Chapter 3, Problem 3.74P

Interpretation Introduction

(a)

Interpretation:

The name of the ionic compound KF needs to be determined.

Concept introduction:

In an ionic compound, a cation is named first, while an anion is named later. As the question contains monoatomic ions, the rules related to the nomenclature of monoatomic ions should be followed.

Answer to Problem 3.74P

Potassium fluoride.

Explanation of Solution

An ionic compound is a combination of a cation (positively charged ion) & an anion (negatively charged ion). This combination results in a charge neutralized stable chemical species.

There is a specific pattern to name an ionic compound. Usually, in a formula of an ionic compound, a cation is presented in the right side, while an anion is in the left side.

Naming of cations

1. The naming of the cation is very simple. It is just the writing of the name of the metal element.
2. Sometimes there are some metals that form different cations. In that case after the cation name, the charge should be indicated in roman numbers, with in the brackets.

Naming of anions

1. To determine the name of the monoatomic anion (anion which has only one type of atom) following rules should be followed. When naming an anion the ending name of the elemental anion should be removed to replace it by "ide". This question contains ionic compounds with monoatomic anions.

These rules will be cleared when using them practically to write the ionic names.

Consider KF. The cation is K⁺. The only cation related to K is K⁺. Therefore, 2^nd rule of cations is not applied.

KF − Potassium + Fluor(ine)

Within the brackets, it contains the ending of the anion. That part should be removed to replace by "ide".

Potassium + Fluor(ide)

Potassium fluoride.

Interpretation Introduction

(b)

Interpretation:

The name of the ionic compound ZnCl₂ needs to be determined.

Concept introduction:

In an ionic compound cation is named first, while an anion is named later. As the question contains monoatomic ions, the rules related to the nomenclature of monoatomic ions should be followed.

Answer to Problem 3.74P

Zinc(II) Chloride.

Explanation of Solution

An ionic compound is a combination of a cation (positively charged ion) & an anion (negatively charged ion). This combination results in a charge neutralized stable chemical species.

There is a specific pattern to name an ionic compound. Usually, in a formula of an ionic compound, a cation is presented in the right side, while an anion is in the left side.

Using the described rules, the name of the ionic compound can be derived as follows.

Consider ZnCl₂,the cation is Zn²⁺. So, II should be mentioned within brackets.

ZnCl₂ − Zinc(II) + Chlor(ine)

Within the brackets, it contains the ending of the anion. That part should be removed to replace by "ide".

Zinc(II) + Chlor(ide)

Zinc(II) Chloride

Interpretation Introduction

(c)

Interpretation:

The name of the ionic compound Cu₂Sneeds to be determined.

Concept introduction:

In an ionic compound cation is named first, while an anion is named later. As the question contains monoatomic ions, the rules related to the nomenclature of monoatomic ions should be followed.

Answer to Problem 3.74P

Copper(I) Sulfide.

Explanation of Solution

An ionic compound is a combination of a cation (positively charged ion) & an anion (negatively charged ion). This combination results in a charge neutralized stable chemical species.

There is a specific pattern to name an ionic compound. Usually, in a formula of an ionic compound, a cation is presented in the right side, while an anion is in the left side.

Using the described rules, the name of the ionic compound can be derived as follows.

Consider Cu₂S. The cation is Cu+ (Cuprous). Cu has two cations as Cu+ (Cuprous) & Cu²+ (Cupric). So the second rule for cations applies here. So, I should be mentioned within brackets.

Cu₂S − Copper(I) + Sulf(ur)

Within the brackets, it contains the ending of the anion. That part should be removed to replace by "ide".

Copper(I) + Sulf(ide)

Copper(I) Sulfide

Copper(I) Sulfide is the name of Cu₂S, according to the IUPAC (International Union of Pure and Applied Chemistry) rules of ionic compound nomenclature. Generally, Cu₂S also be known as Cuprous Sulfide as Cu+ ion is known as Cuprous ion.

Interpretation Introduction

(d)

Interpretation:

The name of the ionic compound SnO needs to be determined.

Concept introduction:

In an ionic compound cation is named first, while an anion is named later. As the question contains monoatomic ions, the rules related to the nomenclature of monoatomic ions should be followed.

Answer to Problem 3.74P

Tin(II) Oxide

Explanation of Solution

An ionic compound is a combination of a cation (positively charged ion) & an anion (negatively charged ion). This combination results in a charge neutralized stable chemical species.

There is a specific pattern to name an ionic compound. Usually, in a formula of an ionic compound, a cation is presented in the right side, while an anion is in the left side.

Using the described rules, the name of the ionic compound can be derived as follows.

Consider SnO, the cation is Sn²+ (Stannous). Sn has two cations as Sn²+ (Stannous) & Sn⁴+ (Stannic). So the second rule for cations applies here. So II should be mentioned within brackets. The common name for the metal is Tin.

SnO − Tin(II) + Ox(ygen)

Within the brackets, it contains the ending of the anion. That part should be removed to replace by "ide".

Tin(II) + Ox(ide)

Tin(II) Oxide

Tin(II) Oxide is the name of SnO, according to the IUPAC (International Union of Pure and Applied Chemistry) rules of ionic compound nomenclature. Generally, SnO also can be known as Stannous Oxide as Sn²+ ion is known as Stannous ion.

Interpretation Introduction

(e)

Interpretation:

The name of the ionic compound AuBr₃ needs to be determined.

Concept introduction:

In an ionic compound cation is named first, while an anion is named later. As the question contains monoatomic ions, the rules related to the nomenclature of monoatomic ions should be followed.

Answer to Problem 3.74P

Gold(III) Bromide

Explanation of Solution

An ionic compound is a combination of a cation (positively charged ion) & an anion (negatively charged ion). This combination results in a charge neutralized stable chemical species.

There is a specific pattern to name an ionic compound. Usually, in a formula of an ionic compound, a cation is presented in the right side, while an anion is in the left side.

Using the described rules, the name of the ionic compound can be derived as follows.

Consider AuBr₃. The cation is Au³+ (Auric). Au has two cations as Au+ (Aurous) & Au³+ (Auric). So the second rule for cations applies here. So III should be mentioned within brackets. The common name for the metal is Gold.

AuBr₃ − Gold(III) + Brom(ine)

Within the brackets, it contains the ending of the anion. That part should be removed to replace by "ide".

Gold(III) + Brom(ide)

Gold(III) Bromide

Gold(III) Bromide is the name of AuBr₃, according to the IUPAC (International Union of Pure and Applied Chemistry) rules of ionic compound nomenclature. Generally, AuBr₃ also be known as Gold tribromide or Auric bromide.

Interpretation Introduction

(f)

Interpretation:

The name of the ionic compound Li₂S needs to be determined.

Concept introduction:

In an ionic compound cation is named first, while an anion is named later. As the question contains monoatomic ions, the rules related to the nomenclature of monoatomic ions should be followed.

Answer to Problem 3.74P

Lithium Sulfide.

Explanation of Solution

Ionic compound is a combination of a cation (positively charged ion) and an anion (negatively charged ion). This combination results in a charge neutralized stable chemical species.

There is a specific pattern to name an ionic compound. Usually, in a formula of an ionic compound, a cation is presented in the right side, while an anion is in the left side.

Using the described rules, the name of the ionic compound can be derived as follows.

Consider Li₂S. The cation is Li⁺. The only cation related to Li is Li⁺. Therefore, 2^nd rule of cations is not applied.

Li₂S − Lithium + Sulf(ur)

Within the brackets, it contains the ending of the anion. That part should be removed to replace by "ide".

Lithium + Sulf(ide)

Lithium Sulfide

Interpretation Introduction

(g)

Interpretation:

The name of the ionic compound SnBr₄ needs to be determined.

Concept introduction:

In an ionic compound cation is named first, while an anion is named later. As the question contains monoatomic ions, the rules related to the nomenclature of monoatomic ions should be followed.

Answer to Problem 3.74P

Tin(IV)bromide.

Explanation of Solution

Ionic compound is a combination of a cation (positively charged ion) and an anion (negatively charged ion). This combination results in a charge neutralized stable chemical species.

There is a specific pattern to name an ionic compound. Usually, in a formula of an ionic compound, a cation is presented in the right side, while an anion is in the left side.

Using the described rules, the name of the ionic compound can be derived as follows.

Consider SnBr₄. The cation is Sn⁴+ (Stannic). Sn has two cations as Sn²+ (Stannous) & Sn⁴+ (Stannic). So the second rule for cations applies here. So IV should be mentioned within brackets. The common name for the metal is Tin.

SnBr₄ − Tin(IV) + Brom(ine)

Within the brackets, it contains the ending of the anion. That part should be removed to replace by "ide".

Tin(IV) + Brom(ide)

Tin(IV) Bromide

Tin(IV)Bromide is the name of SnBr₄, according to the IUPAC (International Union of Pure and Applied Chemistry) rules of ionic compound nomenclature. Generally, SnBr₄ also can be known as Stannic Bromide as Sn⁴+ ion is known as Stannic ion.