EBK BASIC BIOMECHANICS
7th Edition
ISBN: 9780100409453
Author: Hall
Publisher: YUZU
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Textbook Question
Chapter 3, Problem 2AP
Gravitational force on planet X is 40% of that found on the earth. If a person weighs 667.5 N on the earth, what is the person’s weight on planet X? What is the person’s mass on the earth and on planet X? (Answer: weight on planet X = 267 N; mass = 68 kg on either planet)
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Chapter 3 Solutions
EBK BASIC BIOMECHANICS
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- Give an interpretation for the following graph:arrow_forwardThe above computation of gravitational force between two celestial objects (like Earth and the moon) is based on which equation? (V1)(P1) = (V2)(P2) F = GM1M2/d2 (years)2 = (A.U.)3 vm = ½ (vo + vf) S = vot + ½ (a) t2arrow_forwardAccording to Jean Buridan’s equation, the momentum or “impetus” of an 8 kilogram mass moving at 48 meters per second would be: 192 kilogram-meters per second 384 kilogram-meters per second 576 kilogram-meters per second 768 kilogram-meters per second 960 kilogram-meters per secondarrow_forward
- The momentum or “impetus” of a 12 kilogram mass moving at 7 meters per second can be stopped completely by a direct collision with a 3-kilogram mass moving at a velocity of: 14 meters per second 28 meters per second 36 meters per second 63 meters per second 84 meters per secondarrow_forwardBased on the acceleration in the above ball rolling down an inclined plane (with vo = 0 meters per second), how far would it have traveled along the inclined plane in the first six seconds of rolling? 9 meters 16 meters 25 meters 36 meters 49 metersarrow_forwardWhat was the momentum or “impetus” of the above moving object before its collision? 252 kilogram-meters per second 168 kilogram-meters per second 120 kilogram-meters per second 84 kilogram-meters per second 28 kilogram-meters per secondarrow_forward
- When Galileo Galilei rolled a ball down an inclined plane, it traveled 1.0 meters in the first second, and a total of 4.0 meters in the first two seconds. What was its acceleration on this inclined plane? 2.0 meters per second2 3.0 meters per second2 4.0 meters per second2 5.0 meters per second2 6.0 meters per second2arrow_forwardThe above computation of momentum (the term used by Isaac Newton), or “impetus” (the term used by Jean Buridan), is based on which of the following equations? (mass1)(velocity1) = (mass2)(velocity2) F = GM1M2/d2 (years)2 = (A.U.)3 vm = ½ (vo + vf)arrow_forwarda toy car rolls 10 meters (m) across the floor. it takes 5 seconds (s) to cross this distance. what is the speed of this car?arrow_forward
- Using the above “mean-speed theorem”, calculate the average velocity of a car with constant acceleration from 0 km/hour (initial speed) to 80 km/hour (final speed) over a 5-minute period of time. average velocity over 5 minutes = 16 kilometers/hour average velocity over 5 minutes = 20 kilometers/hour average velocity over 5 minutes = 24 kilometers/hour average velocity over 5 minutes = 32 kilometers/hour average velocity over 5 minutes = 40 kilometers/hourarrow_forwardThe “mean-speed theorem” for calculating average velocity under constant acceleration, developed by Thomas Bradwardine and the Mertonian Calculators at Oxford University, is expressed algebraically as: density = weight/volume (m1)(v1) = (m2)(v2) C. (vm) = 1/2 (v0 + vf) s = (v0)(t) + 1/2 (a)(t2) velocity = distance/timearrow_forwardThe “mean-speed theorem” for finding average velocity under constant acceleration, proposed by the Oxford Calculators, and demonstrated geometrically by Nicole Oresme, is expressed algebraically as: density = weight/volume (m1)(v1) = (m2)(v2) (vm) = 1/2 (v0 + vf) s = (v0)(t) + 1/2 (a)(t2) velocity = distance/timearrow_forward
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