Concept explainers
(a)
Interpretation:
(a)
Explanation of Solution
Given,
Molar Mass of
Hence,
Balanced equation is given below,
Two moles of cobalt reacts with eight moles of carbon monoxide gives one mole of dicobalt octacarbonyl.
Mass in grams of dicobalt octacarbonyl is calculated as follows,
According to the gram calculation, cobalt is limiting reagent, therefore the gram of cobalt is calculated as follows,
The mass (g) of dicobalt octacarbonyl is
(b)
Interpretation:
The additional mass of the limiting reactant that is needed to react completely with the residual excess reactant has to be calculated.
(b)
Explanation of Solution
Given,
Molar Mass of
Assuming that the carbon monoxide in the final product is the only carbon monoxide used.
Mass in grams of dicobalt octacarbonyl is calculated as follows,
Excess CO is calculated as follows,
Balanced equation is given below,
Two moles of cobalt reacts with eight moles of carbon monoxide gives one mole of dicobalt octacarbonyl.
Grams of cobalt is calculated for reaction of excess carbon monoxide is given below,
Therefore,
(c)
Interpretation:
Total mass of dicobalt octacarbonyl produced from subpart (a) and (b) has as to be calculated.
(c)
Explanation of Solution
Given,
Molar Mass of
Balanced equation is given below,
Two moles of cobalt reacts with eight moles of carbon monoxide gives one mole of dicobalt octacarbonyl.
Mass in grams of dicobalt octacarbonyl is calculated as follows,
Therefore the total gram of dicobalt octacarbonyl is calculated as follows,
Total mass of dicobalt octacarbonyl produced is
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Chapter 3 Solutions
EBK CHEMISTRY: THE MOLECULAR SCIENCE
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