Show that lim x → π / 3 sin ( x − π / 3 ) 4 cos 2 x − 1 = − 3 6 . Do this by first creating a vector x that has the elements π / 3 − 0. 1 , π / 3 − 0.000 1 , π / 3 + 0.000 1 , π / 3 + 0.0 1 , and π / 3 + 0. 1 . Then, create a new vector y in which each element is determine from the elements of x by sin ( x − π / 3 ) 4 cos 2 x − 1 . Comoare the elementd of y with the value − 3 6 . Use formatlong to display the numbers.
Show that lim x → π / 3 sin ( x − π / 3 ) 4 cos 2 x − 1 = − 3 6 . Do this by first creating a vector x that has the elements π / 3 − 0. 1 , π / 3 − 0.000 1 , π / 3 + 0.000 1 , π / 3 + 0.0 1 , and π / 3 + 0. 1 . Then, create a new vector y in which each element is determine from the elements of x by sin ( x − π / 3 ) 4 cos 2 x − 1 . Comoare the elementd of y with the value − 3 6 . Use formatlong to display the numbers.
Show that
lim
x
→
π
/
3
sin
(
x
−
π
/
3
)
4
cos
2
x
−
1
=
−
3
6
. Do this by first creating a vectorx that has the elements
π
/
3
−
0.
1
,
π
/
3
−
0.000
1
,
π
/
3
+
0.000
1
,
π
/
3
+
0.0
1
, and
π
/
3
+
0.
1
. Then, create a new vector y in which each element is determine from the elements of x by
sin
(
x
−
π
/
3
)
4
cos
2
x
−
1
. Comoare the elementd of y with the value
−
3
6
. Use formatlong to display the numbers.
Quantities that have magnitude and direction but not position. Some examples of vectors are velocity, displacement, acceleration, and force. They are sometimes called Euclidean or spatial vectors.
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