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Use the principle of superposition to determine the current
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- Using mesh current analysis, find the voltage, v,across the source in the circuit of Figure P3.18.arrow_forwardDetermine v(t) in the circuit of Fig. P3.19 given that vs(t)=2u(t) V, R1=(1)ohm, R2=(3) ohm, C=0.3689 F, and L=0.2259 H. Please answer in typing format solution please Please it's urgent i will be likearrow_forwardUsing mesh current analysis, find the voltage vacross R4 in the circuit of Figure P3.25. LetVS1 = 12 V; VS2 = 5 V; R1 = 50 Ω; R2 = R3 = 20Ω ;R4 = 10 Ω; R5 = 15Ω .arrow_forward
- In the circuit shown in Figure P3.33, F1 and F2 arefuses. Under normal conditions they are modeled as ashort circuit. However, if excess current flows througha fuse, it “blows” and the fuse becomes an open circuit.VS1 = VS2 = 120 VR1 = R2 = 2 Ω R3 = 8Ω R4 = R5 = 250 mΩIf F1 blows, or opens, determine, using KCL and nodeanalysis, the voltages across R1, R2, R3, and F1.arrow_forwardA 10-mH inductor has a parasitic series resistance of R s =1 Ω, as shown in FigureP3.68.a. The current is given by i( t )=0.1 cos( 10 5 t ). Find v R ( t ), v L ( t ), and v(t). In thiscase, for 1-percent accuracy in computing v(t), could the resistance be neglected?b. Repeat if i( t )=0.1 cos( 10t ).arrow_forwardUsing KCL, perform node analysis on the circuitshown in Figure P3.24, and determine the voltageacross R4. Note that one source is a controlled voltagesource! Let VS = 5 V; AV = 70; R1 = 2.2 kΩ;R2 = 1.8 kΩ; R3 = 6.8 kΩ; R4 = 220Ωarrow_forward
- Using mesh current analysis, find the currents i1 and i2 for the circuit of Figure P3.14.arrow_forward1.What factor(s) can contribute to differences between ideal theoretical values in a circuit and values measured in actual practice? A) Measurement inaccuracy B)Component tolerances C)Both (a) and (b). D)Neither (a) nor (b). 2.What maximum range of values could resistor R3 have and still be within tolerance assuming R3 is a 10% resistor? A) 3296.7 – 3303.3 Ω B) 2970 – 3630 Ω C) 3267 – 3333 Ω D) 2967 – 3633 Ω 3.A voltage of one volt applied across a resistance of one ohm produces a current of one ampere. What happens to the current if the voltage is doubled and the resistance is halve? A)It doubles. B)It increases four times. C)It increases three times. D)It remains the same. In Question 3, what is the current in amperes if the voltage is halved and the resistance is doubled? A) 1 ampere B) 33 ampere C) 5 ampere D) 25 amperearrow_forwardUsing mesh current analysis, find the currents I1, I2, and I3 in the circuit of Figure P3.17 (assume polarity according to I2).arrow_forward
- Use the mesh analysis to determine the currents i1 and i2 in the circuit of Figure P3.7arrow_forwardfind Rt, It, Pt, P1, P2, P3P4,P5,P6arrow_forwardQ3:- Design the circuit shown in Fig.(3) , to give a voltage gain = 20 Assume Veso =3V , Vbso =4V, Ing =5 mA and K=2 mA / V? Rin =1 MQ Vop =24Varrow_forward
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