Explanation Given info: The radius of a cylinder is 3 mm and the electrical field strength is 1 × 10 8 t 2 V / m . The formula to calculate of electric flux through the cylinder is, ϕ e = E → ⋅ A → = E A cos θ • E is the electric field strength. • A is the surface area of cylinder. • θ is the angle between electric field and area vector. The electric field and the area vector are parallel to each other so the angle is zero. The formula to calculate area of cylinder is, A = π R 2 • R is the radius of cylinder. Substitute 0 ° for θ and π R 2 for A in above equation to find ϕ e To determine (b) To draw: The diagram showing the magnetic flux field lines inside and outside the cylinder. To determine (c) The expression for the magnetic field strength at a distance r < R from the centre and value of the magnetic field. To determine (d) The expression for the magnetic field strength at a distance r > R from the centre and value of the magnetic field.

4th Edition

ISBN: 9781323759967

Author: Knight

Publisher: Pearson Custom Publishing

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Question

Chapter 31, Problem 39EAP

To determine

(a)

The expression for the electric flux through the entire cylinder.

To determine

(b)

To draw: The diagram showing the magnetic flux field lines inside and outside the cylinder.

To determine

(c)

The expression for the magnetic field strength at a distance r<R from the centre and value of the magnetic field.

To determine

(d)

The expression for the magnetic field strength at a distance r>R from the centre and value of the magnetic field.

Expert Solution & Answer

Chapter 31 Solutions

PHYSICS F/SCIEN.+ENGIN.BUNDLE >CI<

Ch. 31 - Prob. 1CQ Ch. 31 - Sharon drives her rocket through the magnetic...Ch. 31 - If you curl the fingers of your right hand as...Ch. 31 - What is the current through surface S in FIGURE...Ch. 31 - Is the electric field strength in FIGURE Q31.5...Ch. 31 - Do the situations in FIGURE Q31.6 represent...Ch. 31 - In what directions are the electromagnetic waves...Ch. 31 - The intensity of an electromagnetic wave is 10W/m2...Ch. 31 - Prob. 9CQ Ch. 31 - Prob. 10CQ

Ch. 31 - Prob. 1EAP Ch. 31 - 2. A rocket cruises past a laboratory at in the ...Ch. 31 - Prob. 3EAP Ch. 31 - Prob. 4EAP Ch. 31 - Prob. 5EAP Ch. 31 - Prob. 6EAP Ch. 31 - Prob. 7EAP Ch. 31 - Prob. 8EAP Ch. 31 - Prob. 9EAP Ch. 31 - Prob. 10EAP Ch. 31 - Prob. 11EAP Ch. 31 - Prob. 12EAP Ch. 31 - Prob. 13EAP Ch. 31 - Prob. 14EAP Ch. 31 - Prob. 15EAP Ch. 31 - Prob. 16EAP Ch. 31 - Prob. 17EAP Ch. 31 - Prob. 18EAP Ch. 31 - Prob. 19EAP Ch. 31 - Prob. 20EAP Ch. 31 - Prob. 21EAP Ch. 31 - Prob. 22EAP Ch. 31 - Prob. 23EAP Ch. 31 - Prob. 24EAP Ch. 31 - Prob. 25EAP Ch. 31 - Prob. 26EAP Ch. 31 - Prob. 27EAP Ch. 31 - Prob. 28EAP Ch. 31 - Prob. 29EAP Ch. 31 - Prob. 30EAP Ch. 31 - Prob. 31EAP Ch. 31 - An electron travels with <m:math...Ch. 31 - Prob. 33EAP Ch. 31 - Prob. 34EAP Ch. 31 - Prob. 35EAP Ch. 31 - Prob. 36EAP Ch. 31 - Prob. 37EAP Ch. 31 - Prob. 38EAP Ch. 31 - Prob. 39EAP Ch. 31 - Prob. 40EAP Ch. 31 - Prob. 41EAP Ch. 31 - Prob. 42EAP Ch. 31 - Prob. 43EAP Ch. 31 - Prob. 44EAP Ch. 31 - Prob. 45EAP Ch. 31 - The electric field of a 450MHz radio wave has a...Ch. 31 - Prob. 47EAP Ch. 31 - Prob. 48EAP Ch. 31 - Prob. 49EAP Ch. 31 - A LASIK vision-correction system uses a laser that...Ch. 31 - Prob. 51EAP Ch. 31 - Prob. 52EAP Ch. 31 - Prob. 53EAP Ch. 31 - Prob. 54EAP Ch. 31 - Prob. 55EAP Ch. 31 - Prob. 56EAP Ch. 31 - Prob. 57EAP Ch. 31 - Prob. 58EAP Ch. 31 - Prob. 59EAP Ch. 31 - Prob. 60EAP Ch. 31 - An electron travels with through a point in space...Ch. 31 - Prob. 62EAP Ch. 31 - Prob. 63EAP Ch. 31 - Prob. 64EAP

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