Interpretation:
Among I, II and III, arrangement that possesses strongest intermolecular attractions has to be determined. Also, reason for the same has to be explained.
Concept Introduction:
Intermolecular forces are forces that are responsible for interaction between molecules. Such forces include both attractive as well as repulsive forces.
Types of intermolecular forces:
1. Ion-dipole forces: These forces come into play when ions interact with polar molecules. Ion gets attracted to oppositely charged end of polar molecule.
2. Dipole-dipole forces: These forces arise when there is interaction between oppositely charged ends of different dipoles.
3. London forces: These forces exist when there is interaction between nonpolar molecules. There occurs distortion in symmetry of electron clouds when two nonpolar molecules come closer to each other. Such forces exist in all molecules and therefore London forces are called universal.
4. Hydrogen bonding: This intermolecular force exists when hydrogen atoms are connected to highly electronegative elements like
Want to see the full answer?
Check out a sample textbook solutionChapter 3 Solutions
Chemical Principles: The Quest for Insight
- Define the following terms and describe how each depends on the strength of the intermolecular forces. a. surface tension b. viscosity c. melting point d. boiling point e. vapor pressurearrow_forwardPredict which liquid—glycerol, HOCH2CH(OH)CH2OH, or hexane, C6H14—has the greater surface tension. Explain your prediction.arrow_forwardOn the basis of intermolecular attractions, explain the differences in the boiling points of n butane (1 C) and chloroethane (12 C), which have similar molar masses.arrow_forward
- For liquid-state samples of the following diatomic molecules, indicate the type or types of intermolecular forces (dipoledipole interactions, hydrogen bonding, London forces) present. There may be more than one correct answer in a given situation. a. H2 b. HF c. CO d. F2arrow_forwardThe root mean square speed of H2, molecules at 25 C is about 1.6 km/s. What is the root mean square speed of a N2, molecule at 25 C?arrow_forwardDefine the following and give an example of each: (a) dispersion force (b) dipole-dipole attraction (c) hydrogen bondarrow_forward
- Introductory Chemistry: An Active Learning Approa...ChemistryISBN:9781305079250Author:Mark S. Cracolice, Ed PetersPublisher:Cengage LearningChemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage Learning
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistry: An Atoms First ApproachChemistryISBN:9781305079243Author:Steven S. Zumdahl, Susan A. ZumdahlPublisher:Cengage LearningChemistry by OpenStax (2015-05-04)ChemistryISBN:9781938168390Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark BlaserPublisher:OpenStax