Pearson eText Genetic Analysis: An Integrated Approach -- Instant Access (Pearson+)
3rd Edition
ISBN: 9780135564172
Author: Mark Sanders, John Bowman
Publisher: PEARSON+
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Textbook Question
Chapter 3, Problem 29P
A wild-type Drosophila male and female are crossed, producing 324 female progeny and 161 male progeny. All their progeny are wild type.
a. Propose a genetic hypothesis to explain these data.
b. Design an experiment that will test your hypothesis, using the wild-type progeny identified above. Describe the results you expect if your hypothesis is true.
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Some sweet-pea plants have purple flowers and others have white flowers. A homozygous variety of sweet pea that has purple flowers is crossed with a homozygous variety that has white flowers. All the F1 have purple flowers. When these F1 self-fertilize, the F2 appear in a ratio of 916 purple to 716 white. a. Give genotypes for the purple and white flowers in these crosses. b. Draw a hypothetical biochemical pathway to explain the production of purple and white flowers in sweet peas
Drosophila females heterozygous for three recessive mutations, a, b, and c , were crossed to males homozygous for all three mutations.The cross yielded the following results:
in the image
Q. Construct a linkage map showing the correct order of these genes and estimate the distances between them.
The fruit fly, Drosophila melanogaster, a vestigial female fly is mated to a male that is scarlet eyes and bristled. Phenotypically wild type F1 female progeny were mated to fully homozygous (mutant) males, and the following progeny (of 1000 total) were observed (shown on table)
a. Which gene is in the middle?
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Chapter 3 Solutions
Pearson eText Genetic Analysis: An Integrated Approach -- Instant Access (Pearson+)
Ch. 3 - Examine the following diagrams of cells from an...Ch. 3 - Our closest primate relative, the chimpanzee, has...Ch. 3 -
3. In a test of his chromosome theory of...Ch. 3 - Cohesion between sister chromatids, as well as...Ch. 3 - 5. The diploid number of the hypothetical animal...Ch. 3 - 6. An organism has alleles R1 and R2 on one pair...Ch. 3 - Explain how the behavior of homologous chromosomes...Ch. 3 - 8. Suppose crossover occurs between the homologous...Ch. 3 -
9. Alleles A and a are on one pair of autosomes,...Ch. 3 - Prob. 10P
Ch. 3 - Describe the role of the following structures or...Ch. 3 - A womans father has ornithine transcarbamylase...Ch. 3 - In humans, hemophilia A (OMIM 306700) is an...Ch. 3 -
14. A wild-type male and a wild-type female...Ch. 3 - 15. A woman with severe discoloration of her tooth...Ch. 3 - 16. In a large metropolitan hospital, cells from...Ch. 3 - In cats, tortoiseshell coat color appears in...Ch. 3 - 18. The gene causing Coffin–Lowry syndrome (OMIM...Ch. 3 - 19. Four eye-color mutants in Drosophila—apricot,...Ch. 3 - 20. For each pedigree shown,
a. Identify which...Ch. 3 - 21. Use the blank pedigrees provided to depict...Ch. 3 - 22. Figure 3.22 (page 89) illustrates reciprocal...Ch. 3 - 23. In fruit flies, yellow body (y) is recessive...Ch. 3 - 24. In a species of fish, a black spot on the...Ch. 3 - LeschNyhan syndrome (OMIM 300322) is a rare...Ch. 3 - 26. In humans, SRY is located near a...Ch. 3 - 27. In an 1889 book titled Natural Inheritance...Ch. 3 - 28. In Drosophila, the X-linked echinus eye...Ch. 3 - 29. A wild-type Drosophila male and female are...Ch. 3 - 30. Drosophila has a diploid chromosome number of...Ch. 3 - The cell cycle operates in the same way in all...Ch. 3 - 33. Form a small discussion group and decide on...Ch. 3 - 34. Duchenne muscular dystrophy (DMD; OMIM 310200)...Ch. 3 - Prob. 35P
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- Consider the first category of test-cross offspring shown in figure 8.2 (+b, LS). Consider also that the parents of the heterozygous female flies in the test cross had the following genotypes: bb, SS, and +, LL. A. What would be the physical phenotype of these flies? B. If PC was conducted with the DNA of one of these flies using the primers for the molecular marker, what would be the appearance of the bands on an electrophoresis gel with the PC products? C. If the gene for black body and the locus for the molecular marker (L long or S short) were unlinked, what proportion of the test-cross progeny would be black flies that are heterozygous for the molecular marker? What proportion would be flies with normal body color, which are homozygous for one form of the molecular marker? D. If the gene for black body and the locus for the molecular marker were linked, how would the proportion of flies be different?arrow_forwardThe data set attached summarizes F2 numbers from an F1 cross arising from two, true-breeding Drosophila strains (P generation), which differ with respect to two mutant traits. Here are the hypothesis: Leg length - The wild-type and mutant alleles for leg length are incomplete dominant relative to each other. Justification: The data set includes three phenotypic categories for leg length: wild type (long leg), medium leg, and truncated wings. The presence of three distinct phenotypes suggests an incomplete dominance pattern, where the heterozygous individuals exhibit an intermediate leg length phenotype (medium leg). The absence of purebred short-legged individuals supports the idea that the long leg allele is dominant over the short leg allele. This shows that mode of inheritance is incomplete dominance of the alleles relative to each other. Since the data does not mention any specific differences between males and females, we can assume that the mode of inheritance for the trait is…arrow_forwardConsider two maize plants:a. Genotype C/c m ; Ac/Ac+, where cm is an unstable allele caused by a Ds insertionb. Genotype C/c m, where cm is an unstable allele caused by Ac insertionWhat phenotypes would be produced and in what proportions when (1) each plant is crossed with a basepair-substitution mutant c/c and (2) the plant in part a is crossed with the plant in part b? Assume that Ac and c are unlinked, that the chromosome-breakage frequency is negligible, and that mutant c /C is Ac+.arrow_forward
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- Please explain how you do this question step by step I am very confused! thank you:) You have three independent mutant alleles in the Drosophila gene no-antenna: nan1, nan2 and nan3. You determine the phenotype of Drosophila that are heterozygous for the three alleles (heterozygous for a wild-type allele and a mutant allele), and that are homozygous for the three mutant alleles. The antenna is composed of three segments that are followed at the distal end by a feathery arista (that is the antenna is composed of three segments and an arista). Allele nan1 nan2 nan3 heterozygous Wild-type No arista Wild-type homozygous No arista No antenna No antenna nan1 is a __x__ allele, nan2 is a __y__ allele, and nan3 is a __z__ allele. X Y Z A Dominant negative Null Hypomorphic B Null Dominant negative Hypomorphic C Null Hypomorphic Dominant negative D Hypomorphic Dominant negative Null E Dominant negative Hypomorphic Null Referencing the table above, select the…arrow_forwardKernel color in wheat Red kernel color in wheat results from the interaction between two dominant alleles. With only one dominant allele, the phenotype is brown while in the absence of any dominant allele, the phenotype is white. Suppose that plants of a variety that is true breeding for red kernels are crossed with plants true breeding for white kernels. What specific type of interaction can be observed? A. duplicate dominant genes B. duplicate genes with cumulative effects C. complementary genes D. dominant epistasis (case 2)arrow_forwardSome sweet-pea plants have purple flowers and others have white flowers. A homozygous variety of sweet pea that has purple flowers is crossed with a homozygous variety that has white flowers. All the F1have purple flowers. When these F1 self-fertilize, the F2 appear in a ratio of 916 purple to 716 white. a.Draw a hypothetical biochemical pathway to explain the production of purple and white flowers in sweet peas.arrow_forward
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