Concept explainers
Write an unbalanced equation to represent each of the following reactions: (a) potassium hydroxide and phosphoric acid react to form potassium phosphate and water; (b) zinc and silver chloride react to form zinc chloride and silver; (c) sodium hydrogen carbonate reacts to form sodium carbonate, water, and carbon dioxide; (d) ammonium nitrite reacts to form nitrogen and water; and (e) carbon dioxide and potassium hydroxide react to form potassium carbonate and water. (0 Balance equations (a)-(e).
Interpretation: An unbalanced equation that represents each of the given reactions and the balanced chemical equation for the same given reactions are to be written.
Concept introduction:
A chemical reaction uses a symbol to describe what occurs in a particular chemical reaction.
A chemical statement is represented in a chemical reaction.
Answer to Problem 21QP
Solution: a)
b)
c)
d)
e)
f)
And
Explanation of Solution
a)Potassium hydroxide and phosphoric acid react to form potassium phosphate and water.
Potassium hydroxide is represented as
b) Zinc and silver chloride react to form zinc chloride and silver.
Zinc is represented by the symbol
c) Sodium hydrogen carbonate reacts to form sodium carbonate, water, and carbon dioxide.
Sodium hydrogen carbonate is represented as
d) Ammonium nitrate reacts to form nitrogen and water.
Ammonium nitrate is represented as
e) Carbon dioxide and potassium hydroxide react to form potassium carbonate and water.
Carbon dioxide is represented as
f) Balance all above equation
Balancing of chemical reactions is done on the basis of “The Law of Conservation of Mass.” The balanced equation representing the given reactions are as follows:
The equation of part (a) is as follows:
As a first step, add a coefficient of 3 in front of potassium on the reactant side.
Now, add acoefficient of 3 in front of hydrogen on the product side.
Thus,
Hence, the first equation is balanced.
Now, the equation of part (b) is as follows:
As a first step, add a coefficient of 2 in front of
Now, add acoefficient of 2 in front of
Thus,
Hence, the second equation is balanced.
Now, the equation of part (c) is as follows:
As a first step, add a coefficient of 2 in front of
Thus,
Hence, the third equation is balanced.
Now, the equation of part (d) is as follows:
As a first step, add a coefficient of 2 in front of
Thus,
Hence, the fourth equation is balanced.
Now, the equation of part (e) is as follows:
As a first step, add a coefficient of 2 in front of
Thus,
Hence, the fifth equation is balanced.
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Chapter 3 Solutions
Aleks 360 Access Card 1 Semester For Introductory Chemistry
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