PROGRAMMABLE LOGIC CONTROLLERS (LOOSE PA
5th Edition
ISBN: 9781264206216
Author: Petruzella
Publisher: MCG
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Question
Chapter 3, Problem 16RQ
Program Plan Intro
a.
Addition of two binary numbers:
Binary addition is performed as given below.
Explanation of Solution
b.
Adding 101 to 011:
- Here, it is given that the binary number 101 must be added with the binary number 011.
- It is performed as given below.
Explanation of Solution
c.
Adding 1100 to 1011:
- Here, it is given that the binary number 1100 must be added with the binary number 1011.
- It is performed as given below.
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Students have asked these similar questions
The Decimal equivalent of the Binary number
(01110.1010 ), is
a. (14.625),
10
b. (12.15)10
c. (74.365),
10
d. (9.68),
10
Convert the value of the following binary numbers to hexadecimal notation
a. 11012
b. 111011102
Express the following octal number in decimal (743.50)
Select one:
a. 48.62
b. 483.625
c. 48.2
d. 1E3.A
Chapter 3 Solutions
PROGRAMMABLE LOGIC CONTROLLERS (LOOSE PA
Ch. 3 - Prob. 1RQCh. 3 - Convert each of the following decimal numbers to...Ch. 3 - Prob. 3RQCh. 3 - Prob. 4RQCh. 3 - Prob. 5RQCh. 3 - Prob. 6RQCh. 3 - Prob. 7RQCh. 3 - Prob. 8RQCh. 3 - Prob. 9RQCh. 3 - Prob. 10RQ
Ch. 3 - Prob. 11RQCh. 3 - Define the term sign bit.Ch. 3 - Prob. 13RQCh. 3 - Prob. 14RQCh. 3 - Prob. 15RQCh. 3 - Prob. 16RQCh. 3 - Prob. 17RQCh. 3 - Prob. 18RQCh. 3 - Prob. 19RQCh. 3 - Prob. 1PCh. 3 - Prob. 2PCh. 3 - Prob. 3PCh. 3 - Prob. 4PCh. 3 - Prob. 5PCh. 3 - Prob. 6PCh. 3 - Prob. 7PCh. 3 - Prob. 8PCh. 3 - Prob. 9PCh. 3 - Prob. 10P
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Similar questions
- A(n) __________ is an integer stored in double the normal number of bit positions.arrow_forwardConvert this decimal number to octal and binary numbers: a. 76 b. 32 c. 20 d. 359arrow_forwardExpress the following binary number in decimal (1100110.110) Select one: a. 102.375 b. 100.5 c. 822 d. 102.75arrow_forward
- Examples 1: Convert following binary numbers to decimal numbers:arrow_forwardConvert the following binary numbers to decimal numbers.(a) 1011(b) 11011010(c) 01001011(d) 10110100arrow_forwardConvert the following binary numbers tohexadecimal and base 10:a. 1111 b. 1001101 c. 1100101 d. 1011100e. 11101 f. 101000arrow_forward
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