Bundle: Physics for Scientists and Engineers with Modern Physics, Loose-leaf Version, 9th + WebAssign Printed Access Card, Multi-Term
9th Edition
ISBN: 9781305932302
Author: Raymond A. Serway, John W. Jewett
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Videos
Question
Chapter 31, Problem 79CP
To determine
The currents in each resistors.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
A closed curve encircles several conductors. The line integral PB.dL around this curve
is 3,83x104 T.m
(a) What is the net current in the conductors?
(b) If you were to integrate around the curve in the opposite direction, what would be
the value of the line integral?
Select one:
lenci=D
305 A, 0.0 T.m
lencl = 502 A, -3.83 x 10 4T.m
lenci = 502 A, -7.66 x 104 T.m
lencl = 600 A, -7.66 x 104T.m
lencl = 305 A, -3.83 x 10 4 T.m
lencl =
502 A, 0.0 T.m
%3D
A2.10 cm x 2.10 cm square loop of wire with
resistance 1.00×10-2 has one edge parallel to a
long straight wire. The near edge of the loop is 1.10
cm from the wire. The current in the wire is
increasing at the rate of 120 A/s.
7.
a
C
R₂
Given E=12V, R₁-1002, R₂ = 1502 and C=1uF.
a) The switch S has been on position a for a long period of time. Find the charge of the
capacitor.
b) Find the current through the ammeter 9.50 µs after S is thrown from position a to position
b.
c) After S is thrown from a to b, at what time, in us, does the charge on C become equal to
2.00 uC
Chapter 31 Solutions
Bundle: Physics for Scientists and Engineers with Modern Physics, Loose-leaf Version, 9th + WebAssign Printed Access Card, Multi-Term
Ch. 31.1 - A circular loop of wire is held in a uniform...Ch. 31.2 - QUICK QUIZ 30.2 In Figure 30.8a, a given applied...Ch. 31.3 - Figure 30.12 (Quick Quiz 30.3) QUICK QUIZ 30.3...Ch. 31.5 - Prob. 31.4QQCh. 31.6 - Prob. 31.5QQCh. 31 - Prob. 1OQCh. 31 - Prob. 2OQCh. 31 - Prob. 3OQCh. 31 - Prob. 4OQCh. 31 - Prob. 5OQ
Ch. 31 - Prob. 6OQCh. 31 - Prob. 7OQCh. 31 - Prob. 8OQCh. 31 - Prob. 9OQCh. 31 - Prob. 10OQCh. 31 - Prob. 11OQCh. 31 - Prob. 1CQCh. 31 - Prob. 2CQCh. 31 - Prob. 3CQCh. 31 - Prob. 4CQCh. 31 - Prob. 5CQCh. 31 - Prob. 6CQCh. 31 - Prob. 7CQCh. 31 - Prob. 8CQCh. 31 - Prob. 9CQCh. 31 - Prob. 10CQCh. 31 - Prob. 1PCh. 31 - Prob. 2PCh. 31 - Prob. 3PCh. 31 - Prob. 4PCh. 31 - Prob. 5PCh. 31 - Prob. 6PCh. 31 - Prob. 7PCh. 31 - Prob. 8PCh. 31 - Prob. 9PCh. 31 - Scientific work is currently under way to...Ch. 31 - Prob. 11PCh. 31 - Prob. 12PCh. 31 - Prob. 13PCh. 31 - Prob. 14PCh. 31 - Prob. 15PCh. 31 - Prob. 16PCh. 31 - A coil formed by wrapping 50 turns of wire in the...Ch. 31 - Prob. 18PCh. 31 - Prob. 19PCh. 31 - Prob. 20PCh. 31 - Prob. 21PCh. 31 - Prob. 22PCh. 31 - Prob. 23PCh. 31 - A small airplane with a wingspan of 14.0 m is...Ch. 31 - A 2.00-m length of wire is held in an eastwest...Ch. 31 - Prob. 26PCh. 31 - Prob. 27PCh. 31 - Prob. 28PCh. 31 - Prob. 29PCh. 31 - Prob. 30PCh. 31 - Prob. 31PCh. 31 - Prob. 32PCh. 31 - Prob. 33PCh. 31 - Prob. 34PCh. 31 - Prob. 35PCh. 31 - Prob. 36PCh. 31 - Prob. 37PCh. 31 - Prob. 38PCh. 31 - Prob. 39PCh. 31 - Prob. 40PCh. 31 - Prob. 41PCh. 31 - Prob. 42PCh. 31 - Prob. 43PCh. 31 - Prob. 44PCh. 31 - Prob. 45PCh. 31 - Prob. 46PCh. 31 - Prob. 47PCh. 31 - Prob. 48PCh. 31 - The rotating loop in an AC generator is a square...Ch. 31 - Prob. 50PCh. 31 - Prob. 51APCh. 31 - Prob. 52APCh. 31 - Prob. 53APCh. 31 - Prob. 54APCh. 31 - Prob. 55APCh. 31 - Prob. 56APCh. 31 - Prob. 57APCh. 31 - Prob. 58APCh. 31 - Prob. 59APCh. 31 - Prob. 60APCh. 31 - Prob. 61APCh. 31 - Prob. 62APCh. 31 - Prob. 63APCh. 31 - Prob. 64APCh. 31 - Prob. 65APCh. 31 - Prob. 66APCh. 31 - Prob. 67APCh. 31 - A conducting rod moves with a constant velocity in...Ch. 31 - Prob. 69APCh. 31 - Prob. 70APCh. 31 - Prob. 71APCh. 31 - Prob. 72APCh. 31 - Prob. 73APCh. 31 - Prob. 74APCh. 31 - Prob. 75APCh. 31 - Prob. 76APCh. 31 - Prob. 77APCh. 31 - Prob. 78APCh. 31 - Prob. 79CPCh. 31 - Prob. 80CPCh. 31 - Prob. 81CPCh. 31 - Prob. 82CPCh. 31 - Prob. 83CP
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- 30. A short wire runs along an x axis from x = a to x = -a (Figure P30.30). At t = 0, there is a small sphere carry- ing charge +9o at x = a and a small sphere carrying charge -9o at x = -a. As the spheres discharge and a current is established in the wire, show that, for t>0, the generalized form of Ampère's law (Eq. 30.13) and the Biot-Savart law (Eq. 28.12) give the same result for the magnitude of the mag- netic field a distance b up the y axis. (Hint: Obtain the elec- tric flux through a circular disk in the yz plane, centered at the origin. Because the electric field is not constant over the surface of the disk, you must divide the disk into a nested set of rings of various radii and integrate. A representative ring should have radius r and radial extent dr.) •.. Figure P30.30 b -90arrow_forwarda.Find H in rectangular components at P(3,4,2) If there is a current filament on the z axis carrying 5 mA in the az direction. b. Repeat if the filament is located at x = -1, y = 2. (c) c. Find H if both filaments are present.arrow_forwarddz wire 1- Y 2wire 2 * Pi K.- ļ, - K.- lz- A current carrying wire(wire-1) with i1 = 15 Amperes is placed at the origin on the Y-Z plane. Another current carrying wire(wire-2) with iz = 14 Amperes is placed l = axis. The point P2 is l1 wire-1. Pi (0, 10, –15), P2 (0, 10, 0) and the point P3 (0, 10, 5) are on the same line. The direction of the current is given in the figure. = 12 m distance apart on the Y- = 10 m from the Step 1: Consider a wire-1 only. a) Calculate magnetic field at Pıarrow_forward
- 7 A Z S 30 H command 9. An electric power station that operates at 35 kV and uses a 10:1 step-up ideal transformer is producing 34 MW (Mega- Watt) of power that is to be sent to a big city which is located 300 km away with only 2.5% loss. Each of the two wires are made of copper (resistivity = 1.72 x 10-22.m). What is the diameter of the wires? X 0.85 cm x E 30 R 5 T 6 DEL LL B MacBook Air H N 8 J D 1 M ( 9 K MOSISO A P - command ? optionarrow_forwardThe capacitor in the circuit shown below is initially uncharged. The switch is closed at t = 0 s. ΔVbattery = 30 V, C = 3.0 F, and R = 2.0 Ω. At sometime after the switch is closed, the current in the circuit is measured to be 6.1 A. What is the charge on the capacitor at this time, in Coulomb?arrow_forwardA portion of a long, cylindrical coaxial cable is shown in the figure below. An electrical current I = 3.0 amps flows down the center conductor, and this same current is returned in the outer conductor. Assume the current is distributed uniformly over the cross sections of the two parts of the cable. The values of the radii in the figure are r1 = 1.5 mm, r2 = 4.0 mm, and r3 = 7.0 mm. Using Ampere’s Law, find the magnitude of the magnetic field at the following distances from the center of the inner wire: a. 1.0 mm. b. 3.0 mm. c. 5.5 mm. d. 9.0 mm.arrow_forward
- 7. A sheet of copper foil 1 mm thick, 5 cm wide and 1.75 m long is connected to a voltage source as shown. There is a magnetic field B = 2.5 T into the page. Assume copper has conductivity σ = 5.96 x 107 mho/m and a charge carrier density n = 1028 electrons/m³. a) What is the current density J in the foil? b) What is the Hall voltage as measured by the voltmeter? c) Which point is at a higher potential, a or b? Voltmeter 20 Varrow_forwardQ4: Show detailed work and pay attention to the units. There are two different ways to calculate the potential difference across the bar, using the motional EMF expression or Faraday's Law. Show that both methods give the same answer. Use the right hand rule to figure out which end of the bar (A or B) will be at a higher potential due to the motion of the conductor in the field.arrow_forwardA coil of radius 3 cm has 60 turns of Cu wire of diameter 4 mm. The plane of the coil is perpendicular to a field that changes at the rate of 0.2 T/s. What is the power loss in the coil? The resistivity of Cu is 1.7 × 10-8 S. m. mWarrow_forward
- Problem 1: Two long thin parallel wires are 0.1 m apart and each wire carries a current of 12 A. The current for the wire on the left is into the page and the current for the wire on the right is out of the page. What is B at point P, 0.08 m from one wire and 0.06 m from the other wire? Hint: Point P is on the corner of the right triangle with the right angle. Answer: B = −(1.4 × 10−5 T)î − (4.8 × 10-5 T)ĵ. 0.08 m - X 0.1 m- I -0.06 marrow_forwardA square, 44.0-turn coil that is 13.0 cm on a side with a resistance of 0.900 2 is placed between the poles of a large electromagnet. The electromagnet produces a constant, uniform magnetic field of 0.400 T directed into the screen. As suggested by the figure, the field drops sharply to zero at the edges of the magnet. The coil moves to the right at a constant velocity of 3.10 cm/s. N-turn coil B into the screen Varrow_forwardQI. A capacitor consists of two circular plates of radius a separated by a distance d (assume d a. (A) Use Gauss' Law to find the electric field between the plates as a function of time t, in terms of q(1), a, ɛ, and z. The vertical direction is the k direction. (B)Now take an imaginary flat disc of radius rarrow_forwardarrow_back_iosSEE MORE QUESTIONSarrow_forward_ios
Recommended textbooks for you
College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning
University Physics (14th Edition)PhysicsISBN:9780133969290Author:Hugh D. Young, Roger A. FreedmanPublisher:PEARSON
Introduction To Quantum MechanicsPhysicsISBN:9781107189638Author:Griffiths, David J., Schroeter, Darrell F.Publisher:Cambridge University Press
Physics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
Lecture- Tutorials for Introductory AstronomyPhysicsISBN:9780321820464Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina BrissendenPublisher:Addison-Wesley
College Physics: A Strategic Approach (4th Editio...PhysicsISBN:9780134609034Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart FieldPublisher:PEARSON
College Physics
Physics
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
University Physics (14th Edition)
Physics
ISBN:9780133969290
Author:Hugh D. Young, Roger A. Freedman
Publisher:PEARSON
Introduction To Quantum Mechanics
Physics
ISBN:9781107189638
Author:Griffiths, David J., Schroeter, Darrell F.
Publisher:Cambridge University Press
Physics for Scientists and Engineers
Physics
ISBN:9781337553278
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:9780321820464
Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:Addison-Wesley
College Physics: A Strategic Approach (4th Editio...
Physics
ISBN:9780134609034
Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:PEARSON
What is Electromagnetic Induction? | Faraday's Laws and Lenz Law | iKen | iKen Edu | iKen App; Author: Iken Edu;https://www.youtube.com/watch?v=3HyORmBip-w;License: Standard YouTube License, CC-BY