Given: The values of the variable termed ‘number’ are 30 and 35, and the following expression: if (number % 2 == 0) cout << number << " is even." << endl; cout << number << " is odd." << endl; To find: The possible output of the code. Solution: When the value of the number is 30. The possible outputs of the code can be “30 is even� and “30 is odd�. The condition in the ‘if’ statement will be true because (30 % 2 == 0) will be true. Therefore, the ‘if’ statement will be executed, and it will print the message “30 is even� on the console screen. After that, the third statement will also be executed because it is not written in any ‘if or else’ block...
Given: The values of the variable termed ‘number’ are 30 and 35, and the following expression: if (number % 2 == 0) cout << number << " is even." << endl; cout << number << " is odd." << endl; To find: The possible output of the code. Solution: When the value of the number is 30. The possible outputs of the code can be “30 is even� and “30 is odd�. The condition in the ‘if’ statement will be true because (30 % 2 == 0) will be true. Therefore, the ‘if’ statement will be executed, and it will print the message “30 is even� on the console screen. After that, the third statement will also be executed because it is not written in any ‘if or else’ block...
Solution Summary: The author explains that when the value of the number is 30, the ‘if’ statement will be executed, and it will print the message “30 is even” on the console screen.
Given: The values of the variable termed ‘number’ are 30 and 35, and the following expression:
if (number % 2 == 0)
cout << number << " is even." << endl;
cout << number << " is odd." << endl;
To find: The possible output of the code.
Solution:
When the value of the number is 30.
The possible outputs of the code can be “30 is even� and “30 is odd�. The condition in the ‘if’ statement will be true because (30 % 2 == 0) will be true. Therefore, the ‘if’ statement will be executed, and it will print the message “30 is even� on the console screen. After that, the third statement will also be executed because it is not written in any ‘if or else’ block...
(b)
Explanation of Solution
Given: The values of the variable termed ‘number’ are 30 and 35, and the following expression:
if (number % 2 == 0)
cout << number << " is even." << endl;
else
cout << number << " is odd." << endl;
To find: The possible output of the code.
Solution:
When the value of the number is 30.
The output of the code will be “30 is even�. The condition in the ‘if’ statement will be true because (30 % 2 == 0) will be true. Therefore, the ‘if’ statement will be executed, and it will print the message “30 is even� on the console screen. The ‘else’ statement will not be executed because when the ‘if’ statement is true, it does not execute the ‘else’ part...