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Practice ProblemATTEMPT
Calculate the molecular or formula mass of each of the following compounds: (a) chloride
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- Which of the following is the correct formula for manganese (v) nitrate Mn3(NO3)2 Mn4(NO3)4 Mn(NO3)2 Mn3(NO3)5 Mn(NO3)5 Answer not listedarrow_forwardShort answer: Calculate the number of oxygen atoms in 15.0 g of calcium nitrate, Ca(NO3)2-arrow_forwardA compound is 57.14% C, 6.16% H, 9.52% N, and 27.18% O. The molar mass is 588.6 g/mol. What is the molecular formula? Group of answer choices C14H18N5O2 C28H36N4O10 C7H9NO3 C14H18N2O5 C7H9NO5arrow_forward
- Direction: Find the molecular formula of the followingcompounds 7. A compound contains 62.0% C, 10.4% H, and27.5% O. Determine the empirical formula forthis compound. After analysis, it was found thatthe compound’s molar mass is 58.1g. What isthe compound’s molecular formula?8. Glucose, one of the main sources of energyused by living organisms, has a molecular massof 180.2g. Chemical analysis shows that glucoseis 40.0% C, 6.71% H and 53.3% O. Determineglucose’s molecular formula.9. A class of compounds called sodiummetaphosphates were used as additives todetergents to improve cleaning ability. One ofthem has a molecular mass of 612g. Analysisshows the composition to be 22.5% Na, 30.4% P,and 47.1% O. Determine the molecular formulaof this compound.10. Find the molecular formula for a compound thathas a molecular mass of 92g.mole. The %composition of the compound is 30.4% N, and69.6% O.arrow_forwardCaffeine has an elemental analysis of 49.48% carbon, 5.190% hydrogen, 16.47% oxygen and 28.85% nitrogen. It has a molar mass of 194.19 g/mol. What is the molecular formula of caffeine? Group of answer choices C4H5ON2 C6H6O2N C10H14O2N2 C8H10O2N4arrow_forwardCalculate the number of moles of carbon atoms present in eachof the followingsamples.l type="a">1.271 g of ethanol,i>3.982 g of 1 ,4-dichlorobenzene,i>0.4438 g of carbon suboxide,i>2.9 10 g of methylene chloride,check_circle Expert SolutionInterpretation Introduction(a)Interpretation:Find launchC2H5OHC6H4Cl2C3O2CH2Cl2arrow_forward
- Which of the following is not an empirical formula C2H6 C2H CH3 CHarrow_forwardWhich one of the following is definitely NOT an empirical formula C₄H₁₂N₂O C₁₂H₁₆O₃ C₆H₁₂O₃ C₁₂H₂₂O₁₁ C₃H₈O₂arrow_forwardPT#15 2.) Directions: Calculate the empirical and molecular formula of the given. Question: Determine the molecular formula of the compound with an empirical formula of CH and a formula mass of 78.110 u.arrow_forward
- Problem Ammonium carbonate is a white solid that decomposes with warming. It has many uses, for example, as a component in baking powder, fire extinguishers, and smelling salts.(a) How many formula units are in 41.6 g of ammonium carbonate?(b) How many O atoms are in this sample?Plan (a) We know the mass of compound (41.6 g) and need to find the number of formula units. we need the formula to find the amount (mol) and then multiply by Avogadro’s number to find the number of formula units. [The road map steps are for part (a).] (b) To find the number of O atoms, we multiply the number of formula units by the number of O atoms in one formula unit.arrow_forwardWhich one of the following molecular formulas is also an empirical formula? a. C6H6O2 b. C2H6SO c. H2O2 d. H2P4O6 e. C6H6arrow_forwardUse percent composition and molar mass to determine molecular formula. Close Problem Question Content Area Analysis of a compound of chlorine, oxygen and fluorine showed that it is 34.60% Cl and 46.85% O, with F accounting for the remainder. In a separate experiment, the molar mass of the compound was found to be 102.5 g/mol. Determine the molecular formula of the compound. Enter the elementsin the order Cl, O, F.arrow_forward
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