Interpretation:
The determination of chloride in isotope dilution experiment is done by the mixing of 5.0 mg of sodium chloride with specific activity of
Concept introduction:
The decay constant is determined by using the formula of half time which is given as-
Also, the mass of chloride ion in sample is calculated by following formula-
Where,
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Principles of Instrumental Analysis
- The streptomycin in 500 g of a broth was determined by addition of 1.25 mg of the pure antibiotic containing 14C. The specific activity of this preparation was found to be 240 cpm/mg for a 30-min count. From the mixture, 0.112 mg of purified streptomycin was isolated which produced 675 counts in 60.0 min. Calculate the concentration in parts per million streptomycin in the sample.arrow_forwardThe rate constant for the radioactive decay of 14C is 1.21104 year-1. The products of the decay are nitrogen atoms and electrons (beta particles): C614N714+e rate =k[C614] What is the instantaneous rate of production of N atoms in a sample with a carbon-14 content of 6.5109M?arrow_forwardFluorine-18 is a radioactive isotope that decays by positron emission to form oxygen-18 with a half-life of 109.7 min. (A positron is a particle with the mass of an electron and a single unit of positive charge; the equation is F918O188+e+10 Physicians use 18F to study the brain by injecting a quantity of ?uoro-substituted glucose into the blood of a patient. The glucose accumulates in the regions where the brain is active and needs nourishment. (a) What is the rate constant for [lie decomposition of ?uorine-18? (b) If a sample of glucose containing radioactive fluorine-18 is injected into the blood, what percent of the radioactivity will remain after 5.59 h? (c) How long does it take for 99.99% of the 18F to decay?arrow_forward
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- A supply of fluorodeoxyglucose (FDG) arrives at a positron emission tomography clinic at 8 am. At 2 pm, when you arrive at the clinic to get a PET scan, the activity level of the FDG has dropped significantly because of the 110 minute half-life of the radioactive fluorine. Considering equal masses of FDG at 8 am and 2 pm, by what factor has the activity level been reduced by 2 pm? I really appreciate the help on this question! Thank youarrow_forwardPotassium-Argon dating is a common method of determining the age of rocks based on the time they were last liquified, and thus we can determine the age of a surface by examining the ratio of the parent K40 to the decay product Ar40. This works because argon is a gas, which will be free to bubble out of liquified rock whenever the rock is hot enough to no longer be in it's solid state (think of magma covering a surface). This means that just after the rock solidifies, there should be effectively no Ar40 remaining and that any Ar40 that we do find in the rock at the time of the collection of the sample must be due to radioactive decay. With all of this in mind, if we find that a rock sample has 31 Ar40 atoms for every 1 K40 atom, and the half-life of K40 is 1.3 billion years, how much time has passed in years since that rock was geologically active (aka it was last liquified)? When typing your answer, please do not use commas or scientific notation because of how Blackboard interprets…arrow_forwardPlease helparrow_forward
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