following reaction: (P, is inorganic phosphate, i.e., HPO4² and H₂PO4) glucose + P + 3.3 kcal glucose-6-phosphate + H₂O If the energy used for the reaction is obtained from the hydrolysis of ATP (AH = -7.3 kcal.mol), the reaction will go to completion. Select one: O True O Falsearrow_forwardWhen the following reaction reached equilibrium the concentration of glucose 1-phosphate is 34mM, and the concentration of glucose 6-phosphate is 190mM. At standard temperatures and pressure, calculate the Keq and the ΔGo' glucose 6-phosphate <---(phosphoglucoisomerase)---> glucose 1-phosphate Keq= ΔGo' =arrow_forwardTPP is a coenzyme for transketolase, the enzyme that catalyzes the conversion of a ketopentose (xylulose- 5-phosphate) and an aldopentose (ribose-5-phosphate) to an aldotriose (glyceraldehyde-3-phosphate) anda ketoheptose (sedoheptulose-7-phosphate). Notice that the total number of carbons in the reactants and products is the same (5 + 5 = 3 + 7). Propose a mechanism for this reaction.arrow_forward
- At active muscle I. PCO2 is high II. acidity is low III. carbamate forms IV. hemoglobin is stabilized in the T state O lonly O II, III and IV O I and III O I, II, III and IV O I, III and IVarrow_forwardTPP is a coenzyme for transketolase, the enzyme that catalyzes the conversion of a ketopentose (xylulose5-phosphate) and an aldopentose (ribose-5-phosphate) to an aldotriose (glyceraldehyde-3-phosphate) and a ketoheptose (sedoheptulose-7-phosphate). Notice that the total number of carbons in the reactants and products is the same (5 + 5 = 3 + 7). Propose a mechanism for this reaction.arrow_forwardIntracellular concentrations in resting muscle are as follows: fructose- 6-phosphate, 1.0 mM; fructose-1,6-bisphosphate, 10 mM; AMP, 0.1 mM; ADP, 0.5 mM; ATP, 5 mM; and Pi, 10 mM. Is the phosphofructokinase reaction in muscle more or less exergonic than under standard conditions? By how much?arrow_forward
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