Elementary Surveying (14th Edition)
14th Edition
ISBN: 9780133758887
Author: Charles D. Ghilani, Paul R. Wolf
Publisher: PEARSON
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Textbook Question
Chapter 3, Problem 3.5P
Discuss the diffexrence between accuracy and precisimm.
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1) a transit with stadia interval factor of 100.8 was set up at point C on the line bet. A and B. The ff. readings were observed: (*see from attached photo)
If the distance from the focus is 0.38m. determine the ff.:
a) horizontal distance bet. A and B
b) Diff. in elevation bet. A and B of the value of HI are 300m and 315m respectively.
The following tacheometric observations were made from station A to stations 1 and 2.
The height of the instrument above the ground was 1.52 m. Take stadia interval factor and constant as 100 and 0, respectively. If the staff was inclined by 1° to the vertical, solve for the following:a. Error in horizontal distance if the staff is inclined towards theinstrument for the line A-1. b. Error in the vertical distance if the staff is inclined away from theinstrument for the line A-2. c. If the elevation of point 1 is 115.673 m, determine the correctelevation of point 2.
Describe Correction factor for field SPT values.
Chapter 3 Solutions
Elementary Surveying (14th Edition)
Ch. 3 - Discuss the differences between an error and a...Ch. 3 - Prob. 3.2PCh. 3 - Prob. 3.3PCh. 3 - Prob. 3.4PCh. 3 - Discuss the diffexrence between accuracy and...Ch. 3 - Prob. 3.6PCh. 3 - Prob. 3.7PCh. 3 - Prob. 3.8PCh. 3 - Prob. 3.9PCh. 3 - Prob. 3.10P
Ch. 3 - Prob. 3.11PCh. 3 - Prob. 3.12PCh. 3 - Prob. 3.13PCh. 3 - Prob. 3.14PCh. 3 - Prob. 3.15PCh. 3 - Prob. 3.16PCh. 3 - Prob. 3.17PCh. 3 - Prob. 3.18PCh. 3 - Prob. 3.19PCh. 3 - Prob. 3.20PCh. 3 - Prob. 3.21PCh. 3 - Prob. 3.22PCh. 3 - Prob. 3.23PCh. 3 - Prob. 3.24PCh. 3 - Prob. 3.25PCh. 3 - Prob. 3.26PCh. 3 - Prob. 3.27PCh. 3 - Prob. 3.28PCh. 3 - Prob. 3.29PCh. 3 - Prob. 3.30P
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- Define Normalized CPT Parametersarrow_forwardA line of three-wire differential levels goes from benchmark Gloria to benchmark Carey. The length of the line was determined to be 2097 m. The instrument had a stated compensator accuracy of pm 1.4 mm/ km. The instrument–rod combination had an estimated reading error of 0.4 mm per 40 m. Sight distances were kept to approximately 50 5 m. If the observed difference in elevation is 15.601 m, what is the estimated error in the final elevation difference? If benchmark Gloria had a fixed elevation of 231.071 m and Carey had a fixed elevation of 246.660 m, did the job meet acceptable closure limits at a 95% level of confidence? Justify your answer statistically.arrow_forwardLinear Error of Closure Given a closed traverse with sum of south latitudes exceeds the sum of north latitudes by 3.550 m and the sum of east departures exceeds the sum of the west departures by 2.830 m, determine the following: a.) The Linear Error of Closure. b.) The Bearing of Error. c.) The Relative Precision of the measurements made. Note: EXPRESS YOUR ANSWER UPTO 3 DECIMAL PLACES. Please provide a proven and accurate solution. Thank you so mucharrow_forward
- Q#1: A profile levelling is carried out and consecutive readings were observed on staff rod along a chain line at common interval of 10 meter which are listed below in table. First reading is taken on bench mark of 105.615 meter reduce level. Station Points Chainage (m) Staff Readings (m) Remarks BS IS FS 1 00 3.005 BM 2 10 2.285 3 20 1.560 4 30 1.785 5 40 2.105 6 50 2.875 3.105 CP 1 X 53.35 3.465 7 60 3.955 8 70 3.120 9 80 3.015 10 90 2.580 11 100 1.955 CP 2 Determine the reduce levels of all points using both line of collimation and rise and fall method. (Present your answer in table form).arrow_forwardComplete the following level notes. Show your detailed solution and checking. Differential Leveling Station BS HI FS Elevation BM1 1.050 ---- 147.630 TP1 1.224 1.923 TP2 1.276 1.481 TP3 1.087 2.290 TP4 1.162 2.140 TP5 1.751 2.700 BM2 ---- 2.565arrow_forwardDiscuss Corrected CPT Parametersarrow_forward
- Which statements about the Global Positioning System (GPS) are true(multiple choice questions)A.The plane error is smaller than the elevation errorb.Static measurement is more accurate than dynamic measurementc.using geostationary satellitesD.distance intersection methodarrow_forwardLinear Error of Closure Given a closed traverse with sum of south latitudes exceeds the sum of north latitudes by 3.550 m and the sum of east departures exceeds the sum of the west departures by 2.830 m, determine the following: a.) The Linear Error of Closure. b.) The Bearing of Error. c.) The Relative Precision of the measurements made. Note: EXPRESS YOUR ANSWER UPTO 3 DECIMAL PLACES. (Please provide a proven solution and be accurate. Kindly be mindful for the decimal places. Thank you so much.)arrow_forwardLines of levels were run requiring n instrument setups. If the rod reading for each backsight and foresight has a standard deviation s, what is the standard deviation in each of the following level lines?(a) n = 15, s = ±0.015 ft(b) n = 28, s = ±5 mmarrow_forward
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