(I) Huck Finn walks at a speed of 0.70m/s across his raft (that is, he walks perpendicular to the raft’s motion relative to the shore). The raft is traveling down the Mississippi River at a speed of 1.50 m/s relative to the river bank (Fig. 3-49). What is Huck’s velocity (speed and direction) relative to the river bank? FIGURE 3-49 Problem 58. 58. Call the direction of the flow of the river the x direction, and the direction of Huck walking relative to the raft the y direction. v → Huck rel . bank = v → Huck rel . raft + v → raft rel . bank = 0.70 j ^ m/s + 1 .50 i ^ m/s = ( 1.50 i ^ + 0.70 j ^ ) m/s Magnitude: v Huck rel . bank = 1.50 2 + 0.70 2 = 1.66 m/s Direction: θ =tan − 1 0.70 1.50 = 25 ° relative to river
(I) Huck Finn walks at a speed of 0.70m/s across his raft (that is, he walks perpendicular to the raft’s motion relative to the shore). The raft is traveling down the Mississippi River at a speed of 1.50 m/s relative to the river bank (Fig. 3-49). What is Huck’s velocity (speed and direction) relative to the river bank? FIGURE 3-49 Problem 58. 58. Call the direction of the flow of the river the x direction, and the direction of Huck walking relative to the raft the y direction. v → Huck rel . bank = v → Huck rel . raft + v → raft rel . bank = 0.70 j ^ m/s + 1 .50 i ^ m/s = ( 1.50 i ^ + 0.70 j ^ ) m/s Magnitude: v Huck rel . bank = 1.50 2 + 0.70 2 = 1.66 m/s Direction: θ =tan − 1 0.70 1.50 = 25 ° relative to river
(I) Huck Finn walks at a speed of 0.70m/s across his raft (that is, he walks perpendicular to the raft’s motion relative to the shore). The raft is traveling down the Mississippi River at a speed of 1.50 m/s relative to the river bank (Fig. 3-49). What is Huck’s velocity (speed and direction) relative to the river bank?
FIGURE 3-49
Problem 58.
58. Call the direction of the flow of the river the x direction, and the direction of Huck walking relative to the raft the y direction.
v
→
Huck rel
. bank
=
v
→
Huck rel
. raft
+
v
→
raft rel
. bank
=
0.70
j
^
m/s + 1
.50
i
^
m/s
=
(
1.50
i
^
+
0.70
j
^
)
m/s
Magnitude:
v
Huck rel
. bank
=
1.50
2
+
0.70
2
=
1.66
m/s
Direction:
θ
=tan
−
1
0.70
1.50
=
25
°
relative to river
In Fig. 3-27, a heavy piece of machinery is raised by sliding it a distance d =12.5 m along a plank oriented at angle 20.0° to the horizontal. How far is it moved
(a) vertically
(b) horizontally?
Question 2:
#63 In 1780, in what is now referred to as "Brady's Leap," Captain Sam Brady of the U.S. Continental Army escaped certain death from his enemies by running horizontally off the edge of the cliff above Ohio's Cuyahoga River, which is con-fined at that spot to a gorge. He landed safely on the far side of the river. It was reported that he leapt 22 ft across while falling 20 ft. Tall tale, or possible?
A basketball player is standing on the floor 14.0 m away from the basket. The height of the basket is 3.05 m, and heshoots the ball at 49.0° with the horizontal from a height of 2.00 m. At what speed must the player shoot the ball so thatit goes through the hoop without striking the backboard?
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