Explanation Given: The given equation is v = 0.50 [ S ] 3.0 × 10 − 4 + [ S ] Calculation: Differentiating with respect to [S], d v d [ S ] = d d [ S ] ( 0.50 [ S ] 3.0 × 10 − 4 + [ S ] ) According to the quotient rule of differentiation, ( f g ) ′ = g f ' − f g ' g 2 Therefore, d v d [ S ] = d d [ S ] ( 0.50 [ S ] 3.0 × 10 − 4 + [ S ] ) d v d [ S ] = ( 3.0 × 10 − 4 + [ S ] ) d d [ S ] ( 0.50 [ S ] ) − ( 0.50 [ S ] ) d d [ S ] ( 3.0 × 10 − 4 + [ S ] ) ( 3

15th Edition

ISBN: 9781305177291

Author: James Stewart, Troy Day

Publisher: Cengage Learning

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Differential Equations

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Chapter 3, Problem 78E

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The value and interpretation of dvd[S]

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Chapter 3, Problem 77E

Chapter 3, Problem 79E

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H.W2: A tank contains (400 L) of brine made by dissolving (20 kg) of salt in water. Salt water containing (0.75 kg) of salt per liter runs in at the rate of (2 L/min) and the well-stirred mixture runs out at the same rate of (5 L/min). Find the amount of salt in the tank after 15 minutes.

Find for y= =csc(x) %3D 2

A tank initially contains 200 liters of fresh water. Brine containing 2.5 N/liter of dissolved salt runs into the tank at the rate of 8 liters/min and the mixture kept uniform by stirring runs out at the same rate. After 15 minutes, what is the concentrations of the salt in the mixture? 1.8 N/L 2.1 N/L 0.82 N/L O 1.1 N/L

Chapter 3 Solutions

Biocalculus: Calculus For Life Sciences

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The value and interpretation of d v d [ S ]

Solution Summary: The author explains the value and interpretation of dv dleft[Sright]. The derivative represents the rate of change of enzymatic reaction with respect to the concentration of the

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