Principles of Foundation Engineering (MindTap Course List)
8th Edition
ISBN: 9781305081550
Author: Braja M. Das
Publisher: Cengage Learning
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Question
Chapter 3, Problem 3.24P
(a)
To determine
Find the coefficient of at-rest earth pressure
(b)
To determine
Find the over consolidation ratio
(c)
To determine
Find the modulus of elasticity
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A dilatometer test was conducted in a clay deposit. The groundwater table was located at a depth of 3 m below the surface. At a depth of 8 m below the surface, the contact pressure was and the expansion stress was 350 kN/m2Determine the following:a. Coefficient of at-rest earth pressure,b. Overconsolidation ratio, OCRc. Modulus of elasticity,Assume stress at a depth of 8 m to be and 95 kN/m2 , poisson ratio=0.35.
A dilatometer test (DMT) was conducted in a clay deposit. The water table was located at a depth of 3 mbelow theground surface. At 8 m depth the contact pressure (p1) was 280 kPa and the expansion stress (p2) was 350 kPa.Assume σo = 95 kPa at the 8 m depth and μ = 0.35. Determine (a) Coefficient of at-rest earth pressure Ko,(b) Overconsolidation ratio OCR and (c) Modulus of elasticity Es.
A triaxial test conducted on cohesionless soil gives the following results:
Deviator stress at failure = 410kPa
The angle of shearing resistance = 32 degrees
Determine the following:
a. Confining pressure in kPa
b. Shear stress at failure plane in kPa
c. Angle that the failure plane makes with the principal plane (degrees)
Chapter 3 Solutions
Principles of Foundation Engineering (MindTap Course List)
Ch. 3 - Prob. 3.1PCh. 3 - Prob. 3.2PCh. 3 - Refer to Figure P3.3. Use Eqs. (3.10) and (3.11)...Ch. 3 - Prob. 3.4PCh. 3 - Prob. 3.5PCh. 3 - Prob. 3.6PCh. 3 - Prob. 3.7PCh. 3 - Prob. 3.8PCh. 3 - Prob. 3.9PCh. 3 - Prob. 3.10P
Ch. 3 - Prob. 3.11PCh. 3 - Following are the standard penetration numbers...Ch. 3 - Prob. 3.13PCh. 3 - Prob. 3.14PCh. 3 - Prob. 3.15PCh. 3 - Prob. 3.16PCh. 3 - Prob. 3.17PCh. 3 - Prob. 3.18PCh. 3 - Prob. 3.19PCh. 3 - Prob. 3.20PCh. 3 - Prob. 3.21PCh. 3 - Prob. 3.22PCh. 3 - Prob. 3.23PCh. 3 - Prob. 3.24PCh. 3 - Prob. 3.25PCh. 3 - Prob. 3.26PCh. 3 - Prob. 3.27P
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- A sample of soil is subjected to direct shear testing at its normal water content. Two test are performed. For one of the test, the sample fails at a shear stress of 144 KN/m2 when the normal stress is 192 KN/m2. In the second test, the sample shears at a stress of 168 KN/m2 when the normal stress is 239.4 KN/m2. From these data, Calculate the following:a) Angle of internal frictionb) Cohesion of soilc) Shearing resistance of the soil at a depth of 3600 mm if it has a unit weight of 16.4 KN/m3.arrow_forward1.A dry sand is known to have an angle of internal friction of 29. A triaxial test is planned, where the confining pressure will be 41 kPa. What is the maximum axial stress, in kPa, (major principal stress) that can be applied? Calculate the value to 1 decimal place. Do not provide units in your answer. 2.A clay soil is subjected to a triaxial test under unconsolidated-undrained conditions. At failure, the major and minor principal stresses are 8401 psf and 4875 psf, respectively. What is the shear strength of this soil if the confining pressure is doubled? Provide your answer in psf with no decimals.arrow_forwardA cylindrical sample of soil having a cohesion of 80 kN/m2 and an angle of internal friction of 20° is subjected to a cell pressure of 100 kN/m2. Determine: c. Determine the normal stress kn Kpa at the failure planearrow_forward
- In a drained triaxial test on consolidated clay the stress and angle are as follows : Deviator stress is 20 lb/in2 and friction angle 210 . calculate the effective confining pressure at failure.?arrow_forwardProblem # 5. The angle of friction of compacted dry sand is 37°. In a direct shear test on the sand, normal stress of 150 kN/m^2 was applied. The size of the specimen was 50mm x 50mm 30 mm (height): a. Compute the shearing stress.b. What shear force will cause will cause shear failure?c. Determine the shear stress at a depth 3m. If the void ratio of the soil is 0.60. Sp. Gr. of sand is 2.70.arrow_forwardQuestion 2 The result presented in Table Q2a were obtained from a consolidated drained (CD) triaxial test on a normally consolidated clay sample of 75mm height x 38mm diameter tested at a confining pressure of 50 kPa. Table Q2a. CD triaxial test result Axial strain (%) 1 2 5 10 15 Applied force (kN) 0.01 0.03 0.05 0.08 0.10 Page 3 of 6 (a) Draw the Mohr circle for each stress state in the sample and the total stress path (TSP) throughout the test and determine the slope of the TSP to the horizontal.arrow_forward
- The stresses on a failure plane in a drained triaxial test on sand are as Follows: Normal Stress nf = 100 kN/m2 Shear Stress τf = 40 kN/m2 Required: a) Determine the angle of internal friction and angle of failure plane b) Find the major and minor principle stresses (1 , 3 )arrow_forwardThe soil profile shown consists of dry sand (4-m thick) which overlies a layer of clay (3-m thick). Ground water table is located at the interface of the sand and clay. a. If the water table rises to the top of the ground surface, what is the change in the effective stress (in kPa) at the bottom of the clay layer? Round off to two decimal places. (ANSWER: 26.336) b. Compute the effective stress at the bottom of the clay layer in kPa. Round off to three decimal places (ANSWER: 97.686) c. How many meters must the ground water table rise to decrease the effective stress by 14 kPa, at the bottom of the clay layer? Round off to two decimal places (ANSWER: 2.13)arrow_forwardRefer to the soil profile shown. Given H1 = 8.93 m., and H2 = 5.32 m. If the ground water table rises by 2.01 meters, determine the change in effective stress (numerical value only, in kPa) at the bottom of the clay layer. Properties of dry sand: Gs = 2.56, e = 0.65. Properties of clay: Gs = 2.72, e = 0.87. Round off to two decimal places. Selected Answer: 11.95 Correct Answer: 11.95 ± 1arrow_forward
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