COLLEGE PHYSICS-CONNECT ACCESS
COLLEGE PHYSICS-CONNECT ACCESS
5th Edition
ISBN: 9781260486834
Author: GIAMBATTISTA
Publisher: MCG
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Chapter 3, Problem 41P

(a)

To determine

The acceleration ax at t=11s.

(a)

Expert Solution
Check Mark

Answer to Problem 41P

The acceleration ax at t=11s is 10m/s2_.

Explanation of Solution

Use the given graph and write the expression for the acceleration ax.

    ax=ΔvxΔt        (I)

Here, ax is the acceleration, Δvx is the change in velocity, Δt is the time interval.

Conclusion:

Substitute 10m/s for Δvx, 1s for Δt in equation (I) to find ax.

    ax=10m/s1s=10m/s2

Therefore, the acceleration ax at t=11s is 10m/s2_.

(b)

To determine

The acceleration ax at t=3s.

(b)

Expert Solution
Check Mark

Answer to Problem 41P

The acceleration ax at t=3s is 0m/s2_.

Explanation of Solution

Use equation (I) to solve for ax.

Conclusion:

Substitute 0m/s for Δvx, 1s for Δt in equation (I) to find ax.

    ax=0m/s1s=0m/s2

The object is moving with a constant velocity.

Therefore, the acceleration ax at t=3s is 0m/s2_.

(c)

To determine

The graph of acceleration ax(t).

(c)

Expert Solution
Check Mark

Answer to Problem 41P

Figure 1 shows the graph of acceleration ax(t).

Explanation of Solution

Use the equation (I) to solve for the acceleration ax(t).

t(s)02468101214
ax(t)(m/s2)0005510100

COLLEGE PHYSICS-CONNECT ACCESS, Chapter 3, Problem 41P , additional homework tip  1

Figure 1 shows the graph of acceleration ax(t).

Conclusion:

Therefore, the figure 1 shows the graph of acceleration ax(t).

(d)

To determine

The distance travelled by the object from time t=12s to t=14s.

(d)

Expert Solution
Check Mark

Answer to Problem 41P

The distance travelled by the object from time t=12s to t=14s is 5.0m_.

Explanation of Solution

COLLEGE PHYSICS-CONNECT ACCESS, Chapter 3, Problem 41P , additional homework tip  2

Write the expression for the distance travelled by the object from time t=12s to t=14s.

    distance=area under the graph from t=12s to t=14s        (II)

Write the expression for the read under the graph from time t=12s to t=14s.

    distance=area of triangle ABC        (III)

Write the expression for the area of the triangle.

    area=12(BC)(AB)        (IV)

Use equation (IV) in (III) to solve for the distance travelled.

    distance=12(BC)(AB)        (V)

Conclusion:

Substitute 1s for BC, 10m/s in equation (V) to find distance travelled by the object from time t=12s to t=14s.

    distance=12(1s)(10m/s2)=5.0m

Therefore, the distance travelled by the object from time t=12s to t=14s is 5.0m_.

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Chapter 3 Solutions

COLLEGE PHYSICS-CONNECT ACCESS

Ch. 3.3 - Prob. 3.6PPCh. 3.3 - Prob. 3.3BCPCh. 3.3 - Prob. 3.7PPCh. 3.3 - Prob. 3.3CCPCh. 3.4 - The wheels fall off Beatrice’s suitcase, so she...Ch. 3.4 - Prob. 3.9PPCh. 3.4 - Prob. 3.10PPCh. 3.4 - Prob. 3.11PPCh. 3.5 - Prob. 3.5CPCh. 3.5 - Prob. 3.12PPCh. 3.5 - Prob. 3.13PPCh. 3 - Prob. 1CQCh. 3 - Prob. 2CQCh. 3 - Prob. 3CQCh. 3 - Prob. 4CQCh. 3 - Prob. 5CQCh. 3 - Prob. 6CQCh. 3 - Prob. 7CQCh. 3 - Prob. 8CQCh. 3 - Prob. 9CQCh. 3 - Prob. 10CQCh. 3 - Prob. 11CQCh. 3 - Prob. 12CQCh. 3 - Prob. 13CQCh. 3 - Prob. 14CQCh. 3 - Prob. 15CQCh. 3 - Tell whether each of the following objects has a...Ch. 3 - Prob. 17CQCh. 3 - Prob. 18CQCh. 3 - Prob. 21CQCh. 3 - Prob. 1MCQCh. 3 - Prob. 2MCQCh. 3 - Prob. 3MCQCh. 3 - Prob. 4MCQCh. 3 - Prob. 5MCQCh. 3 - Prob. 6MCQCh. 3 - Prob. 7MCQCh. 3 - Prob. 8MCQCh. 3 - Multiple-Choice Questions 7–16. A jogger is...Ch. 3 - Prob. 10MCQCh. 3 - Prob. 11MCQCh. 3 - Prob. 12MCQCh. 3 - Prob. 14MCQCh. 3 - Prob. 15MCQCh. 3 - Prob. 16MCQCh. 3 - Prob. 17MCQCh. 3 - Prob. 18MCQCh. 3 - Prob. 19MCQCh. 3 - Prob. 20MCQCh. 3 - Prob. 21MCQCh. 3 - Prob. 22MCQCh. 3 - Prob. 23MCQCh. 3 - Prob. 24MCQCh. 3 - Prob. 25MCQCh. 3 - Prob. 26MCQCh. 3 - Prob. 27MCQCh. 3 - Prob. 28MCQCh. 3 - Prob. 29MCQCh. 3 - Prob. 30MCQCh. 3 - Prob. 31MCQCh. 3 - Prob. 32MCQCh. 3 - Prob. 33MCQCh. 3 - Prob. 34MCQCh. 3 - Prob. 1PCh. 3 - Prob. 2PCh. 3 - Prob. 3PCh. 3 - Prob. 4PCh. 3 - Prob. 5PCh. 3 - Prob. 6PCh. 3 - Prob. 7PCh. 3 - Prob. 8PCh. 3 - Prob. 9PCh. 3 - Prob. 10PCh. 3 - You will be hiking to a lake with some of your...Ch. 3 - Prob. 12PCh. 3 - Prob. 13PCh. 3 - Prob. 14PCh. 3 - Prob. 15PCh. 3 - Prob. 16PCh. 3 - Prob. 17PCh. 3 - Prob. 18PCh. 3 - Prob. 19PCh. 3 - Prob. 20PCh. 3 - Prob. 21PCh. 3 - Prob. 22PCh. 3 - Prob. 23PCh. 3 - Prob. 24PCh. 3 - Prob. 26PCh. 3 - Prob. 27PCh. 3 - Prob. 28PCh. 3 - Prob. 29PCh. 3 - Prob. 30PCh. 3 - Prob. 31PCh. 3 - Prob. 32PCh. 3 - Prob. 33PCh. 3 - Prob. 34PCh. 3 - Prob. 35PCh. 3 - Prob. 36PCh. 3 - Prob. 37PCh. 3 - Prob. 38PCh. 3 - Prob. 39PCh. 3 - Prob. 41PCh. 3 - Prob. 42PCh. 3 - Prob. 43PCh. 3 - Prob. 44PCh. 3 - Prob. 45PCh. 3 - Prob. 46PCh. 3 - Prob. 48PCh. 3 - Prob. 49PCh. 3 - Prob. 50PCh. 3 - Prob. 51PCh. 3 - Prob. 53PCh. 3 - Prob. 54PCh. 3 - Prob. 55PCh. 3 - Prob. 56PCh. 3 - Prob. 57PCh. 3 - Prob. 59PCh. 3 - Prob. 60PCh. 3 - Prob. 61PCh. 3 - Prob. 62PCh. 3 - Prob. 63PCh. 3 - Prob. 64PCh. 3 - Prob. 65PCh. 3 - Prob. 66PCh. 3 - Prob. 67PCh. 3 - Prob. 68PCh. 3 - Prob. 69PCh. 3 - Prob. 70PCh. 3 - Prob. 71PCh. 3 - Prob. 72PCh. 3 - Prob. 73PCh. 3 - Prob. 74PCh. 3 - Prob. 75PCh. 3 - Prob. 76PCh. 3 - Prob. 77PCh. 3 - Prob. 78PCh. 3 - Prob. 79PCh. 3 - Prob. 80PCh. 3 - Prob. 82PCh. 3 - Prob. 83PCh. 3 - Prob. 84PCh. 3 - Prob. 86PCh. 3 - Prob. 87PCh. 3 - Prob. 88PCh. 3 - Prob. 89PCh. 3 - Prob. 91PCh. 3 - Prob. 92PCh. 3 - Prob. 93PCh. 3 - An elevator starts at rest on the ninth floor. At...Ch. 3 - Prob. 95PCh. 3 - Prob. 96PCh. 3 - Prob. 98PCh. 3 - Prob. 99PCh. 3 - Prob. 100PCh. 3 - Prob. 101PCh. 3 - Prob. 102PCh. 3 - Prob. 103PCh. 3 - Prob. 104PCh. 3 - Prob. 105PCh. 3 - Prob. 106PCh. 3 - Prob. 107PCh. 3 - Prob. 108PCh. 3 - Prob. 109PCh. 3 - Prob. 110PCh. 3 - Prob. 112PCh. 3 - Prob. 113PCh. 3 - Prob. 114PCh. 3 - Prob. 115PCh. 3 - Prob. 116PCh. 3 - Prob. 117PCh. 3 - Prob. 118PCh. 3 - Prob. 119PCh. 3 - Prob. 120PCh. 3 - Prob. 121PCh. 3 - Prob. 122PCh. 3 - Prob. 123PCh. 3 - Prob. 124PCh. 3 - Prob. 126P
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