PRIN.OF HIGHWAY ENGINEERING&TRAFFIC ANA.
7th Edition
ISBN: 9781119610526
Author: Mannering
Publisher: WILEY
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Chapter 3, Problem 9P
To determine
The elevation of the curve at station
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An equal-tangent crest vertical curve is designed with a PVI at station 110 + 00 (elevation 927.2 ft) and a PVC at station 107 + 43.3 (elevation 921.55 ft). If the high point is at station 110 + 75.5, what is the design speed of the curve?
A symmetrical parabolic summit curve is to connect two roads with grades of
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curve is to pass through a point P at station 18 + 400 at an elevation of 79.267 m.
Determine the elevation at the highest point on the curve.
A crest vertical curve connects a ?4.44% grade and a ?6.87% grade. The PVI is at station 43 ? 50.00 at an elevation of 1240.00 ft. The design speed is 30 mi/h.
Chapter 3 Solutions
PRIN.OF HIGHWAY ENGINEERING&TRAFFIC ANA.
Ch. 3 - Prob. 1PCh. 3 - Prob. 2PCh. 3 - Prob. 3PCh. 3 - Prob. 4PCh. 3 - Prob. 5PCh. 3 - Prob. 6PCh. 3 - Prob. 7PCh. 3 - Prob. 8PCh. 3 - Prob. 9PCh. 3 - Prob. 10P
Ch. 3 - Prob. 11PCh. 3 - Prob. 12PCh. 3 - Prob. 13PCh. 3 - Prob. 14PCh. 3 - Prob. 15PCh. 3 - Prob. 16PCh. 3 - Prob. 17PCh. 3 - Prob. 18PCh. 3 - Prob. 19PCh. 3 - Prob. 20PCh. 3 - Prob. 21PCh. 3 - Prob. 22PCh. 3 - Prob. 23PCh. 3 - Prob. 24PCh. 3 - Prob. 25PCh. 3 - Prob. 26PCh. 3 - Prob. 27PCh. 3 - Prob. 28PCh. 3 - Prob. 29PCh. 3 - Prob. 30PCh. 3 - Prob. 31PCh. 3 - Prob. 32PCh. 3 - Prob. 33PCh. 3 - Prob. 34PCh. 3 - Prob. 35PCh. 3 - Prob. 36PCh. 3 - Prob. 37PCh. 3 - Prob. 38PCh. 3 - Prob. 39PCh. 3 - Prob. 40PCh. 3 - Prob. 41PCh. 3 - Prob. 42PCh. 3 - Prob. 43PCh. 3 - Prob. 44PCh. 3 - Prob. 45PCh. 3 - Prob. 46PCh. 3 - Prob. 47PCh. 3 - Prob. 48PCh. 3 - Prob. 49PCh. 3 - Prob. 50PCh. 3 - Prob. 51PCh. 3 - Prob. 52PCh. 3 - Prob. 53PCh. 3 - Prob. 54PCh. 3 - Prob. 55PCh. 3 - Prob. 56PCh. 3 - Prob. 57PCh. 3 - Prob. 58PCh. 3 - Prob. 59PCh. 3 - Prob. 60PCh. 3 - Prob. 61PCh. 3 - Prob. 62PCh. 3 - Prob. 63PCh. 3 - Prob. 64PCh. 3 - Prob. 65PCh. 3 - Prob. 66PCh. 3 - Prob. 67P
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- A +3.00% grade intersects a -2.40% at station 46+70.00 and elevation 853.48 ft. A 400.00 ft curve will be used to connect the two grades. Compute Station and elevation for the curve's endpoints.arrow_forward3.9 An equal-tangent crest curve connects a +2% initial grade with a -1% final grade, and is designed for 55 mi/h. The station of the PVI is 233 + 40 with elevation 1203 ft. What is the elevation of the curve at station 234 +00?arrow_forwardA symmetrical parabolic summit curve connects two grades of +4.9% and -3.2%. It is to pass through a point "D" on the curve at station 25 + 180m . If the stationing of the grade intersection is 25 + 145m and the stationing of PVC is 24 + 979m determine the following: Length of the parabolic curve Stationing of the highest point. Difference in elevation between PVC and PVI Difference in elevation between PVC and point Darrow_forward
- A 500-m long equal tangent vertical curve has a point of vertical curvature at station 2 + 600 and elevation 450 m. The initial grade is -1% and final grade is +1% b) determine the highest and the lowest points on this vertical curve by using the K-value.arrow_forward1. If PVI at sta 5+650 has an elevation of 122.45 m what is the elevation of the grade tangent at station 5+684? Given grade is +3%. 2. If a 26-degree curve consists of a 14 degree simple curve, what is the angle of the transition curves?arrow_forward1. An equal-tangent crest vertical curve is being designed for a speed of 45 mph. The curve connects grades of 1.3% and -2.4% in the direction of interest. The curve high point is at station 110+30 and has an elevation of 930 ft. What is the station and elevation of the PVC and the PVI? [Answer: PVI station: 110+50.3; PVI elevation: 930.6']arrow_forward
- An equal tangent crest curve connects a +2% initial grade with a -1% final grade, and is designed for 55 mi/h. That station of the PVI is 233+40 with elevation 1205 ft. What is the elevation of the curve at station 234+50?arrow_forwardA -4% grade line meets another line of +3.2% grade at station 11+ 4O. If a 225-ft parabolic curve connects these grade lines, at what station is the lowest point along the curve located? Your answerarrow_forwardA vertical equal-tangent, 1000 ft long, connects an initial grade of -2.5% and a final grade of +2%. The PVC of the curve is located at station 95 + 00 and has an elevation of 850 ft. At which station is the PVI of the curve located? 80 + 00 83 + 75 O 90 + 00 O 95 + 00 O 100 + 00arrow_forward
- 4. An equal tangent (sag) vertical curve connects an initial grade of -3% and a final grade of +1% and is designed for 60 mph. The PVI is at station 250+50 and elevation 732 ft. What is the station and elevation of the lowest point on the curve?arrow_forwardA-4% grade line meets another line of +3.2% grade at station 11+ 40. If a 225-ft parabolic curve connects these grade lines, at what station is the lowest point along the curve located?arrow_forwardA 400-ft equal-tangent sag vertical curve has its PVC at station 78+00 and elevation 800 ft. The initial grade is -4% and the final grade is +2.5%. Determine the station of the lowest point of the curve.arrow_forward
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