PHYSICS OF EVERYDAY PHEN (LL)
PHYSICS OF EVERYDAY PHEN (LL)
9th Edition
ISBN: 9781260729214
Author: Griffith
Publisher: MCG
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Textbook Question
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Chapter 3, Problem 2SP

Two balls are released simultaneously from the top of a tall building. Ball A is simply dropped with no initial velocity, and ball B is thrown downward with an initial velocity of 15 m/s.

  1. a. What are the velocities of the two balls 1.3 seconds after they are released?
  2. b. How far has each ball dropped in 1.3 seconds?
  3. c. Does the difference in the velocities of the two balls change at any time after their release? Explain.

(a)

Expert Solution
Check Mark
To determine

The velocities of the two balls 1.3s after they are released.

Answer to Problem 2SP

The velocities of the two balls A and B 1.3s after they are released are 13m/s and 28m/s respectively.

Explanation of Solution

Given Info: A ball is thrown downward with initial velocity 15m/s and another is dropped with no initial velocity.

Write the expression for the final velocity.

v=v0+gt

Here,

v is the final velocity

v0 is the initial velocity

t is the time

g is the acceleration due to gravity

For the ball with the initial velocity, substitute 15m/s for v0, 10m/s2 for g and 1.3s for t to get v.

v=(15m/s)+(10m/s2)(1.3s)=28m/s

For the ball starting from rest, substitute 0m/s for v0, 10m/s2 for g and 1.3s for t to get v.

v=(0m/s)+(10m/s2)(1.3s)=13m/s

Conclusion:

Thus, the velocities of the two balls A and B 1.3s after they are released are 13m/s and 28m/s respectively.

(b)

Expert Solution
Check Mark
To determine

The distance each ball has dropped in 1.3s.

Answer to Problem 2SP

The distance each ball A and B has dropped in 1.3s are 8.45m and 11.05m respectively.

Explanation of Solution

Given Info: A ball is thrown downward with initial velocity 15m/s and another is dropped with no initial velocity.

Write the expression for the distance travelled.

d=v0t+12gt2

Here,

d is the distance travelled

For the ball with the initial velocity, substitute 15m/s for v0, 10m/s2 for g and 1.3s for t to get d.

d=(15m/s)(1.3s)+12(10m/s2)(1.3s)2=11.05m

For the ball starting from rest, substitute 0m/s for v0, 10m/s2 for g and 1.3s for t to get d.

d=(0m/s)(1.3s)+12(10m/s2)(1.3s)2=8.45m

Conclusion:

Thus, the distance each ball A and B has dropped in 1.3s are 8.45m and 11.05m respectively.

(c)

Expert Solution
Check Mark
To determine

Whether the difference in the velocities of the two balls change at any time.

Answer to Problem 2SP

The difference in the velocities of the two balls does not change at any time as it is given by the initial velocity of the balls.

Explanation of Solution

Write the expression for the final velocity.

v=v0+gt

This equation gives the final velocity of the balls. The difference in the velocity is given by the initial velocity as the change is usually the acceleration due to gravity multiplied by the time which is the same for both the balls. Thus the difference is only in the initial velocity of the ball which is also a constant value and therefore, does not change at any time.

Conclusion:

Thus, the difference in the velocities of the two balls does not change at any time as it is given by the initial velocity of the balls.

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Chapter 3 Solutions

PHYSICS OF EVERYDAY PHEN (LL)

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