Concept explainers
Videos
(a)
To identify an action-reaction pair of forces.
(a)
Answer to Problem 1Q
The force the person exerts on the wall and the force the wall exerts on the person is an action-reaction pair.
Explanation of Solution
Action – reaction pair of forces always acts on separate object.
When a person pushes on a wall, the wall pushes back on the person. Here the person exerts force on the wall and wall in turn exerts force on the person. The force exerted by the person on the wall is equal in magnitude and opposite in direction to the force exerted by the wall on the person and they acts on different objects.
Conclusion:
Therefore, the force the person exerts on the wall and the force the wall exerts on the person is an action-reaction pair.
(b)
To identify an action-reaction pair of forces, book resting on the table.
(b)
Answer to Problem 1Q
The gravitational force exerted the book on the table and the normal force exerted by the table on the book is action-reaction pair force.
Explanation of Solution
The gravitational force exerted by the book on the table and the normal force exerted by the table on the book is action-reaction pair force and they acts on different objects. The gravitational force exerted by the book on the table is equal in magnitude and opposite in direction to the force exerted by the table on the book.
Conclusion:
Therefore, the gravitational force exerted the book on the table and the normal force exerted by the table on the book is action-reaction pair force.
(c)
To identify an action-reaction pair of forces, a hockey puck sliding across an icy surface.
(c)
Answer to Problem 1Q
The
Explanation of Solution
The frictional force exerted by the moving hockey puck on the ice and the frictional force exerted by the ice on the hockey puck is action-reaction pair force and they acts on different objects. The frictional force exerted by the moving hockey puck on the ice is equal in magnitude and opposite in direction to the frictional force exerted by the ice on the hockey puck.
Conclusion:
Therefore, the frictional force exerted by the moving hockey puck on the ice and the frictional force exerted by the ice on the hockey puck is action-reaction pair force.
(d)
To identify an action-reaction pair of forces, a car accelerating from rest.
(d)
Answer to Problem 1Q
The frictional force exerted by the tire on the road and the force exerted by the road on the tire is action-reaction pair force.
Explanation of Solution
The frictional force exerted by the tire on the road and the force exerted by the road on the tire is action-reaction pair force and they acts on different objects. The frictional force exerted by the rotating tire on the road is equal in magnitude and opposite in direction to the frictional force exerted by the road on the tire.
Conclusion:
Therefore, the frictional force exerted by the tire on the road and the force exerted by the road on the tire is action-reaction pair force.
(e)
To identify an action-reaction pair of forces, an object undergoing free fall in a vacuum.
(e)
Answer to Problem 1Q
The gravitational force exerted on the object by the object on which the object is falling and gravitational force on the falling object on which the object is falling is an action-reaction pair.
Explanation of Solution
The gravitational force exerted on the object by the object on which the object is falling is equal in magnitude and opposite in direction to gravitational force on the falling object on which the object is falling is an action-reaction pair and they acts on different objects.
Conclusion:
Therefore, the gravitational force exerted on the object by the object on which the object is falling and gravitational force on the falling object on which the object is falling is an action-reaction pair.
(f)
To identify an action-reaction pair of forces, a basketball player jumping to dunk a basketball.
(f)
Answer to Problem 1Q
The force exerted by the basketball player against the floor and the force the floor exerts on the basket ball are action-reaction pairs.
Explanation of Solution
The force exerted by the basketball player against the floor while he dunks the ball and the force the floor exerts on the basket ball are equal in magnitude and opposite in direction and they acts on different objects. The force exerted by the basketball player against the floor while and the force the floor exerts on the basket ball are action-reaction pairs.
Conclusion:
Therefore, the force exerted by the basketball player against the floor while and the force the floor exerts on the basket ball are action-reaction pairs.
(g)
To identify an action-reaction pair of forces, a person throwing a baseball.
(g)
Answer to Problem 1Q
The force the person exerts against the basket ball to accelerate it and the force the basketball exerts on the person is action-reaction pair.
Explanation of Solution
The force the person exerts against the basket ball to accelerate it and the force the basketball exerts on the person is equal in magnitude and opposite in direction and they acts on different objects. The force the person exerts against the basket ball to accelerate it and the force the basketball exerts on the person is action-reaction pair.
Conclusion:
Therefore, the force the person exerts against the basket ball to accelerate it and the force the basketball exerts on the person is action-reaction pair.
Want to see more full solutions like this?
Chapter 3 Solutions
College Physics
- Which of the following statements is most correct? (a) It is possible for an object to have motion in the absence of forces on the object. (b) It is possible to have forces on an object in the absence of motion of the object. (c) Neither statement (a) nor statement (b) is correct. (d) Both statements (a) and (b) are correct.arrow_forwardDoes the ground need to exert a force on you for you to jump off the ground, or do you need to exert a force on the ground? If the ground must exert a force on you, is that force greater than the force you exert on the ground?arrow_forwardTwo blocks of mass 3.50 kg and 8.00 kg are connected by a massless string that passes over a frictionless pulley (Fig. P4.47). The inclines are frictionless. Find (a) the magnitude of the acceleration of each block and (b) the tension in the string. Figure P4.47arrow_forward
- Two people, one of mass 100 kg and the other of mass 50 kg, stand facing each other on an ice-covered (essentially frictionless) pond. If the heavier person pushes on the lighter one with a force F, thenA. the force felt by the heavier person is (-1/2)FB. the force felt by the person is -2FC. the magnitude of the acceleration of the lighter person will be half of the magnitude of the acceleration of the heavier personD. the magnitude of the acceleration of the lighter person will be twice the magnitude of the acceleration of the heavier personwww.crackap.com---------------------arrow_forwardWhich of the following statements describing forces is NOT TRUE? A. Forces always cause objects to move. B. A net force causes objects to accelerate. C. Balanced force cause objects to remain at rest or move at constant velocity. D. Forces can change the direction of an object without changing its speed.arrow_forwardAn object with a mass of 7.5 kg accelerates 8.3 m/s2 when an unknown force is applied to it. What is the amount of the force? An object with a mass of 2000 g accelerates 8.3 m/s2 when an unknown force is applied to it. What is the amount of the forcearrow_forward
- Which is true of the force pair of Newton's third law? a. The two forces never produce an acceleration. b. The two forces act on different objects. c. The two forces always cancel each other. d. The two forces are in the same direction.arrow_forwardSketch (either by hand or on a computer) the scenario of a book sitting on a table. Draw arrows representing the relevant forces on the sketch and an additional arrow showing the acceleration if necessary. Sketch (either by hand or on a computer) the scenario of a man pushing a box across a frictionless floor. Draw arrows representing the relevant forces on the sketch and an additional arrow showing the acceleration if necessary. Sketch (either by hand or on a computer) the scenario of air inside and outside of a balloon. Draw arrows representing the relevant forces on the sketch if necessary. Thanks!arrow_forwardA panda of mass 45 kg is climbing up a vine that can bear a maximum tension of 640 N. Identify in which of the following cases will the vine break: ( a ) panda accelerates up at 5 m/s2 ( b ) panda accelerates down at 5 m/s2arrow_forward
- A freight train consists of two 8.00x104 kg engines and 45 cars with average masses of 5.50x104 kg. What force must each engine exert backward on the track to accelerate the train at a rate of 5.00x10-2 m/s2 if the force of friction is 7.50x105 N, assuming the engines exert identical forces? Group of answer choices 882 kN 441 kN 221 kN 110 kNarrow_forwardA boat moving with a velocity of 10m/s, towards west is acted upon by a pair of balanced forces. Which of the following statements is true? a. The boat continues to travel westward with a velocity 10m/s b. The speed of the boat decreases gradually and comes ton a stop c. The speed of the boat gradually increases d. The boat travels with an acceleration of -9.8 m/s2arrow_forwardA man is standing in a room with a low ceiling. He has raised his arms and pushing against the ceiling with a force of 400 N. His mass is 89 kg. What force (in kN) does the floor exert on him?arrow_forward
Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
College PhysicsPhysicsISBN:9781285737027Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning
Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage Learning