PRINT UPGRADE - COMPTIA A+ CORE 2 EXAM
10th Edition
ISBN: 9780357482971
Author: ANDREWS
Publisher: CENGAGE L
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Textbook Question
Chapter 3, Problem 10TC
THINKING CRITICALLY
If 2 bits of a byte are in error when the byte is read from ECC memory, can ECC detect the error? Can it fix the error?
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For the ROM diagram please fill the truth table
values using hexadecimal digits only. Output 3 is
the most significative bit. A3 is the most
significative address line.
mo
ml
m2
m3
m4
m5
m6
m8
m9
ml0
ml1
m12
m13
ml4
ml5
A, A, A, A,
°o
о, о, о, о,
Decoder
Using Emu8086, write an ALP that will print the sum
of two (2) variables X and Y to memory OB55H if
their values are equal; otherwise, it will print their
quotient to memory location DB5SH, Declare X and Y
to have the size 16 bits each.
Given the 12-bit Hamming code below, identify the correct 8-bit memory word it represents. You must show work.
0 1 1 0 1 1 0 0 1 1 0 1
Chapter 3 Solutions
PRINT UPGRADE - COMPTIA A+ CORE 2 EXAM
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- Suppose we want an error-correcting code that will allow all single-bit errors to be corrected for memory words of length 10. a. How many parity bits are necessary? b. Assuming we are using the Hamming algorithm presented in this chapter to design our error-correcting code and an odd parity , find the code word to present the 10-bit information word: 1 00 1 1 00 1 1 1 We now receive the following code word: C. 10 10 1 1 0 0 0 0 10 1 1 Is this a legal code word, assuming an odd parity? If not, what is the corrected code word? (Which bit is the error bit?)arrow_forwardCalculate the parity of a byte with the value 31 and show the pattern stored to memory. Assume the parity bit is on the right. Suppose the most significant bit was inverted in memory, and then you read it back. Did you detect the error? What happens if the two most significant bits are inverted?arrow_forwardA 12-bit Hamming code word containing 8 bits of data and 4 parity bits is read from memory. What was the original 8-bit data word that was written into memory if the 12-bit word read out is as follows:1. 0000111010102. 1011100001103. 101111110100arrow_forward
- A set of ten packed BCD numbers is stored in the memory location starting at 3050H. i. Write a program with a subroutine to add these numbers in BCD. If a carry is generated, save it in register B, and adjust it for BCD. The final sum will be less than 9999sCD. ii. Write a second subroutine to unpack the BCD sum stored in registers A and B, and store them in the memory locations starting at 3070H. The most significant digit (BCD4) should be stored at 3070H and the least significant digit (BCD) at 3073H.arrow_forwardPlease answer the following questions about RISC-V floating-point representation: a. Please represent the number -1.2356 ´ 108 using the 32-bit RISC-V format. b. What is the range (i.e., lower bound and upper bound) of floating-point numbers that the 32-bit RISC-V format can represent? What problems it will cause if the floating-point number we want to represent goes below the lower bound or above the upper bound? What would be a solution to such problems?arrow_forwardHow does the ALU handle signed and unsigned integer operations, and what are the implications of overflow?arrow_forward
- Parity is a function in which the output depends on the number of 1s in the input. For an even parity function, the output is 1 if the input has an even number of ones. Suppose a ROM is used to implement an even parity function with a 4-bit input. Which of A, B, C, or D represents the contents of the ROM?arrow_forwardSuppose we want an error-correcting code that will allow all single-bit errors to be corrected for memory words of length 10. 1. a) How many parity bits are necessary? 2. b) Assuming we are using the Hamming algorithm presented in this chapter to design our error-correcting code, find the code word to represent the 10-bit information word: 1 0 0 1 1 0 0 1 1 0.arrow_forwardExplain the significance of "carry-in" and "carry-out" in ALU arithmetic operations.arrow_forward
- Create a MIPS programme that calculates the Hamming ECC code for an 8-bit byte. 8-bit positive numbers are easier to deal with than bigger ones, so your programmes function for them. The programme requests a byte of data (a positive number from 0 to 255 in decimal) and creates the 12-bit Hamming code. The programme then outputs hex with a label.arrow_forward5. Suppose we want an error-correcting code that will allow all single-bit errors to be corrected for memory words of length 10. a. How many parity bits are necessary? b. Assuming we are using the Hamming algorithm presented in this chapter to design our error-correcting code and an odd parity, find the code word to present the 10-bit information word: 1 0 0 1 1 0 0 1 1 1arrow_forwardy of H Q. For the given circuit, which of the following is correct? E OF RAM 256 X 4 A. The number 5 is being written to the memory at address location 203. B. The chip has not been enabled, since the EN terminal is 0; therefore, nothing will be written to the chip and the output is tri- 1 A0 1 A1 O A2 O A3 1 A4 A 255 O A5 1 A6 1 A7 71 QO stated. O DO 1 D1 O D2 1 D3 C. Decimal 10 is being written into memory location 211. D. The read/write line is LOW; therefore, WRITE decimal 5 is being stored at memory O R/W O CS READ EN location 211. Data inputs Address inputs DDDD Data outputsarrow_forward
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