Physics for Scientists and Engineers, Vol. 1
6th Edition
ISBN: 9781429201322
Author: Paul A. Tipler, Gene Mosca
Publisher: Macmillan Higher Education
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Question
Chapter 3, Problem 33P
(a)
To determine
To Draw:A motion diagram for the data collected for a rookie bungie jump and the acceleration for each consecutive
(b)
To determine
Whether, the y component of the acceleration varies in sign and in magnitude when the direction of motion is reversed.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
The position-time graph that
describes the motion of an object is
given as in the figure below.
if the values of a= 138.4m, b=227.5m
and c=312.5m, Find the distance
traveled by the object ( in units of m)
over the time interval of [0, 40] s.
x(m)
a
t(s)
10
30
40
Select one:
O A. 263.2
OB. 401.6
OC. 490.7
OD. 678.4
O E. 540.0
20
Then, substituting the time, results to the following
hmax = (
)+ (1/2)ay(
Substituting ay = -g, results to
hmax = (
)- (1/2)g(
simplifying the expression, yields
hmax =
x sin
b)
The distance traveled by a projectile follows a uniform motion, meaning, velocity is constant from the start point until it reach the ground along the
horizontal axis, so, the range R can be expressed as
R= Vinitial-xt
Substituting the initial velocity on the x-axis results to the following
R = (
)t
But, the time it takes a projectile to travel this distance is just twice of tmax-height, by substitution, we obtain the following:
R =
x 2 x (
Re-arranging and then applying the trigonometric identity
sin(2x) = 2sin(x)cos(x)
we arrive at the expression for the range R as
R =
sin
A particle moves along the x-axis with position function
x(t) = At² + B²²³,
where 4 = 3 m s-² and B=ms-3 are constants. Find the instantaneous velocity vx and
the instantaneous acceleration ax of the particle at time t = 2 s. Give your answers by
entering the appropriate integer numbers in the two empty boxes below (you don't need
to concern yourself with significant figures in this question).
At time t=2s : Vx =
At time t=2s : ax =
ms-1.
ms-2.
You may use the following standard derivative:
dc4"
dt
nCtn - 1 where C and are any constants.
n
Chapter 3 Solutions
Physics for Scientists and Engineers, Vol. 1
Ch. 3 - Prob. 1PCh. 3 - Prob. 2PCh. 3 - Prob. 3PCh. 3 - Prob. 4PCh. 3 - Prob. 5PCh. 3 - Prob. 6PCh. 3 - Prob. 7PCh. 3 - Prob. 8PCh. 3 - Prob. 9PCh. 3 - Prob. 10P
Ch. 3 - Prob. 11PCh. 3 - Prob. 12PCh. 3 - Prob. 13PCh. 3 - Prob. 14PCh. 3 - Prob. 15PCh. 3 - Prob. 16PCh. 3 - Prob. 17PCh. 3 - Prob. 18PCh. 3 - Prob. 19PCh. 3 - Prob. 20PCh. 3 - Prob. 21PCh. 3 - Prob. 22PCh. 3 - Prob. 23PCh. 3 - Prob. 24PCh. 3 - Prob. 25PCh. 3 - Prob. 26PCh. 3 - Prob. 27PCh. 3 - Prob. 28PCh. 3 - Prob. 29PCh. 3 - Prob. 30PCh. 3 - Prob. 31PCh. 3 - Prob. 32PCh. 3 - Prob. 33PCh. 3 - Prob. 34PCh. 3 - Prob. 35PCh. 3 - Prob. 36PCh. 3 - Prob. 37PCh. 3 - Prob. 38PCh. 3 - Prob. 39PCh. 3 - Prob. 40PCh. 3 - Prob. 41PCh. 3 - Prob. 42PCh. 3 - Prob. 43PCh. 3 - Prob. 44PCh. 3 - Prob. 45PCh. 3 - Prob. 46PCh. 3 - Prob. 47PCh. 3 - Prob. 48PCh. 3 - Prob. 49PCh. 3 - Prob. 50PCh. 3 - Prob. 51PCh. 3 - Prob. 52PCh. 3 - Prob. 53PCh. 3 - Prob. 54PCh. 3 - Prob. 55PCh. 3 - Prob. 56PCh. 3 - Prob. 57PCh. 3 - Prob. 58PCh. 3 - Prob. 59PCh. 3 - Prob. 60PCh. 3 - Prob. 61PCh. 3 - Prob. 62PCh. 3 - Prob. 63PCh. 3 - Prob. 64PCh. 3 - Prob. 65PCh. 3 - Prob. 66PCh. 3 - Prob. 67PCh. 3 - Prob. 68PCh. 3 - Prob. 69PCh. 3 - Prob. 70PCh. 3 - Prob. 71PCh. 3 - Prob. 72PCh. 3 - Prob. 73PCh. 3 - Prob. 74PCh. 3 - Prob. 75PCh. 3 - Prob. 76PCh. 3 - Prob. 77PCh. 3 - Prob. 78PCh. 3 - Prob. 79PCh. 3 - Prob. 80PCh. 3 - Prob. 81PCh. 3 - Prob. 82PCh. 3 - Prob. 83PCh. 3 - Prob. 84PCh. 3 - Prob. 85PCh. 3 - Prob. 86PCh. 3 - Prob. 87PCh. 3 - Prob. 88PCh. 3 - Prob. 89PCh. 3 - Prob. 90PCh. 3 - Prob. 91PCh. 3 - Prob. 92PCh. 3 - Prob. 93PCh. 3 - Prob. 94PCh. 3 - Prob. 95PCh. 3 - Prob. 96PCh. 3 - Prob. 97PCh. 3 - Prob. 98PCh. 3 - Prob. 99PCh. 3 - Prob. 100PCh. 3 - Prob. 101PCh. 3 - Prob. 102PCh. 3 - Prob. 103PCh. 3 - Prob. 104PCh. 3 - Prob. 105PCh. 3 - Prob. 106PCh. 3 - Prob. 107PCh. 3 - Prob. 108PCh. 3 - Prob. 109PCh. 3 - Prob. 110PCh. 3 - Prob. 111PCh. 3 - Prob. 112PCh. 3 - Prob. 113PCh. 3 - Prob. 114PCh. 3 - Prob. 115PCh. 3 - Prob. 116PCh. 3 - Prob. 117PCh. 3 - Prob. 118PCh. 3 - Prob. 119PCh. 3 - Prob. 120PCh. 3 - Prob. 121PCh. 3 - Prob. 122P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- the motion of the particle is described by the equation x(t)=at^3-bt^2. where a is 3.36 in m/s^3 and b is 2.84 in m/s^2. find the instantaneous velocity in m/s of the particle from time t 5.93s. Express your answer rounded off to two decimal places. Do not include the unit.arrow_forwardHigh-speed motion pictures (3500 frames/second) of a jumping 230 μg flea yielded the data to plot the flea's acceleration as a function of time as shown in the figure ( Figure 1). (See "The Flying Leap of the Flea," by M. Rothschild et al. in the November 1973 Scientific American.) This flea was about 2 mm long and jumped at a nearly vertical takeoff angle. Use the measurements shown on the graph to answer the questions. Figure alg 150 100 50 0 0 0.5 1.0 1.5 Part E Use the graph to find the flea's maximum speed. Express your answer in meters per second to two significant figures. IVE] ΑΣΦ 3 v=1.6 Submit Previous Answers Request Answer ? X Incorrect; Try Again; 2 attempts remaining m/sarrow_forwardAn object's velocity as a function of time in one dimension is given by the expression; v(t) = 3.8t + 6.68 where are constants have proper SI Units. At what time is the object's velocity 61.2 m/s?arrow_forward
- I am having trouble solve a beggining question for my physics lab course. I have to dervive a formula for time given the equations in the photo attatched. In this experiment a cannon is being fired at a specified height and angle. To start, the cannon is set to a height of 10m and the angle of the launch being set at 0 degrees.arrow_forwardThe acceleration of a particle is a constant. At t = 0 the velocity of the particle is (15.8î + 18.4ĵ) m/s.At = 3.6 s the velocity is 10.5ĵ m/s. (Use the following as necessary: t. Do not include units in your answers.) (b) How do the position (in m) and velocity (in m/s) vary with time? Assume the particle is initially at the origin.arrow_forwardSlowing Down: The speed of an object moving through a viscous fluid is given byU(1) = A. c-br(a) If the numerical value of A (in SI units) is 5.20 and the numerical value of b (in SIunits) is 1.19, then what is the initial acceleration of the particle, at time / = 0?(b) How far does the particle move in the first 3.00 s?You may ignore gravity. The particle has the same density as the fluid.arrow_forward
- Please answer the following question(s): 1. The speed of a boat in still water is vá. A river flows with a speed of v₁. The boat travels distance of 19 miles downstream in a river in 1 hour. However, the return journey takes 2 hours. Calculate the vand v₁. Hint: Velocity=displacement/time. Displacement can be positive of neagtive depending on the direction. You will first need to set up the equations by taking into account the resultant velocity of the boat in flowing water. Consider the direction the river is flowing to be positive. Set up two equations, one for the downstream journey and one for the upstream journey, in terms of "v" and "v": Do v" and "v, add or substract downstream to give the resultant downstream velocity? Do v" and "v, add or substract upstream togive the resultant upstream velocity? Use the upstream direction as negative. The resultant upstream velocity should be negative. vb vb Downstream positive Vr Upstream negative Vrarrow_forwardAn object's position as a function of time in one dimension is given by the expression; 3.89t2 + 2.22t + 7.48 where are constants have proper SI Units. What is the object's average velocity between the times t = 3.16 s and t = 8.38 s? with everything in 3 sig figsarrow_forwardThe rectilinear motion of a particle is given by s = v squared minus 9 where s is in feet(ft) and v in feet per second (ft/sec).When t = 0, s = 0 and v = 3 ft/sec. Find the displacement-time (s-t), velocity-time (v-t), and acceleration-time (a-t) relation. Note: a = 0.15 m/s squared (or 0.50 ft/sec squared).arrow_forward
- The "reaction time" of the average automobile driver is about 0.7 ss . (The reaction time is the interval between the perception of a signal to stop and the application of the brakes.) An automobile can slow down with an acceleration of 13.2 ft/s2ft/s2 . A)Compute the total distance covered in coming to a stop after a signal is observed from an initial velocity of 16.6 mi/hmi/h . (in a school zone) B)Compute the total distance covered in coming to a stop after a signal is observed from an initial velocity of 57.0 mi/hmi/h Give answers in ftarrow_forwardAn object's position as a function of time in one dimension is given by the expression; 2.74t2 + 3.01t + 13.9 where are constants have proper SI Units. What is the object's average velocity between the times t = 4.06 s and t = 8.22 s?arrow_forwardOne of my questions got solved and helped me so much thank you! Here’s another one please. Two trains are 9.82km apart. They travel in opposite directions, to each other. Train A has a speed of 5.87 km/h at departure and an acceleration of 0.29m/s squared. Train B has a speed of 20.3m/s at the start and an acceleration of 0.69m/s squared. B. Determine when the trains meet.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Physics for Scientists and Engineers, Technology ...PhysicsISBN:9781305116399Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
Physics for Scientists and Engineers, Technology ...
Physics
ISBN:9781305116399
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Relative Velocity - Basic Introduction; Author: The Organic Chemistry Tutor;https://www.youtube.com/watch?v=_39hCnqbNXM;License: Standard YouTube License, CC-BY